I absolutely admire your math presentation, style and depth of awareness of the subject!!! You bring a smile to my face, and gratitude to my heart! Thank you for being such a great teacher!!! God Bless You!!!
I am thankful to you for your simplified explanations. Teaching with patience and step by step. Also, it seems that there is not much ventilation in the room, though you are so focused. SALUTE!! take care and keep the good work going.
Your explanation is really wow sir pls upload remaining part of this topic and more topics sir tq so much sir finally I understand wt's the time distance relation and how to slove
40:60 = 2:3 =velocity ratio 3:2= time ratio So,here 1 unit time =1.5hr Hence distance= 3×1.5×40=180km or 2×1.5×60=180km 2nd one Velocity ratio 4:8 = 1:2 Time ratio 2:1 1 unit time = 3hr So, distance= 2×3×4= 24km
Sir, here also there is another short cut. Combined speed is 100 km/h. So, in 1 and half hour both covered 150 km distance. The ratio of their speeds is 2:3. The difference of ratio is 1. This 1 part out of 5 part must be the distance travelled less by 40 km/h vehicle or travelled more by 60km/h vehicle. So, 150 multiplied by 1/5 gives 30. So, the distance must be 150+30= 180 kms or 150-30=120 kms. We have to eliminate one of them. 60 km/h vehicle takes 3 hours to travel 180 kms and 40km/h vehicles takes 4 1/2 hours to travel 180 kms. The difference of 1 1/2 hrs between the two established here. In second case, 60km/h takes 2 hours and 40km/h vehicles takes 3 hours to cover 120 kms. In this case, the difference is just 1 hour which does not satisfy the condition ie 1 1/2 hour. So, the correct option is 180 kms.
Shahrukh starts from Barabanki to Fatehpur , 1 hour after Ajay starts. Shahrukh meets Kajol 1.5 hours after Shahrukh starts. If the speed of Shahrukh is at least 20km/h faster than the speed of Kajol. What is the minimum speed of Shahrukh to overtake Ajay, before he meets Kajol? Pls give me solution of this question sir
How to solve this using the above trick,amit goes to his office by car at the speed of 80km/hr and reaches 15 min earlier.if he goes at the speed of 60 km/hr , he reaches 15 min late. what will be the speed of the car to reach on time...
Finally someone who explain briefly in English. Thank you so much Sir!!
I absolutely admire your math presentation, style and depth of awareness of the subject!!! You bring a smile to my face, and gratitude to my heart! Thank you for being such a great teacher!!! God Bless You!!!
Thank you so much for the motivation
I am thankful to you for your simplified explanations. Teaching with patience and step by step. Also, it seems that there is not much ventilation in the room, though you are so focused. SALUTE!! take care and keep the good work going.
u can gift him a AC...
as a fee
sir really makes me Mathematics is too easy....God will bless you....Thank you so much sir...LOVELY
How time difference is 1 and half hr? If Difference is minus then 1 hr - 1/2 hr should be 1/2hr.?? Please help?
Excellent mate, Just remind my old days of mathmatics tricks. I used to be a teacher 20 years ago :)
thanks sir for uploading those videos...really it's helps us a lot..
Best explanation in the shortest time. Really saved my time
Remembering the formula is more easier than solving in traditional manner
Your tricks are helpful Sir... Thank you
Brilliant simple things are effective
Awesome sir 🙏 thankyou so much
This is amazing !!
Your explanation is really wow sir pls upload remaining part of this topic and more topics sir tq so much sir finally I understand wt's the time distance relation and how to slove
Thank you very much sir
40:60 = 2:3 =velocity ratio
3:2= time ratio
So,here 1 unit time =1.5hr
Hence distance= 3×1.5×40=180km or 2×1.5×60=180km
2nd one
Velocity ratio 4:8 = 1:2
Time ratio 2:1
1 unit time = 3hr
So, distance= 2×3×4= 24km
Superb. Do share the links with your WhatsApp groups and contacts
Thanks a lot bro.....
How this 1 unit of time become 3... Please explain
Thank you sir.very well explained. Your videos are great.
Thanks. Do share the links with your whatsapp groups and contacts
Mr Agarwal I have understood how it is done but I did not understand the concept behind the problem.Can you please teach us using the long method.
I know this trick. Please do more difficult problems in an easy way with shortcuts.
Time difference should be 0.5 right?
awesome... nice way to find this types of sums
By time difference. You mean sum?
Really what a wonder sir.superb sir💐
sir your super sir , thanks a lot , it was great video
Sir please give some more questions for practise
Sir
Please upload more videos on
remaining concepts of Aptitude & Reasoning
Sir, thank you soo much....I was really clearly understood....
Nice.... Nice.... Great ....
I’m not able to understand the difference of 1/2 and 1; in other to get 1,5? Please help me
Yes bro. I am also not understand how 1 hour minus 1/2 make 1.5
Thak youu sir ❤️
really very easy trick to solve in seconds thank you sir
Thanks. For getting the compiled PDFs of short tricks....send a message on my personal WhatsApp number 9896369963.
only if we could raise enough money to buy good air--condition system for Suresh Sir - love you man
Hahaha....no one bothers to contribute....criticism is plenty.
