Scullcom Hobby Electronics #19 - DC-DC Boost Converter Test & Review
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- Опубликовано: 15 апр 2015
- Review and Test of a cheap DC to DC Boost Converter Module which uses the XLSEMI Integrated Circuit XL6009. Several modules are tested under different input voltage and output load conditions.
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Crystal clear explanation, thank you for your commitment!
+Manlio Malavolti Thank you.
I'm sitting here with the data sheet for this chip in front of me. It lists the min input voltage as 5 volts. What is the use of letting making measurements while the input voltage has drooped below the min recommend.
The behavior should be known.
The 6009 builtin mosfet can handle input current of 4A, so if you have a low input voltage , as soon as the input current exceed 4A, your desired voltage will drop for sure. When the chip's temperature exceed 65 celsius degree, you need a heatsink
I Enjoy the vids. You are very clear and explain in a well structured manner. It Would be great to see more vids similar using the many different cheap eBay circuit board packages. Your test results are very helpful. Thank you!
mitchellpurelife Thanks for your kind comments. I hope to do more videos of this nature.
Can only dream of having a lab like that but I am working on it! Love the videos I am self educated in electronics thanks to guys like this. Got into some fairly advance stuff I just over study w/e I am trying and its almost like I have done it before.
Thanks for your comment.
Wonderful demonstration ! Keep up the great work !
Best Regards,
Rudolf
Thanks.
A very valuable evaluation of this product. Many thanks!
Thanks Michael.
I bought those little dc dc converter for making a data logger but it was very complicated because the converter introduced a lot of noise and the measurement was not ok. I would like to find ones that are already filtered.
Please I have another question? I want to use 4 leds 10w 12v 900ma all together using the same power cable. How Can I use them all together when The maximum current for each is 900ma? If I use them in parallel, is it necessary or possible to use one power supply 12v 3,6a? I mean, if I use one power supply 12v 3,6a, this current will be divided equally for each one? If I want to use 2 leds 10w 12v, may I use one power supply 12 1,8a?
Great video as always.Well explained and delivered.
+Piddy D Thank you.
Did you look to see what the noise looks like? Is this suitable for a uC equipped with ADC (Like the Arduino)?
I heard that they produce so much noise, as to make working on Analog signals difficult.
Fabulosa prueba de dicho modulo. Muchas gracias!!
Hi, Thanks for your excellent test!, this for the step-up converter. Do you have a test for "Step-Down", too?
Thanks. Have have not done a video test on a Step-Down converter yet, but may be in the future. I am currently working on an update to my Electronic DC Load.
Very good video, thanks for the explaining
i need ur help on a led driver. hlg 250c 1050mah. how to dim a batter way than a tanchy potentiometer potentiometer
Dear Sir, thanks for the video. Question, the dropping of the input voltage is not depend form the power supply you have used at the input? it is possible that at high current lie you had when the output was 1A and the input was about 3A that the power supply you had connected at the input was reaching its limit?
Exellent and professional video reference. Thanks
+hemidenis Thank you.
Did you measure the heat dissipation temp @ 10 w on chip and how a heat sink may adjust results ?
No on this test I did not apart from the finger test and it was hot !!! :)
Great Video! Question: Why is the input voltage decreasing as the output current load increases? I would think that if the input is a constant voltage source it would remain stable.
Rad Stor Thanks. The reason that the input voltage was decreasing as output current increased was due to the fact that the power supply I used at the time to feed in to the unit was not handling the higher input currents, and was limiting. I probably should have used one of my better quality bench power supplies. I will do that next time.
From datasheet of XL4009 handles 4A at input side, so I am concerned about, What could be the max power delivered out at 30 Volts with the input of 20 V.Thx for the review though
I have many of these modules and I used them successfully in many applications that require low wattage. It seems a bit hard to stick a standard heat-sink on the module?
MrMonomonster You can use some thermal conductive heatsink glue which works very well.
Thanks for the review. I have a few similar modules on the way, but they are rated 5A maximum! (very suspect) Will be interesting to see how they perform.
+NearFarMedia Thanks for your comments.
A really good video. I now know how many I need to do the job at what settings. Thanks. Have you tested others. I'm looking to make an efficient UPS for a laptop using 19v 3 amp max. With a 12 v large battery and a few chargers to keep topped up. The Charger are optimisers. I hope to have a 24 hour UPS by using such items.
