I've learned so much from watching your physics videos in two days than what I have failed to learn in a month from my incompetent physics professor. Thank you so much for posting such high-quality videos that are also entertaining!
Sorry to learn that you are not getting what you need from your physics professor. Kudos to you for finding other resources to help you learn. Thanks for the high praise!
I had no idea what I was doing in this chapter and after watching your videos on kinematics and projectile motion, I was able to get a 100 on my unit test!! Thank you for these really explanatory videos!!
@@FlippingPhysics really, you should do that. Three years went by in learning physics but my professor couldn't explain even remotely closer to your explanation.😅
I love how you sneak warnings for common mistakes into your videos. That situation where you forget to switch the calculator mode between your physics and calculus classes... 😭!
Look at 2 graphs in the thumbnail of this video: www.flippingphysics.com/drop-and-upward-throw.html 1) The graph of position as a function of time in the upper left. 2) The graph of velocity as a function of time just below it. Both of these graphs are for an object which is thrown straight upward from the time it leaves my hand until I catch it again at the same height. The derivative of a position as a function of time graph is velocity. In other words the derivative of the first graph is the second graph. Derivative is slope. As the ball moves up, the velocity is decreasing, hence the slope of the 1st graph is decreasing as a function of time. When the ball is at the very top (its _maximum_ height), its velocity is zero, which means the slope of the 1st graph is zero, which means the value of the 2nd graph is zero. Hence: Set the derivative of a function equal to zero and you will find where that function has maxima and minima. Hope that helps!
That is called the "sine double angle formula" and we use it in the derivation of the range equation: www.flippingphysics.com/deriving-the-range-equation.html
Look at the extreme case that the launch angle is straight up. This one is intuitive that it should have zero range, due to no horizontal initial velocity. Because the range of a projectile is a continuous function, this means that at some point, there is a turning point on this function where maximum range will occur. After that maximum range angle, the function should become a decreasing function that brings it back down to zero. That turning point ends up occurring at 45 degrees, when the landing elevation is the same as the launch elevation.
LOL, *complementary* not complimentary. spikedmath.com/comics/553-complimentary-angles2.png I know you have freely admitted spelling is not your strong point. (A little Latin helps here - complere means "to fill or complete")
![Projectile Motion & Parabolas [Science of NFL Football]](/img/1.gif)
I've learned so much from watching your physics videos in two days than what I have failed to learn in a month from my incompetent physics professor. Thank you so much for posting such high-quality videos that are also entertaining!
Sorry to learn that you are not getting what you need from your physics professor. Kudos to you for finding other resources to help you learn. Thanks for the high praise!
I had no idea what I was doing in this chapter and after watching your videos on kinematics and projectile motion, I was able to get a 100 on my unit test!! Thank you for these really explanatory videos!!
Glad I could help and congrats!
you should teach professors on how to teach physics.
wow. thanks.
@@FlippingPhysics really, you should do that. Three years went by in learning physics but my professor couldn't explain even remotely closer to your explanation.😅
Dude, you're a lifesaver. I've got a test tomorrow. Hope I pass
I hope you pass too!
your presentation is so good
thanks
Billy's "and this one time" bit reminds me of Anthony Michael Hall's monologue about his cousin Kendall.
I love how you sneak warnings for common mistakes into your videos. That situation where you forget to switch the calculator mode between your physics and calculus classes... 😭!
OMG THANK YOU MR P!
My physics teacher right now is screwing me so hard so I started referring to your videos.
Sir your explanation is too good . Thank you sir for this explanation
what a great teacher
Thanks a lot! Really Helpful Videos!
+Noman Hasan You are welcome. Thanks for the adulation!
:)
OMG!!! I ENJOYED LEARNING WITH YOU!!!
WONDERFUL!!!
Dhanyawad. (Means THANKS in hindi).
Your FAN from india
You are welcome my friend. Best of luck to you in your studies.
OMG!!!!!! This is a really good video! Made really easy to understand :D Plus I like the humor
Wonderful!
no one tell him he wrote "complimentary" not "complementary"
Definitely don't do that.
How would you calculate the change in distance from a elevated launch platform?
I needed this so much ; O; Thanks lmao
Glad I can make you laugh and learn.
Mr.P how do you stand Bo disrespecting you like at 2:09?
We all have bad days.
Thanks for this.
You are welcome.
Nice shot
if only i could give you more than one like
There are all sorts of things you can do to help out! And thank you for your lovely comments.
flippingphysics.com/help-out.html
surely , I'll try to do some of these which i possibly can to help you
Thank you. Enjoy learning!
Professor can u say where you are. I mean which place
but how do you use the Range equation if you do not know the angle?? I have the initial velocity and where object lands ??
Solve the equation for theta. In other words, rearrange the equation such that it is theta = ....
Hello
I have a duty to Sunday and need your help I could not understand the question clearly
Hey Mr. P, why did we use sin(2theta) in the range equation and not 2sin(theta)cos(theta)?
I would suggest you watch this: ruclips.net/video/zr4lNTxI0FM/видео.html
I like Billy's presonality :)
can you please tell me that why do we use the derivative of something with respect to something to find the maximum quantity of that particular thing?
Look at 2 graphs in the thumbnail of this video: www.flippingphysics.com/drop-and-upward-throw.html
1) The graph of position as a function of time in the upper left.
2) The graph of velocity as a function of time just below it.
Both of these graphs are for an object which is thrown straight upward from the time it leaves my hand until I catch it again at the same height.
The derivative of a position as a function of time graph is velocity. In other words the derivative of the first graph is the second graph. Derivative is slope. As the ball moves up, the velocity is decreasing, hence the slope of the 1st graph is decreasing as a function of time. When the ball is at the very top (its _maximum_ height), its velocity is zero, which means the slope of the 1st graph is zero, which means the value of the 2nd graph is zero.
Hence: Set the derivative of a function equal to zero and you will find where that function has maxima and minima.
Hope that helps!
I clicked on this video not knowing who it was and then I saw Bo and died of happiness XD
My first video of this channel: Effing Physics!
Can’t see the board
I thought sin 2 theta is a trig identity that equals 2(sin theta cos theta).
That is called the "sine double angle formula" and we use it in the derivation of the range equation: www.flippingphysics.com/deriving-the-range-equation.html
why wouldn 't larger angles would not produce a larger range?
Look at the extreme case that the launch angle is straight up. This one is intuitive that it should have zero range, due to no horizontal initial velocity. Because the range of a projectile is a continuous function, this means that at some point, there is a turning point on this function where maximum range will occur. After that maximum range angle, the function should become a decreasing function that brings it back down to zero. That turning point ends up occurring at 45 degrees, when the landing elevation is the same as the launch elevation.
تشكر thanks
+Gholam Mustafa Ali مرحبا بك You are welcome.
lol you forgot to change socks
thos 3 students look really similar
LOL, *complementary* not complimentary. spikedmath.com/comics/553-complimentary-angles2.png I know you have freely admitted spelling is not your strong point. (A little Latin helps here - complere means "to fill or complete")
This video is not accurate, I have never seen any students that engaged in a physics class.
ps: it's a joke. Thanks for the amazing explanation!
ha
as of right now video games don't make use of this.
actually let me specify a bit further, they don't use it in bullet drop, however it is used in grenades and maybe... arrows, mainly in gears of war.
Ey ey guys t f is the magnitude help :)
I describe magnitude here: ruclips.net/video/uTQ4_AOae1g/видео.htmlm10s
Nice shot