Advent of Code 2020 Day 9 - using Python

[@umarpatel5809]

what does data[i] do

[@dylancodes1669]

data[i] will access an element in the input list. In this case, data[i] represents the number that we are checking is corrupted or not.

[@ccall48]

you really gotta update that java dude or mute the notification lol

[@dylancodes1669]

lol I'll get rid of it

[@masterbe591]

I cheated for part one and used combinations-method 😋
import itertools, time
def puzzle_input():
with open("input.txt") as f:
data = [int(line.replace("
", "")) for line in f]
return data
puzzle = puzzle_input()
def solution_1(data):
width = 25
for x in range(width, len(data)):
sums = list(map(sum, list(itertools.combinations(data[x - width:x], 2))))
if data[x] not in sums:
return data[x]
def solution_2(data):
for x in range(1, data.index(sum_to_find)):
for y in range(0, data.index(sum_to_find)):
if sum(data[y:y + x]) == sum_to_find:
return min(data[y:y + x]) + max(data[y:y + x])
start = time.perf_counter()
print(solution_1(puzzle), time.perf_counter() - start)
sum_to_find = solution_1(puzzle)
start = time.perf_counter()
print(solution_2(puzzle), time.perf_counter() - start)

[@dylancodes1669]

Dang those solutions are so short! I've never tried itertools before.