Excellent testing.
Is it possible to connect two of these in parallel to each other so the load would have a higher current?
it would be possible but not ideal as current sharing may not be equal. Better to get a higher current rating DC-DC converter.
Thanks for the info :)
Thanks a bunch for this information, I'm making a portable, recycled 18650 powered, uUSB charged portable power supply, knowing this kind of module's actual output limit allows me to know what to expect.
Needless to say you got a new subscriptor :D
+Gonzalo del Moral Thanks for your comments and subscribing.
Nice video. I saw a few of your videos already, I learn a lot of them. I have 2 questions about it. Why does the input voltage drop. Seems to me its not a problem of the module, but of the powersupply or connector resistance? And if the module is cooled, does it give more output power?
Roeland Riemens Thanks for your comments. The voltage drop was due to two the resistance of the leads I used to connect the input power - the leads were long and not ideal for high currents. I did find that adding a heatsink did increase the output power capabilities.
Hi do you have any videos explaining how I can understand this?
With 12v input these units happily go well above 10w output. It depends on the input/output ratio.
Thanks Matt.
To get a consistent result which is more in keeping with the claimed performance you must maintain the input voltage (measured at the module input points) each time you modify the load. Maximum output wattage, although possible in the short term, could never be expected to be sustainable from such a small device surface area without the use of additional heatsinking. Efficiency claims also cannot be maintaied at minimum line input voltage due to higher circuit currents (and therefore higher in circuit voltage drops) adding to the heat problem. On a positive note, I am very impressed with your programmable load and wish I had one.
Thanks for your comments. Regards, Louis
Thanks, very helpful and professional! :)
Thank you.
Could two of these be placed in series powered from seperate batteries to make a +- power supply ?
Hi,
I have never tried it. The negative line of each boost converter feed straight through from the battery negative to the negative output of each boost converter. So in effect you would have the positive boost voltage from one converter connected effectively to the negative side of the battery feeding the other boost converter. Give it a try and see what happens!
Regards,
Louis
Trying to use one of these on your precision voltage calibration source which ive adapted but the performance on 3.7v is terrible - the regulation is all over the place with very high inrush current
Why does the input voltage drops when you connect the load. Isnt it seposed to be stable if it is connected to a power suply?
Yes the input voltage should normally be stable but it depends on the capability of the power supply. In this case it was mainly due to the long wire length and wire gauge which cased a voltage drop.
Sir your presentation is really amazing by giving various inputs with volt and current. In this regard i have one question hope you can help and throw some insight.
I have connected Lithium Battery full charged (4.2v) with rated of 3000mah and connected as input to XL6009E1 boost module and set output as constant to 12v to plug wifi router and set-top box, however its not connected and at output the voltage is dropped to 4v. I have google but couldn't find any content. Hope you will give some insight.
Nice job! useful
Useful information.
+nisstw Thanks.
Hello Nice Video. I have one of this boost converters . When I feed with 5v (5V 35A PC PSU) and adjust the ouput to 8V with no load, is fine; and to 35v. But on load condition, a little 12v bulb, mine converter the voltage go down to 5..V and only drain 145mA. Can´t boost anything. On the contrary the same thing but with 12v input, performs well... Is posibly that my converter is defective? What do you think. Thanks and regards (sorry for me english)
Thanks for your comments. Your English is just fine.
Is there such a thing as a boost converter current limiter? Like a boost CV CC (constant current). I want to keep my batteries at 9V but limit the output current to about 300 mA
Yes but remember as the battery discharges the voltage of the battery will drop anyway even though the current output is maintained at 300mA. As an example search for "LM2577S LM2596S DC Step Up Down Boost Buck CC CV Voltage Converter LED Driver UK" on eBay - they cost about £7.
I know the batteries will reduce, but I mean to boost it to 9V. Thanks for the link. After checking a pololu boost converter and seeing it had a quiescent current in the mA, I'm going to assume they all have that and abondon the idea for this project! THanks.
valuable video cheers keep it up👍 I wish if measure the produced power ripple coming out
What is supplying the input power? Shouldn't it keep up with the demand and output constant voltage?
+Stephen Kramer Thanks for your comment. The main problem at the higher currents was the resistance of the leads I used from the power source - should have use much heavier gauge wire!! Using sensing leads on a power supply capable of that would resolve this issue but the power supply I used did not have this option.