Sir I will contribute
@@sureshaggarwal CAN I SPONSOR?
Very helpful trick👍
Very much amazing...its really so tricky 🙏 sir
Thanku verybmuch
Sir, here also there is another short cut. Combined speed is 100 km/h. So, in 1 and half hour both covered 150 km distance. The ratio of their speeds is 2:3. The difference of ratio is 1. This 1 part out of 5 part must be the distance travelled less by 40 km/h vehicle or travelled more by 60km/h vehicle. So, 150 multiplied by 1/5 gives 30. So, the distance must be 150+30= 180 kms or 150-30=120 kms. We have to eliminate one of them. 60 km/h vehicle takes 3 hours to travel 180 kms and 40km/h vehicles takes 4 1/2 hours to travel 180 kms. The difference of 1 1/2 hrs between the two established here. In second case, 60km/h takes 2 hours and 40km/h vehicles takes 3 hours to cover 120 kms. In this case, the difference is just 1 hour which does not satisfy the condition ie 1 1/2 hour. So, the correct option is 180 kms.
can u explain me this method
Kattai kamaal ,perfect
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One more way if u forget formula
Since distance is constant in both case
4(X+2)=8(x-1)
Find X and substitute back in LHS or rhs
Sir i want notes that contains all models of questions and that was explained by u...plz rply
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Excellent sir
sir can we use in class 10 borad exams????
Only for competitive exams
Sir if he arrive early - early we take it both difference time or sum of the both
Sir can you make videos on infinite series and general n th term of series? Please sir
Thankyou thankyou thankyou very much 💓 💖 sir
How is difference between 2 and 1 is three
thank you so much well explain
Sir how can the difference be 3 between 2h and 1h
Sir how do we calculate if the time taken is in minutes
sir please upload LCM problems
Awesome sir 👌
What can i do if i get fraction as distance
please upload formulas for geomentry which is heplful to ssc exams
Exactly what I wanted🤘
I like ur smile smile sir...
Sir aap england se ho
Thanku sir thanks a lot for this short cut
sir place remaining parts also
Sir please speak loud😀😀🙏🙏👍🏻👍🏻
Sir pls load time distance part 2
Very interesting teach
Your
Short Cuts are Awesome sir
But still some concepts are left,
Please make videos on remaining concepts sir , if Possible
Sir makes a video rs aggarwal class 10
Wow... amazing video... super
Priya saheb rpf ni bharti na related prasna
Sir put alligation and mixture shortcuts
How
Wooooooow so easy
For pdfs of short tricks.....whatsapp 9896369963
Amazing
Sir Namskar thanks
Sir u r telling difference between time but doing addition
Shahrukh starts from Barabanki to Fatehpur , 1 hour after Ajay starts. Shahrukh meets Kajol 1.5 hours after Shahrukh starts. If the speed of Shahrukh is at least 20km/h faster than the speed of Kajol.
What is the minimum speed of Shahrukh to overtake Ajay, before he meets Kajol?
Pls give me solution of this question sir
two trains traveling perpendicular to each other at 36kmph and 48kmph what is the distance between them after 15 seconds . solution
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Nice way to solve the sum
thank you sir
nice tricks
Sir how to find when both the time is given in minutes. Assume 15 mins early and 20 mins late.? then how to calculate?
Just add it 15+20=35mins then 35/60
@@minnelmeeran I’m able to understand the time difference to get 1,5 in first example
Nice sir
Sir time difference 1.5 or 3 kaisa aa that hai
hey its easy add the speed and divide by 2 thats it
If u give a little focus on ur voice to achha hota
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How to solve this using the above trick,amit goes to his office by car at the speed of 80km/hr and reaches 15 min earlier.if he goes at the speed of 60 km/hr , he reaches 15 min late. what will be the speed of the car to reach on time...
Plz sir there is a nice solution to your qn..i hv visited that channel.. sudhirsirjnv
If the speed increase and decrease by same km/hr...then what is the formula
Difference of time 3 kese
Assume 0 as the present time
He reached 2 hrs late which means -2
And then he reached 1 hr earlier it means +1
The difference between -2 and +1 is 3👍
U take wrong time because we have add time not subtract in this method please check
more short cuts
Hii sir
Bahhh
Actually I think time difference is 0.5 not 1.5
Please sir upload more videos on Geometry.
Thanks sir in helping me I got selected 8n jnv 🤩🤩🤩🤩🤩🤩🤩
Sir ssc cgl related questions
+Aravi Agri .....suggest questions on whatsapp.....9896369963.....I will video graph the solutions and put on channel
Ya sir
Say in minutes
Sir Hindi me v padhiye na....
Thank you so much Sir 🙏
Thank you so much Sir
Thanks sir
Nice sir