Turbulent Energy Cascade Part 1/4

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  • Опубликовано: 9 ноя 2024
  • Scales of turbulent motion, dissipation on the smallest scales

Комментарии • 18

  • @neelmehta100
    @neelmehta100 4 года назад +1

    Thank you! Exactly what I needed. I also found the book for this work:
    Pope, S.B., 2000, "Turbulent Flows." Chapter 6.
    But it helped me to see you working from it.

  • @ningtian7255
    @ningtian7255 9 лет назад +1

    great introduction! Thank you so much for your hard work, Prof. Jorg Schluter

  • @eng.maimonahkhader3311
    @eng.maimonahkhader3311 3 года назад

    Thank you

  • @makavelilcf
    @makavelilcf 6 лет назад

    Great course of lectures

  • @zhongxuanhou2727
    @zhongxuanhou2727 5 лет назад

    Very good lecture!

  • @juliavolkle6815
    @juliavolkle6815 7 лет назад

    Thanks for the good explanation!

  • @dowellchan3890
    @dowellchan3890 5 лет назад

    Thanks for your lecture.!!!!!!!!

  • @nikan4now
    @nikan4now 9 лет назад +2

    Thanks for the great video series. Question here: say the eddy is translating with velocity u in the x direction...which is the characteristic velocity of the eddy and how do we measure it....does the probe have to move with the eddy at velocity u and then measure the rms of the three fluctuating components over a specific period of time?

  • @bakrybsata3114
    @bakrybsata3114 5 лет назад

    Amazing :) :) :)
    Thank you sooooo much.

  • @joaohackerott2378
    @joaohackerott2378 9 лет назад

    very good explanation

  • @FirehawkVFX
    @FirehawkVFX 6 лет назад

    Awesome, thankyou!

  • @دروساونلاين-س9ك
    @دروساونلاين-س9ك 8 лет назад

    Good evening sir
    How are you -I I hope you are good ;
    I have a question please:
    I want you to tell me how many method to model turbulent flow and it is the best way?
    What is the problem of closure
    And there's how do they model?
    I hope you reply to my questions
    thank you

  • @yohanshin152
    @yohanshin152 6 лет назад

    Thank you so much for providing gorgeous lecture about turbulent. By the way, how can I derive dissipation rate equation (epsilon = 2 nu S_ij S_ij )? What I understood is that, dissipation rate is the rate of turbulent kinetic energy transformation to thermal energy. So is it right that dissipation is due to shear stress? Then why is it square of S_ij?

    • @rishabhsingh1459
      @rishabhsingh1459 4 года назад

      That term can be best understand when you derive mean kinetic energy equation. Follow kundu and cohen for more

    • @apoorvmishra6992
      @apoorvmishra6992 2 года назад

      @@rishabhsingh1459 what's kundu and cohen

    • @rishabhsingh1459
      @rishabhsingh1459 2 года назад

      @@apoorvmishra6992 they have authored book - 'Fluid Mechanics'.

    • @apoorvmishra6992
      @apoorvmishra6992 2 года назад

      @@rishabhsingh1459 can you share the link?