Can I drive external MOSFET to increase the output voltage up to 240V ?
Hi, I would not use this device to do that. You will need a much larger inductor to achieve what you are trying to do. There are better solutions such as use a standard 12-0-12 volt secondary mains transformer and build a power inverter using either Mosfets or Power Transistors as the switching on the secondary winding's and control then with a square wave switching signal (i.e. use an NE555).
Thanks for testing!
where I can buy the xtw-sy-8 power supply in europe without being scammed ? Thanks for helping me
Wouldn't have been great to plug this to an oscilloscope to see the signal it delivers (stability, noise, ...) ?
+Tigrou7777 Thanks for your comment.
I put a heat sink on the bottom side of the PCB where the device transfers the heat. Some ppl adhere it to the top of the chip which makes no sense to me.
Hi , thank u for the in-depth analysis of the boost converters.
I wanted to get 32 volts off 16 volts. i used one of these and work fine momentarily well on a load of 10 ohms bldc motor.then it failed or rather burnt. Later i just tried two of these in parallel, without any expectations, but to my surprise it worked fantastically. i removed one of the varistors and connected other varistor in parallel.. can u tell me with ur knowledge if this is stable system ??? can i connect more units in parallel to boost output power???
You can parallel these units to increase the maximum current but you will find that the current load may not be split equally between the two units. A better choice would be to use a single higher current boost converter. If you check-out eBay you will find there are plenty of high current boost converters of 10A or 20A available at low cost.
thanks a lot sir. i will check it :)
u explained it so beautifully....rigorous testing
Greetings, Scullcom ....
Great Review.
I have some couple of questions, just to make sure that i understand what this little DC-DC Boost converter module is..
So, if i understand correctly, assuming the minimum input voltage of this booster was 3.7v and the maximum output voltage was 12v.
I can hook up a 3.7v LiPo to the input and get a 12v out of the output ??
If my above question is indeed True, then how safe would you rate theses boosters ?
"safe": as in throwing them into commercial applications
and final question: What are the drawbacks ? you definitely do gain something
from the boosters but what do you lose ?
aside from never applying a higher voltage comparable to the max output voltage at the input. what are the dangers of this booster/ or stuff you need to watch out for when using them??
Thanks,
Regards
Sorry for the delay I missed seeing your comment earlier.
Yes you should be able to get 12v output from a 3.7v input battery.
These boosters should be fairly safe as the on board XL6009 IC has built in protection for both current limiting and over heating - if it exceeds a safe temperature it will shut down automatically.
Draw backs are switching current ripply on the output voltage at the switching frequency of 400KHz to reduce this I would suggest adding 2 more 220uF capacitors with low ESR across the existing 220uF output capacitor. It is better to use 3 capacitors in parallel as apposed to one big value capacitor since paralleling capacitors will give a lower ESR which is what you need.
There are no real dangers in using this boost converters.
I use this in my selfmade 12v vent where I supply it with usb power. But it does not work properly, The input voltage is not 5 but 2,4 volts, even if I use my lab bench power supply. When I increase the current from the 900 mA which would be enough to power it to mor than 2 amps suudenly the voltage increases to 5 volts and the currents drops back to under 900 mA. Can anybody help me?
Thank you for the upload!
I want to step up 3.7v to 9v-12v at >= 500ma.
Can this be done? I am trying to stay small. I have a 3.7v 1200mah LiPo for supply.
Thanks!
CORZER0 Yes. This DC to DC converter should do the job for you. This module can accept an input voltage down to 3 volts so your 3.7 volt is OK.
Scullcom Hobby Electronics Thank you, kind Sir!
I don't need to boost voltage, I need to power a drone with a 11.1 volt LiPo battery rated at 35C that is supposed to run at 7.4 volts. I am going to power a Photo gimbal and carry a go-pro camera and I need to know if this unit will cut the voltage to the circuit board of the drone which has a voltage cut off at 10.5 volts?
no it does not have a low voltage cutoff. then again, you should not need one, you not be discharging lipo 100%, you should aim to discharge no more than 50-60%, you do not need a low voltage cutoff, you need shorter flight times or more capcity
I want to use 50w led 36v 1,5a but I need to know if this board has the capacity? Maximum hours?
Some one please could explain what kind of testes is he doing??? He changes the Amp value on the equipment and the imputs multimeters change. I need to understand? What is he testing? The board capacity? Please....
