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If you want my personal help with Chem, apply for tuition starting September 2024: forms.gle/7xMUS6pSaU5BkgfSA
omg ur such a lifersaver n I couldn't have done this without u ... thnxxxxxx
These vids are bang on 👌 🐐
appreciate it :)
If I calculate the concentration of HX for 4.3 correctly but not sure if it’s right in the exam should I just use the one given in 4.4?Thank you, Great video, very helpful!
Yes always use the exam one if you are unsure
I think you would get error carried forward, no matter which no. you used
Thank you for allll these videos 💯😍
No worries! 😊
Omg lifesaver thank u sm
these videos are amazing. any chance for a video on group 7
Thanks! I will do my best but I have a crazy busy weekend tutoring students before paper 1 so may not have time :(
On part 4.3 wouldn’t HX be the weak acid instead of NaOH since that is a strong base
Actually never mind I wasn’t thinking
@ 5:40 why do we use the end point moles when the Q asked for the concentration in the OG solution ? I don't get that bit
i dont really know bro, sorry
Because at the end point the mol of OH- is equal to the initial mol of HX, this is why you get the steep change in pH.
If you want my personal help with Chem, apply for tuition starting September 2024: forms.gle/7xMUS6pSaU5BkgfSA
omg ur such a lifersaver n I couldn't have done this without u ... thnxxxxxx
These vids are bang on 👌 🐐
appreciate it :)
If I calculate the concentration of HX for 4.3 correctly but not sure if it’s right in the exam should I just use the one given in 4.4?
Thank you, Great video, very helpful!
Yes always use the exam one if you are unsure
I think you would get error carried forward, no matter which no. you used
Thank you for allll these videos 💯😍
No worries! 😊
Omg lifesaver thank u sm
these videos are amazing. any chance for a video on group 7
Thanks! I will do my best but I have a crazy busy weekend tutoring students before paper 1 so may not have time :(
On part 4.3 wouldn’t HX be the weak acid instead of NaOH since that is a strong base
Actually never mind I wasn’t thinking
@ 5:40 why do we use the end point moles when the Q asked for the concentration in the OG solution ? I don't get that bit
i dont really know bro, sorry
Because at the end point the mol of OH- is equal to the initial mol of HX, this is why you get the steep change in pH.