The main reason u are not getting support even after such good content is that your channel name is salogic, but if someone searches sa logic, then your channel does not appear, so plz get a better name for your channel related to maths..For example Maths GO!
Why do you assume that m=sqrt(x)/2 and n=sqrt(y)/2 are both integers?
To make it easy to solve. ❤
As you see you don't SOLVE, you GUESS. It's not math...
V2^×-V2^y=60
=2^6=64
=64-4 =60 y=4 2^2
V2^6^1/2 = 2^1/12
V2^2^1/2 = 2^1/4
X= 12^2 Y=4^2
X=144 Y=16
Very nice! I really appreciate that ❤
The main reason u are not getting support even after such good content is that your channel name is salogic, but if someone searches sa logic, then your channel does not appear, so plz get a better name for your channel related to maths..For example Maths GO!
X=144, y =16
Very nice! I really appreciate that ❤
X =256
Y=16
Yes, you are right! ❤
(V2)^(V144)-(V2)^(V16)=(V2)^(12)-(V2)^(4) , 2^6-2^2=64-4 , --> 60 , 2^m-2^n=64-4 , --> 60 , 2^6-2^2=64-4 , --> 60 ,
2=V2^2 , 2^6=(V2^2)^6 , 2^6=(V2)^(2*6) , 2^6=(V2)^12 , Vy=12 , 12^2=144 , y=144 , With this method, x=16,
Very nice! I really appreciate that ❤