Man thank you so much for preparing and sharing these videos! I am an undergraduate student as a mechanical engineer and I am studying for my final exam by your videos!
i'm very grateful for your videos about op-amps .i'm using them to revise for my exams coz i do my bachelors in chinese and sometimes i don't understand in class but now i'm understanding everything through this video.
Thank you so much. I had several examples of Op-Amp circuits in my college classes and you were able to solve them effectively. Thanks again for the easy and detailed explanation. Have a great day. From Korea.
The timestamps for the different topics covered in the video is given below: 0:51 Inverting Summing Amplifier 4:48 Scaling and Addition using Summing Amplifier 5:29 Averaging operation using Summing Amplifier 6:40 Application of summing Amplifier 9:26 Non-Inverting Summing Amplifier (with two inputs) 12:51 Non-Inverting Summing Amplifier (with three inputs)
The explanation of non inverting summing amplifier is not understanding well as that of inverting summing amplifier they both didn't go in the same way as that of inverting and non inverting op amp
God playlist bro its like life saver i am from IIT Bombay First year and you ask anybody from where we should learn op amp and they all say your channel name
Thank you so much, sir! You taught in a way no one could, and as the same student who slept when my professor handled this, loved listening to your teaching with great attentiveness... You made this more interesting, while our sir made it look cumbersome
thanks a lot, was slogging the whole semester in this chapter, thank you so much for making it so simple🙏🙏, hope to watch many more topics like these 👍
Sir,thanks for video on electronic,before I had little confusion in learning electronic devices. But now it is clear with ur video ...l will watch all of ur videos sir .
This opamp series in incredible! Deep and lucid style of explanation makes us to understand concepts in much simpler way! One doubt from above video, sir you have said individual voltages we apply in inverting summer will be separated due to virtual ground and effective input impedance will be the R1. What will happen if all three voltages are given at a time? Pl can u elaborate on how each sources acts separate and input impedance doest not change after adding multiple resistance on input side? Thank you
Actually, all the sources are applied simultaneously. But for the analysis, we are applying the superposition theorem. When you consider one source at a time, then the remaining source will be zero. And if you look the circuit, due to virtual ground both terminals of the resistors will be at ground potential. So, it won't affect the impedance of the circuit. I hope it will clear your doubt.
It has been considered. And based on that only, we got Vo = (1 + Rf/ Ra) *V+ . Once, we got V+ using the superposition theorem, then using the concept of virtual ground only, we got Vo = (1 + Rf/ Ra)*V+. In the earlier video of non-inverting op-amp, since I have already covered it, so here I have directly used the expression. For more info, you can check that video. ruclips.net/video/uyOfonR_rEw/видео.htmlsi=ichrOUKxnM8PcJ-y
thanks sir . you helped me understand a tough topic and i helped you by disabling adblocker🎃♨️. as usual i use ad blocker but when i watch any educational video i turn it of and reload the site so that the ads can run . though it might seem funny but if everyone would do in such a way that it could result in a beautiful amount 🖤❤️❤️
Thank you sir nice and clear explanation. But my question is When we about the advantage of non inverting in the previous video, infinite input impedance was one advantage right? So why do we put R1,R2 and R3?
Without the resistors R1, R2 and R3, if you directly connect the three voltages at the non-inverting terminal then it will violate the KVL. Basically, you are connecting three different voltages at the same node. But with resistors, because of the drop across it, it won't happen. And you can find the effective voltage at V+ using the superposition theorem. I hope, it will clear your doubt.
And sir also plz upload some videos on working procedure of filter circuits(i mean how the charging discharging of capacitor, inductor helps in smoothing the ripple )....plz sir upload some videos on these, plz sir, please
In case of the inverting configuration, due to virtual ground, one end of the resistors is connected to the ground. When we consider one source at a time and consider all other sources as zero, (to find the output), then both ends of resistors (For those input signals which are considered as zero) will be at the ground. So, effectively there is no impact of those voltage sources on the output. But that is not the case in the non-inverting configuration as I mentioned at 16:22. I hope it will clear your doubt. If you still have any doubt then let me know here.
