CSAT 2023 | Answer Key | UPSC CSE | Detailed Analysis in Tamil
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- Опубликовано: 5 окт 2024
- Asper UPSC Key
Question no.49 Answer option (a)
Question no.67 answer (d)
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No wonder if some of these questions may come in next group 1!!!!!!!
Very good explanation.
Thank you very much sir
Excellent in your explanations sir. Very useful for my preparations. Thank you sir.
Very Excellent Teacher but going Fast,
Your Hard work is Amazing 👏
For the 49th question ..
One can do the actual calculation that is 10000000000÷7
One can observe that the remainder cycle repeats every 6th time ... Means.. finding the remainder of the rest 4th cycle gives the actual remainder that is 4 which falls on Thursday
Thank you so much sir
It's very useful thank u soo much sir
Wonderful explanation sir....
Sir 14 question p=7 and c=10 how its satisfies the first condition can u explain me
I need the UPSC questions papers sir...
Sir, 10th question if we take 108/9=12& diff is 7 and 7 is one of the option
Sir screen theliva show agala sir
Thanks ji
Class is super sir, kindly share the fees structure.when will you start new csat batch ?
🎉❤
29 question.ans.946?
Superb..
English medium available
How sir 945÷4 is 1 ... Sir can you please explain it how?
That's remainder theorem dude
945 ÷ 4 remainder 1 eppid varum
Bro 4la ÷ panna epudi kandu pidiganum na namagu kuduthuruga number la last 2 digit 4÷ panna pothum 945 kuduthuruguranga ipo 45÷4 panunga remainder 1 kidigum so remainder 1 than varum