Trigonometry Top-10 सवाल🔥 एक सवाल पक्का Gagan Pratap Sir
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- Опубликовано: 11 сен 2024
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Trigonometry ke top 10 sawal kaise lage mere bhai😊😊😊 videos ko jyada se jyada share kare , dosto se subscribe bhi karwaye ☺️☺️
Aur kis chapter ke top 10 questions solve karna chahte hai ??? Comments me batao🙂
Bahut hi laa jabab question the guru jii
Algebra ke guru ji
Bhut badhiya solution karwaya sir apne sir please number system ke har ek topic ke bhi top 10 questions Kara do
Mixture allegation ~~ multiplying factor wala
Guruji har chapter k hi kra dijiye concept k sath. Bhot productive h accha revision ho rha hai.
SecA+tan³A.CosecA= SecA(1+tan²A)= Sec³A
▶️tan²A=3+Q²
▶️1+tan²A=4+Q²
▶️Sec²A=4+Q²
▶️SecA= (4+Q²)½
▶️Sec³A= (4+Q²)³/²
Option D ✅
Bahi aapne ye type kaise kiya hai ?
D
Bahut sahi bro
Opt d
Thanks brother 😊
*_"अतीत पर रोने से बेहतर है नए भविष्य का निर्माण कीजिए.,क्योंकि अतीत एक सबक है भविष्य नहीं..😊......!_*
जय हिन्द गुरुदेव,,❤️🔥🇮🇳
Q11 option d (4+q2)3/2
sec +tan3a coseca
1/c + sin3/cos3 *1/sin3
1/c + sin2a/cos3a
On solving = sec3a
And put Value from below
Tan2a +1= 3+Q2 +1
Sec2a = 4+q2
(sec2a)3/2 or sec3a = (4+q2)3/2 ans
Seca+tan^3a.coseca
Seca+sin^3a/cos^3a.coseca
Seca+tan^2a.seca
Seca(1+tan^2a)
Sec^3a
(√1+tan^2a)^3
(4+Q^2)^3/2
11.Ans-D (4+Q^2)3/2
Putting Q=0
Tana=√3
A=60⁰
Now sec60⁰+tan³60.cosec60⁰
=1/2+3√3×2/√3 =8
Satisfying option 4. At Q=0✅✅✅
ANS. (D) (4+Q^2)^3/2 JAI JAI SHIYA RAM SIR JI
Q.11- 42:10 Ans. (D)❤ chlo ab to sir ke ashirbad se CGL nikal jayga
1/c3=sec3
Sec2-1 =tan2
Put in eq and solve it
option d is coreect
(d) (4+Q^2)^3/2
Tan²a= 3+Q².............................. seca+tan³a×coseca= 1/ cos³a = sec³a
1+tan²a = 1+3 + Q²
Sec² = 4 + Q²
Sec = ( 4+Q²)1/2
Sec³a = (4+Q²)3/4
3/4 😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂pagal
Main jb. Kam time m questions ko slove lar leti huu to apnne ap pe gurv hone lagta hhh......because of sir
Value putting se jldi hoga Q=0
tana=√3.
a=60
Seca+(tan)2.coseca=8
And d is the right option
Jai shree Ram sir ji ❤❤❤
D
Put q=0. a=60⁰ ( 2+3root3×2/root 3=8 that is in option D
Let, Q=0,
Then, a=60°
2+3√3•2÷√3
=8
So, option d is correct 💯
😊
Nice class sir ji ...
by the way answer is option D: Thank you.
Like for Gagan sir ❤❤❤❤
Q11.. by value putting
Put Q=0.. so a = 60degree
Thus solving equation by putting 60
We get 8
Only option D makes it 8
Pahle math se dar lagta tha per aab sab se jayada interest hi math me ho Gaya
Batch liya bhai aapne
SecA+ tan ^2A*CosecA=Sec^3A.
tan^2A=3+Q^2.
Sec^2-1=3+Q^2.
Sec^2A=4+Q^2.
SecA=(4+Q^2)^1/2.
Sec^3A= (4+Q^2)^3/2.
Correct answer is :-. D.
Thank you so much sir ji 🙏❤️
Kon kon sir ko dil se pasand karta hai ❤❤
Tere andar bhi kaun kaun wala bhut ghus gaya k
Tumera bhi fefda dhadakta hh kya..❤❤
hmare pass dil hi nahi h😂😂tut chuka h😂😂
Hum toh gurde se pasand karte hain dil toh kisi or ko de diya hai n isliye
Option D is the Right Answer ❤️❤️🙏🙏
Sir Mera Selection Hone ke baad Main apne Salary ka 25 ℅ Aapko Donate karunga / Yearly❤
Achcha joke tha bhai
Brother selection only maths se nhi hoga
Put Q=0 then a=60°
After solution option (d) satisfy the condition. So option (d) is correct
I scored 10/10 😊😊
All questions are repeated in practice session on RUclips by gagan sir🤗🤗
Yes, correct
@@MathsConceptKing_ Thank you sir I request you please start something new 🆕.
Sir Homework question's answer-------option (D) is right answer (4+Q^2)^3/2
Right answer
@@MathsConceptKing_ 2024 me rank nikalkar aapse Milne aaunga sir 🙏🥰
एक पुल की मेहराब वृत्त की चाप के आकार की है। यदि पुल की चौड़ाई 40 m है और इसके मध्य भाग की ऊँचाई 8 m है, तो पुल की वक्रता त्रिज्या क्या है ? Please solve this question ❓
Let radies is R
Then remaining part is R-8
R^2=20^2+(R-8)^2
HW-option D. Added 4 both sides of equation
option D(4+Q²)³/²
Option D is the absolute answer. As we see from the given expression, it could be reduced to sec a(1+tan²a), or (1+tan²a)½(1+tan²a)= (1+tan²a)^1.5. Thus, the answer is, (1+3+a²)^1.5= (4+a²)^1.5.