Your answer is right but we can't apply superposition theorem for bilateral circuits as we know all semiconductor devices are bilateral or non linear so prove that
well, actually it depends, what is the input signal frequency, and what is the input voltage. Because when op-amp is used with negative feedback, then stability is a function of frequency. For, small DC voltage (in mV), the output will be stable. With the gain of 100, it will be in Volts. But let's say, if you apply an input voltage of 10V, in that case, you won't get 1000V at the output. Rather output gets saturated at the Vsat voltage. For +15V supply, possibly you would get around 12-13V at the output.
My question is why voltage division took place only on the non inverting configuration when we employed superposition theorem what if we employed superposition theorem in the inverting config will voltage division among resistors will take place or not?
In the case of the inverting configuration, if you apply the superposition theorem, then only once source will be active at a time. For example, V1 is active and V2 and V3 is zero. That means one end of the resistor R2 and R3 will be at ground potential. Also, due to the virtual ground, other terminals will be grounded. That means both terminals of R2 and R3 will be at ground potential. And they will act it as if they are not the part of the circuit. So, there is no point of applying the voltage divider rule. I hope it will clear your doubt.
@@ALLABOUTELECTRONICS sir in non inverting we can also do the same thing , active only one source and rest of two source will be grounded then how we can apply superposition theorem , and in the non inverting summing amplifier you are also doing the same thing, grounding V2 , calculating V1 . please clear my doubt ?
Hello My question is that in a single opamp if we apply some signals( like V1a, v2a, v3a etc.) on positive terminal and some signals (like v1b, v2b, v3b etc. ) on the negative terminal in that case what will be the formula for output??
I have discussed that in the separate video. Please watch the video on the differential amplifier. You will get the answer. And after that still, if you have any question then do let me know here.
Can you explain in the superposition theorem, why v1+ =(R2*V1) / (R1+R2), but not v1+ =(R1*V1) / (R1+R2). I can't find any explanation about this voltage division rule.
First, let's assume that when V1 is acting alone, then the total current in the loop is I. So, I = V1 / (R1 + R2). Now, the voltage V+ is actually a voltage drop across R2 right !! And using ohms law, we can say that, V+ = I1*R2. Now, putting the value of I, further, it can be written as V1*R2 / (R1 + R2). So, that is a voltage divider rule. In that equation, V1/ (R1 + R2) is the total current in that loop. I hope, it will clear your doubt.
Actually there is a flow of little current ( in uA). But for ideal opamp it is zero. More over, through bias voltages, opamp also draws the required current for the operation. I hope it will clear your doubt.
At 10:40 the resistance of the OP-Amp is infinite, shouldn't all the voltage V2 drop across the Op Amp itself and thus making V2+=0 ? I am confused at that exclusion of OP-amp's infinite resistance from the circuit
Oh!! I solved by individual currents and added them, got the same value for V2. But when we take currents in consideration we can say current will not enter Op-amp due to infinite resistance, but how do we explain the same with voltage?
@@zenvir1680 If there is a current flowing through any resistor, then there will be a voltage drop across that resistor. It is independent of the resistance of the op-amp. At the non-inverting terminal, the current is flowing through R1 and R2. And the voltage drop across the R1 is V2+.
In case of the non-inverting summing amplifier, V+ terminal is not at ground potential and same is true with inverting terminal. But because of negative feedback, there will be virtual short between inverting and non-inverting terminal (V- = V+)
i have a doubt....that is u have applied superposition theorem for v1 then u have to take series resistance but u taken parallel resistance that is for v1 u have to take r1/r1+r2 but u taken r2/r1+r2.
Ok, I got it where you are referring to. See, here we are applying the voltage divider rule. While applying superposition theorem, If you just consider V1 voltage source alone( and V2 as 0V), then voltage at the non- inverting terminal is V1* R2 / ( R1+R2). Please check the voltage divider rule for resistor once again, you will get it. And if you still have any doubt then let me know here.