We are testing the efficiency of the DC to DC voltage converter. A DC source is used to provide input power to the DC to DC converter under constant voltage, while an electronic load is needed to draw power from the output, usually under constant current loading.The efficiency is then the ratio of power out to power in, most often expressed as a percentage.
Thank you! God bless you.
It would be interesting to see on the scope the output ripples at different loads.
+Христо Христов I will bear that in mind for the future.
I find my self incredibly grateful for your hard work, Now do you think that it'll be to much to ask for a small video showing how to improve that? I mean I really would like to have something that would allow me to get at least 50 Watts??
i bought a DEOK 100W 6A DC Power Source on amazon , person made a comment that it generates
radio frequency interference , what would be a better buy ? how do i stop radio frequency interference ???
+jimmy butler Most cheap DC Boost Converter Modules have issues with RF interference. This module uses the LTC1871 and I see from looking at the module DEOK they only use one 220uF electrolytic capacitor on the output which is probably why you are having a problem. If you check the LCT1871 data sheet they recommend using four 150μF Panasonic capacitors (EEFUEOJ151R) in parallel plus a further two 22μF, low ESR (X5R) Taiyo Yuden ceramic capacitors (JMK325BJ226MM) added for HF noise reduction. The reason you should use four 150uF capacitors in parallel rather than just one big capacitor of four times that value is because of the inductive effect of electrolytic capacitors. The inductive effect or four in parallel is much lower than one big value capacitor. At higher frequencies, this becomes an increasing problem and at some point the impedance becomes positive and the capacitor in facts starts acting like as an inductor. Thats why in good quality switch mode power supplies you see they use lots of electrolytic capacitors in parallel on the output. Hope this is of some help.
Bhai agr mene 4 volt ki battery lagaye tou current 4 volt sy upper nhe Jara minuse horaha hai plus nhe aur agr 12 volt lagaye tou 12 volt sy upper nhe Jara 12 sy Kam horaha hai jwb jaldi
what would happen if you connect two boost converters in series?
The boost converter has a maximum output voltage so will not exceed that level if you put two in series.
Nice Review. Thanks
Thanks
very good experiment
keep the good work really helpful
Thanks Jimmy.
your review is very usefull.
thank you sir
Thanks.
honestly a very good job, thank you, best regards
+eu mesmo Thanks.
Nice video. At this time, sellers advertise its efficiency as: "
+DJ S Yes they are good value for such a low cost.
Sir can i get 9 volt output with 1.2 volt or say 2.4 volt ( 2xAAA) battery input ?
Hi, The minimum input voltage for these DC-DC Up Converters is 3V so you would need to use two 1.5V battery cells. If you use 2 x 1.2V cells it may work if they are fully charges since the voltage would be higher than the 2.4V. Regards, Louis
is it possible to use this module for step down voltage
It doesn't seem so. Step-up + step-down converters cost almost same as two similar units -- the only benefit is location on same PCB.
subbed from Martin's channel. Cheers!
Mooky Mann Many thanks.
How come there are pleople powering 100w LEDs with these? 3A 40v
Its all to do with the Wattage - 100watt LED's normally require between 30 to 34 volts which would mean they would draw about 3 Amp of current. So you could use one of these DC-DC Converters but you would need to add a good heat sink to the Buck Converter IC.
SW pins is driving another high voltage MOSFET...is that possible ?
In theory it may be. Give it a try.
thanks, nice review, helpful.
Your welcome.
Great Review, so what you are saying Louis, is that we cannot always believe everything we hear on the net?? haha! Thanks for sharing, always wondered about these boosters. So right about the heat sink, at 12V you should get a clean 20W or so at least. The off the shelf unit is going into breakdown.
+saturn5tony At the end of the day you seem to get what you pay for!
So true, but after great testing like you do and with some of of the Chinese products, it good to know you can enjoy them with free shipping as well. I would not leave my house tho with any of these on...haha!
Very good review
how much power it can handle
Hi this is a great tutorial thanks, I have got one of these XL6009 to operate my desk top fan. The fan runs on 2 AA batteries but they don't last very long so I have connected 4 AA to my XL6009 and the fan wont turn, any ideas please? Many thanks John :)
+John Berry Thanks for your comments.
perfect test video thank you
Thanks.
does this chip is short circuit prevention built in them, or they just fry if output is shorted accidently. Pls answer thank
Hi Omar,
The module uses the XL6009 DC-DC converter and is protected by internal thermal shutdown, current limiting so should be OK if there is a short on the output. It also has over voltage protection.
