I don't know about Newtonian fractals, I'm still learning. I updated the description so you can see what is happening at each transition. I hope it makes sense.
@@FalkBay any f, it would typically have solutions (regions of convergence are typically towards the solutions, and typically a polynomial. The most famous Newtonian fractal is for f(z)=z³-1, but this seems very similar to some others
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fractaldale juliadale
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This feels oddly Newtonian, what are the parameters?
I don't know about Newtonian fractals, I'm still learning. I updated the description so you can see what is happening at each transition. I hope it makes sense.
@@FalkBay the Newtonian fractal is z(n+1)=z(n)-f(z(n))/f'(z(n)), or to make it easier to read, in code-isher notation it would be z=z-f(z)/f'(z)
@@yoavmal Does this hold for any differentiable function? or do f and f' need to be something specific?
@@FalkBay any f, it would typically have solutions (regions of convergence are typically towards the solutions, and typically a polynomial. The most famous Newtonian fractal is for f(z)=z³-1, but this seems very similar to some others
Ok thank you. Maybe I'll try it. I currently have other formulas in my head.