What I mean to say is, if both resistors are equal then in that case, you will get (1 + Rf/ Ra) (V1 + V2)/2 R is just for representation to indicate that, the value of two resistors are equal. I hope it will clear your doubt.
I think you are talking about the difference amplifier where there is a voltage source on both positive and negative terminals, isn't it? There is a separate video for that. Please check it.
It is frequently called a signal mixer as it is used to combine audio signal from several microphones, guitars, tape recorders, etc., to provide a single output. Hope that helps. Happy Learning.....
Please check the community tab section of the channel. You will find many questions related to the op-amp. Also, I have made two dedicated videos in the questions based on the op-amp. Here is the link: ruclips.net/video/VdP3tTcaZIc/видео.html
At 9:52 you said voltage at non inverting node is Vx Doubt : Its negative feedback opamp. Inverting end is grounded thus at 0 potential. Then why virtual ground concept isn't applicable here? Why node voltage at Vx ≠0?
No, the inverting node is not at the ground potential. The voltage at the inverting end is the voltage drop across the resistor Ra. Let's say some current Ia is flowing through Ra then the voltage at the inverting end or V- is Ia x Ra. The concept of virtual short is still applicable. That means the voltage at the inverting and non-inverting terminal is the same. That means V+ = V- . Or V+ = Ia x Ra. I hope it will clear your doubt.
@@ALLABOUTELECTRONICS It did to an extent! Last doubt sir please help : lets consider inverting terminal is grounded in that case will Vx or V+ is zero irrespective of any input voltage applied at the non inverting (V+) terminal like V¹, V²?
@@ogbuddha7835 when the inverting terminal is connected directly to the ground terminal then there is no negative feedback. The negative feedback exists when we connect the feedback resistor between the output and inverting terminal and resistor R1 between inverting terminal and the ground.
@@ALLABOUTELECTRONICS You just solved the biggest doubt in my mind. Thank you so much sir. You may not change your world by doubt solving of one random subscriber. But you will change the world of the subscriber.
I was referring about the magnitude of the gain. Its actual gain would be -1 (The second amplifier stage). But because of that overall gain of the two stages will be positive.
But sir if we apply voltage divider rule for non inverting terminal....the voltage at that point does not become equal to that in the inverting terminal .........I am talking about the case of inverting summing amplifier......sir please explain
![Ice On My Teeth - ATEEZ エイティーズ 에이티즈 [Music Bank] | KBS WORLD TV 241115](http://i.ytimg.com/vi/c-n92OgbbwA/mqdefault.jpg)
This op-amp series is incredibly good 👌👌
App feedback or integrater kha se pare ho
nice, simple, clean explanation. this guy is in a small group of people who know how to make difficult things easy to understand. thank you.
@@charleselliott4943 see this guy is really good. I am will be on his channel till I finish school and beyond 😎😎
Man thank you so much for preparing and sharing these videos! I am an undergraduate student as a mechanical engineer and I am studying for my final exam by your videos!
+1
i'm very grateful for your videos about op-amps .i'm using them to revise for my exams coz i do my bachelors in chinese and sometimes i don't understand in class but now i'm understanding everything through this video.
Thank you so much.
I had several examples of Op-Amp circuits in my college classes and you were able to solve them effectively.
Thanks again for the easy and detailed explanation.
Have a great day. From Korea.
This op-amp series is really good overall 👍👍
This illustration of Amplifiers is outstanding. Well done! Thanks you so much!
The timestamps for the different topics covered in the video is given below:
0:51 Inverting Summing Amplifier
4:48 Scaling and Addition using Summing Amplifier
5:29 Averaging operation using Summing Amplifier
6:40 Application of summing Amplifier
9:26 Non-Inverting Summing Amplifier (with two inputs)
12:51 Non-Inverting Summing Amplifier (with three inputs)
Sir why don't u make videos of op amps circuits experiments
Sir what is dc offset?