Seca +tan3a. Coseca
=Seca(1+tan2a)
=Seca.sec2a
=Sec3a
=(4+Q2)3/2
Sir, after reading math from you, I am solving the questions very soon, thank you so much sir.❤
Most welcome
Most welcome
Option(D) right answer🎉🎉agr answer sahi hai to like krna sir😂
Ye series daily chalao sir jee
Very helpful series
By value putting
a=60° and Q=0
Correct ans. Option D
Let ,Tan A = tan 60 = √3
3 = 3 + Q²
Q² = 0
SecA + Tan³A.CosecA =
2 + 3√3× 2/√3 = 8
Ans (d) (4+Q²) = 8 ⚜️
OPTN D....(4+Q^2)^3/2 ANSWER.......THANK YOU SIR FOR OUTSTANDING SESSION NAMASTE 🙏🏻 ❤
Right answer
(4+Q²)³’² is the right answer sir ❤❤❤❤❤ option (d) is the right answer sir ❤❤❤❤❤❤❤❤❤❤❤
(4+Q^2) ^3/2
Option - (D)
Option D is the right answer sir
Thank you for the session sir 🙏
Right answer
शब्द कम पड़ जाते है...
आपके मेहनत के बदले शुक्रिया बोलने के लिए।❤❤❤
So nice of you ❤❤
Answer - d ❤
mera bhi
Last question d option is right
Best explanation sir 🫶❤️
Keep watching
Option D is correct ..... (4+Q²)³/²....
Thanku so mch sir for this amazing class 🥰🤗......
#Mathsguru🤞🏻
Ans d hoga after solving given equation we get - sec^3 , we can find out its value using tan^2 =3+Q^2
Q=o then tan 60 ans d❤❤❤
option D sir ji ..... thnx sir ji itni mehnat free me krne ke liye ..... and mene dekha aap to sbko heart and reply bhi kr dete ho just waw .... aapke passs 30 gante hai kya 🤭😁
42:03 (d) (4+Q^2)^3/2
Kese aaya
Home work ka answer
Option - (d)
option D correct answer of question no, 11 (4+Q^2)^3/2
Sir perday ek video laya kijiye🙏🙏 very helpful video hote hai
I will try
11-d ans❤
Q11-ans option d from value putting if a=60°
Bina aapke video dekhe din nhi gujarta raat nhi hoti love you sir from Bihar ❤
D hoga sir answers
D will be the ans using value putting concept
Put a=60 degree
Option D ] (4+Q^2)3/2
First year engineering me hu but math ke liye jo pyar❤❤ hai usne reel se khich kar video pr laya
SIR OPTION D IS THE RIGHT ANSWER👌👌👌👌👌👌👌👌👌
Q.11...Ans-D (4+Q^2)^3/2.
Q10..D.( 4+Q^2)^3/2
41:55 (4+Q²) ³/²
Option:D (4+Q^2)^3/2
Option --- ddd ((4+Q²) ³/²)
Question no. 11 , Ans - D
Sir mere batch ki validity samapt hone wali h usko kuch din bdha dijiye please 🙏
Option d is correct (4+Q^2)^3\2 ,Aisha baddua n Diya kijiye sir hm sb aapka Bahut respect Krte hai🎉
Sir maine 11 me se 11 saval lagaye maine apane se pahale sir mujhe trigonometry nahi aati thi apaka ka batch padane ke baad math ko ekdum dhuaa... Uda deta hu
D
Es question को पहले long method se करता था but जब से आपका पहले के video me इस question ka solution dekha hai tab se short me hi ho जाता hai
Thank you sir ❤
Option D { Sec³A=( 4+Q²)³/2}
Ddddd Right Answer maza aa gaya h is bar aapse naukari lekar jarur aaunga milane 🙏🙏🙏 sir 😊
Always welcome ❤
Superb session sir maja aa gya. But end me majboor hokar swal ko solve karna pada (4+Q^2)^3/2 d option answer hoga
*"respect button for Gagan sir,,❤❤😊.....!!*
Option d....❤
Chsl ke mock test sir plz
Option D sir.. darr ke maare karna pada 😂🫶
Option D
Ans : option D
thank you so much sir for this session
Always welcome
11 (d) hai answer sir thanks for this amazing session ❤❤
Mind blowing question❤❤
Q:11 Ka answer (4+Q^2)^3/2
🙏 नमस्ते गुरु जी कैसे है आप ?
हमारे लिए इतने Dedication से मेहनत करने के लिए Oscar Goes to You Sir ✓✓
(4+Q^2)^3/2 option D
Option d
Solution of highest quality ❤
Last ka ans option d put a = 45 degree
11 ka dd hoga मेरे गुरु देव (1+ tan square) power 3/2 formula से solve हो gya
Answer is option D ..and mast session sirji 🙏, continue provide pls this type session ❤
Sure 👍
11 question answer - D
D❤
Sir amazing session 🎉❤ Sir VOD agar abhi lete hain toh usme latest questions hongey for cgl 2024?
Sir option (D)- (4+Q²)^3/2 is the right answer sir ji 🥰🙏🙏❤️.
Sabse jyada majaa aaya sir is class me. So thank you so much sir ji 🥰🙏🙏❤️
Sir, add English Subtitles to all RUclips videos. I am interested to learn your class but due to language barrier, i am unable to learn
Option d.. 👍
Ques 11-Option d
(D)(4+Q^2)^3/2
Option Dis the right answer sirji❤
d-
(4+Q^2)3/2