The explanation of non inverting summing amplifier is not understanding well as that of inverting summing amplifier they both didn't go in the same way as that of inverting and non inverting op amp
Sir I have a question can you answer it please
Your information is very useful.thank you
wow..a very nice explanation with so much of clarity...😍👌👏
Preparing for my final exam. Your videos really save me! Thank you for your work!
God playlist bro its like life saver i am from IIT Bombay First year and you ask anybody from where we should learn op amp and they all say
your channel name
Well done, came for quick study help and got what I needed in the first 5 minutes.
Thank you so much, sir! You taught in a way no one could, and as the same student who slept when my professor handled this, loved listening to your teaching with great attentiveness... You made this more interesting, while our sir made it look cumbersome
thanks a lot, was slogging the whole semester in this chapter, thank you so much for making it so simple🙏🙏, hope to watch many more topics like these 👍
Your explanation is incredibly perfect Sir, thank u
So glad I found your channel. Much better than going to school. I don't even have to raise my hand.
U bring conceptual clarity to me thanks a lot
Amazing, all doubts cleared, thank you so much 🙏🏻
Sir,thanks for video on electronic,before I had little confusion in learning electronic devices. But now it is clear with ur video ...l will watch all of ur videos sir .
Thank you all about electronic you are favorite teacher . Thank you Thank you so much 😌
This opamp series in incredible! Deep and lucid style of explanation makes us to understand concepts in much simpler way!
One doubt from above video, sir you have said individual voltages we apply in inverting summer will be separated due to virtual ground and effective input impedance will be the R1. What will happen if all three voltages are given at a time? Pl can u elaborate on how each sources acts separate and input impedance doest not change after adding multiple resistance on input side?
Thank you
Actually, all the sources are applied simultaneously. But for the analysis, we are applying the superposition theorem.
When you consider one source at a time, then the remaining source will be zero. And if you look the circuit, due to virtual ground both terminals of the resistors will be at ground potential. So, it won't affect the impedance of the circuit.
I hope it will clear your doubt.
@@ALLABOUTELECTRONICS tq 👍
Thank You So Much Sir For this effort to help all of us !
TOP CONTENT.. You deserve more subs
Very helpful and zero confusion concept... So very thanks
Amazing Explantion
Thank you Sir
One doubt: Why did we not consider the concept of virtual ground in case of non-inverting summing amplifier? Thank you for your lectures.
It has been considered. And based on that only, we got Vo = (1 + Rf/ Ra) *V+ . Once, we got V+ using the superposition theorem, then using the concept of virtual ground only, we got Vo = (1 + Rf/ Ra)*V+. In the earlier video of non-inverting op-amp, since I have already covered it, so here I have directly used the expression. For more info, you can check that video.
ruclips.net/video/uyOfonR_rEw/видео.htmlsi=ichrOUKxnM8PcJ-y
thanks sir . you helped me understand a tough topic and i helped you by disabling adblocker🎃♨️. as usual i use ad blocker but when i watch any educational video i turn it of and reload the site so that the ads can run . though it might seem funny but if everyone would do in such a way that it could result in a beautiful amount 🖤❤️❤️
you are the best Sir!!!
this series is really good
Hey since you just commented like 5 days ago could you please explain to me why at 6:00 Rf/R=1/n ? I can't seem to be able to understand why
nvm i realized it was an assumption that he made
Excellent series! Thank you so much!!
I'm wondering which software do you use to make such a wonderful video?
Great video 👌! It would be helpful if u could share the ppts/slides that u had used in the video.
Your videos are really good especially this op amp series..but at times I get trouble understanding what you say..can you add subtitles?
Oh don't bother.. I opened it on my laptop and there are subtitle..my bad🤦🏾♀️
Thank you so much sir.. Amazing explanation. It's really superb..
Good video dear
nice content sir
keep up the good work sir
op brooo🔥🔥🔥🔥 it help mee a lott thank u bhayya😍😍😍😍
Amazing, useful. ... Thank you for sharing
Thank you sir nice and clear explanation. But my question is When we about the advantage of non inverting in the previous video, infinite input impedance was one advantage right? So why do we put R1,R2 and R3?
Without the resistors R1, R2 and R3, if you directly connect the three voltages at the non-inverting terminal then it will violate the KVL. Basically, you are connecting three different voltages at the same node. But with resistors, because of the drop across it, it won't happen. And you can find the effective voltage at V+ using the superposition theorem. I hope, it will clear your doubt.
Superb explained 🏆🏆
very good video sir thanks
Is there anything harder than making sure that two resistors have the same resistance?
Actually it is easy to understood a student.
And sir also plz upload some videos on working procedure of filter circuits(i mean how the charging discharging of capacitor, inductor helps in smoothing the ripple )....plz sir upload some videos on these, plz sir, please
Sir, keep it up👆👍👍
You are the GOAT bruh
Really very informative
thank u sir
Nice video again. Can you please elaborate why there would be cross talk between inputs in non-inverting config but not in inverting one ? Thanks.
In case of the inverting configuration, due to virtual ground, one end of the resistors is connected to the ground. When we consider one source at a time and consider all other sources as zero, (to find the output), then both ends of resistors (For those input signals which are considered as zero) will be at the ground. So, effectively there is no impact of those voltage sources on the output.
But that is not the case in the non-inverting configuration as I mentioned at 16:22.
I hope it will clear your doubt.
If you still have any doubt then let me know here.
For God's sake change the intro music else you are doing a good job
If one more resistor R4 is added but without any voltage source, will R4 will affect the calculation of v1+.
This was very helpfull.Thank you
you are really great.
Excellent video ! Thanks
Your answer is right but we can't apply superposition theorem for bilateral circuits as we know all semiconductor devices are bilateral or non linear so prove that
The op-amp is used in the linear region, so superposition theorem can be applied.
I think we can't apply our sir told us proof tell me proof
The 741 ic connected as a non inverting amplifier for a gain of 100. Determine the stability of the amplifier at this gain
well, actually it depends, what is the input signal frequency, and what is the input voltage. Because when op-amp is used with negative feedback, then stability is a function of frequency. For, small DC voltage (in mV), the output will be stable. With the gain of 100, it will be in Volts. But let's say, if you apply an input voltage of 10V, in that case, you won't get 1000V at the output. Rather output gets saturated at the Vsat voltage. For +15V supply, possibly you would get around 12-13V at the output.
My question is why voltage division took place only on the non inverting configuration when we employed superposition theorem what if we employed superposition theorem in the inverting config will voltage division among resistors will take place or not?
In the case of the inverting configuration, if you apply the superposition theorem, then only once source will be active at a time. For example, V1 is active and V2 and V3 is zero. That means one end of the resistor R2 and R3 will be at ground potential. Also, due to the virtual ground, other terminals will be grounded. That means both terminals of R2 and R3 will be at ground potential. And they will act it as if they are not the part of the circuit. So, there is no point of applying the voltage divider rule. I hope it will clear your doubt.
@@ALLABOUTELECTRONICS Thank you this was helpful
@@ALLABOUTELECTRONICS sir in non inverting we can also do the same thing , active only one source and rest of two source will be grounded then how we can apply superposition theorem , and in the non inverting summing amplifier you are also doing the same thing, grounding V2 , calculating V1 . please clear my doubt ?
Good work!!!
different input voltage with different resistors value. which formula we will use?
Thanks for the videos really it was nice
Sir plz tell what if we apply different signals at both the terminals of a summing Op-amp
Hi, you mean to say, if Vin1 and Vin 2 are different then what would be the output?
Hello
My question is that in a single opamp if we apply some signals( like V1a, v2a, v3a etc.) on positive terminal and some signals (like v1b, v2b, v3b etc. ) on the negative terminal in that case what will be the formula for output??
I have discussed that in the separate video. Please watch the video on the differential amplifier. You will get the answer. And after that still, if you have any question then do let me know here.
In case of I(f) current direction will opposite as current flow higher potential to lower potential... V(out)>node potential 0
U are legend what a content
Good 👍
Wonderful guru ji
Sir what is the maximum output voltage produced by a summing amplifier?
Depends on the biasing voltage of the op-amp. The biasing voltage decides the positive and the negative saturation voltage of the op-amp.
sososo helpful! thank you so much!
Very goodexplaination
Can u put videos about regulated power supply sir..plzzzz
I have already made a video on it. Please go through op-amp as voltage regulator video.
@@ALLABOUTELECTRONICS thank u sir
Thank you very much for sharing this video. I have a question: how to do input bias current compensation then in the summing circuits?
Sir can we Rf equals to 0 in non inverting summing amplifier so it can act as average amlifier ?
Very good videos 👌
Amazing, good explanation 😊 Tq for helping in this 😀
Can you explain in the superposition theorem, why v1+ =(R2*V1) / (R1+R2), but not v1+ =(R1*V1) / (R1+R2). I can't find any explanation about this voltage division rule.
First, let's assume that when V1 is acting alone, then the total current in the loop is I. So, I = V1 / (R1 + R2).
Now, the voltage V+ is actually a voltage drop across R2 right !!
And using ohms law, we can say that, V+ = I1*R2. Now, putting the value of I, further, it can be written as V1*R2 / (R1 + R2).
So, that is a voltage divider rule. In that equation, V1/ (R1 + R2) is the total current in that loop.
I hope, it will clear your doubt.
Sir Which software u r using for making videos.
Ans is 4V......if wrong then plzzz tell write ans...
Can anyone please tell me what is meant by providing dc offset to the input signal?
U r awzm great explanation
Which one is best inverting or non inverting amplifier?
Did you get the answer? Which one is better?
Sir, how the bias voltage is placed in the circuit ?
And sir ,which book should i prefer to study the opamp?
Op Amps and linear integrated circuits .- Ramakant A Gayakwad.
sir if the input impedance of an opamp is very high then there will be no flow of current so, whether the opamp circuit in off state OR NOT?
Actually there is a flow of little current ( in uA). But for ideal opamp it is zero. More over, through bias voltages, opamp also draws the required current for the operation. I hope it will clear your doubt.
At 10:40 the resistance of the OP-Amp is infinite, shouldn't all the voltage V2 drop across the Op Amp itself and thus making V2+=0 ?
I am confused at that exclusion of OP-amp's infinite resistance from the circuit
Oh!! I solved by individual currents and added them, got the same value for V2. But when we take currents in consideration we can say current will not enter Op-amp due to infinite resistance, but how do we explain the same with voltage?
@@zenvir1680 If there is a current flowing through any resistor, then there will be a voltage drop across that resistor. It is independent of the resistance of the op-amp. At the non-inverting terminal, the current is flowing through R1 and R2. And the voltage drop across the R1 is V2+.
@@ALLABOUTELECTRONICS I got that. Thank you so much.
Why didn't we apply concept of virtual ground in non inverting summing amplifier..it also uses negative feedback??
In case of the non-inverting summing amplifier, V+ terminal is not at ground potential and same is true with inverting terminal. But because of negative feedback, there will be virtual short between inverting and non-inverting terminal (V- = V+)
sir,how did you put superposition throrem while discussing about non inverting op amp.
I am finding difficulty understanding it, plz help.
Bro pls consider making videos in HINDI in an alternative channel please. It would be really helpful in understanding the concepts.
i have a doubt....that is u have applied superposition theorem for v1 then u have to take series resistance but u taken parallel resistance that is for v1 u have to take r1/r1+r2 but u taken r2/r1+r2.
Would you please mention the timestamp where you are referring to in the video ?
Ok, I got it where you are referring to. See, here we are applying the voltage divider rule. While applying superposition theorem, If you just consider V1 voltage source alone( and V2 as 0V), then voltage at the non- inverting terminal is V1* R2 / ( R1+R2). Please check the voltage divider rule for resistor once again, you will get it. And if you still have any doubt then let me know here.
At 12:20 when you say R1=R2=R , what's R in this equation because it is not on the drawing ? Thank you!
What I mean to say is, if both resistors are equal then in that case, you will get (1 + Rf/ Ra) (V1 + V2)/2
R is just for representation to indicate that, the value of two resistors are equal.
I hope it will clear your doubt.
@@ALLABOUTELECTRONICS yes thank you!
I think u haven't made video on this topic "Op-amp as subtractor"
Please see to it
Please check the video on op-amp as a differential amplifier.
Here is the link : ruclips.net/video/ltVspUteuuI/видео.html
Does this also follow the same concept of biasing voltage as shown in the differential amplifier
Yes, it does.
what if there is a voltage source on the other terminal? e.g non inverting amplifier has a voltage source in the inverting terminal or vice cersa?
I think you are talking about the difference amplifier where there is a voltage source on both positive and negative terminals, isn't it?
There is a separate video for that. Please check it.
where and why we use summing inverting/non inverting amplifier
It is frequently called a signal mixer as it is used to combine audio signal from
several microphones, guitars, tape recorders, etc., to provide a single output. Hope that helps. Happy Learning.....
What happens when multiple inputs are applied to the inverting and non-inverting sides together?
In that case, op-amp can be used as differential amplifier/difference amplifier. It is also known as the subtractor circuit.
Sir, Please make a video on linear digital IC.
Soon I will make it.
Please send some important question from this op amp
Please check the community tab section of the channel. You will find many questions related to the op-amp.
Also, I have made two dedicated videos in the questions based on the op-amp.
Here is the link:
ruclips.net/video/VdP3tTcaZIc/видео.html
At 9:52 you said voltage at non inverting node is Vx
Doubt : Its negative feedback opamp. Inverting end is grounded thus at 0 potential. Then why virtual ground concept isn't applicable here? Why node voltage at Vx ≠0?
No, the inverting node is not at the ground potential. The voltage at the inverting end is the voltage drop across the resistor Ra. Let's say some current Ia is flowing through Ra then the voltage at the inverting end or V- is Ia x Ra. The concept of virtual short is still applicable. That means the voltage at the inverting and non-inverting terminal is the same. That means V+ = V- . Or V+ = Ia x Ra. I hope it will clear your doubt.
@@ALLABOUTELECTRONICS It did to an extent! Last doubt sir please help : lets consider inverting terminal is grounded in that case will Vx or V+ is zero irrespective of any input voltage applied at the non inverting (V+) terminal like V¹, V²?
@@ogbuddha7835 when the inverting terminal is connected directly to the ground terminal then there is no negative feedback. The negative feedback exists when we connect the feedback resistor between the output and inverting terminal and resistor R1 between inverting terminal and the ground.
@@ALLABOUTELECTRONICS You just solved the biggest doubt in my mind. Thank you so much sir. You may not change your world by doubt solving of one random subscriber. But you will change the world of the subscriber.
Sir at 9:22 for the unity gain amplifier the signal should be applied to the positive terminal.. isn't it?
I was referring about the magnitude of the gain. Its actual gain would be -1 (The second amplifier stage). But because of that overall gain of the two stages will be positive.
But sir if we apply voltage divider rule for non inverting terminal....the voltage at that point does not become equal to that in the inverting terminal .........I am talking about the case of inverting summing amplifier......sir please explain
Hi, I didn't get your question. For the inverting summing amplifier, the non-inverting terminal is grounded.
Sorry sorry I mean to say what if I apply voltage divider rule in the inverting terminal of the inverting summing amplifier.....
Please anyone tell me that how these voltages got calculated with resistance ....and which formula used here .
How can we get v0 in inverting summing amplifier with superposition theorem
Make video on transistors
Soon I will start videos on it.
Keep going 🏆🏆🏆🎖️