Thanks for answering, that suggest me to reset the chip, if it stopped giving output.
I have know some of these chips to go faulty mainly due to the fact that some of these Chinese DC-DC converter modules use fake/copy XL6009 chips and therefore may not comply with all the internal protection of a genuine XL6009.
Ohh I got it now
Thanks, Sir, I really appreciate such a quick answer.
When the chip cooks off would it just simply explode or shutdown or something?
Thanks :-)
steve64464 Most likely it will just shut down if its a genuine IC.
Ah thanks for letting me know , when gets toasty i sometimes worrying its gonna blowup and i end up haveing to pull peices of shrapnal out of my face for the rest of the day, Its a bit annoying that they secure the chip down and chop off the head part so you cant mount it to a heatsink.
Question 1: Can i combine two led drivers of 10 watt each, to get 20 watts of power? Question 2: Can I use a 50 watt led driver (ac to ac) combined with (4 diode homemade) rectifier to power a 50 watt warm white cob led, if not this way, how?
GGomar007 Sorry for delay in answering but missed your message. With regards your questions;
1. Yes you could use two 10 watt LED drivers in parallel to get 20 watts but you may have some minor issues if they are not perfectly matched as one unit may try to provide more power than the other one. You could use a small value current limiting resistor in series with each of the outputs of the 10 watt LED drives to try to balance out any current sharing issues - in this case the resistors used would need to be very low in value say less than 0.5 ohm or you will suffer to much voltage drop across the resistors. A better solution would be to try find a 20 watt LED driver unit.
2. As DC watts = AC watts, which is a measure of power or heat. As all LED's are diodes they would rectify any AC voltage.
Scullcom Hobby Electronics Thank you for replying, I have an 50 watt ac led driver, but I brought a 50 watt led that takes dc so I was just curious if it would blow my led if I hooked it up as is.
Hi , bit of a noob in electronics so pls bare with me . I saw the video and was able to understand that it was able to handle upto 10w of power. I have a use case where in I will be supplying an input of 60w i.e. 12v 5A. Will I be able to use 2 of these in parallel to get outputs of 5v 3A each it would still be at 30w combined. Is this feasable ?
Sravan Reddy The golden rule is never connect the output of power supplies in parallel. Rather find a module that's designed to handle the load you want to drive.
+Aadil Shah Maybe it is your golden rule (probably you invented it), but in practice putting power supplies in parallel is relatively common practice for high output currents.Of course there is some rules how that should be done.
Petar Petrovic There's pretty much only two ways to do it:
1.) use a pair of power supplies that are specifically designed to have their outputs connected in parallel. These usually cost about five times as much as a standard power supply with the same specifications.
2.) add a pair of identical large value, load balancing resistors in series with each output. While the resistors need to be relatively large value, they must be chosen for the load impedance. This works well for high impedance loads but is totally impractical for a low impedance L.E.D. that has negligible resistance.
In the case of A.C. power supplies, you also have to ensure that the outputs are precisely in phase, which negates solution number two.
Aadil Shah You are wrong about second way, you do not need large resistance (but that is dependent how well output voltages of power supplies are match) and usual value used is less than 0.1 ohm (or that is big resistance to you),. That solution is suitable for any load (not as you stated only for high impedance load) with any power supply and it is commonly used in high power telecom DC power supplies (>5000A).
There is other ways also (like specific circuits for IC that are made only for that purpose ...).
Petar Petrovic "high power telecom DC power supplies (>5000A)."
Well that right there is a specialist application that's not going to be using some random set of Ebay specials.
0.1 ohm is a strange value for a through-hole resistor. The cheapest I could find was 5ZAR.
I think the smallest resistance I've ever personally used is 56 ohm.
470 ohm is the lowest I generally use in my own designs.
"(but that is dependent how well output voltages of power supplies are match)"
You're assuming that the OP has purchased a matched pair of power supplies, in which case option one applies. However, it's safer to assume that any random pair of power supplies are not matched at all.
You can probably get away with a hacked solution with a boost mode SMPS, but with a buck converter or a linear regulator you're going to overload one of the two supplies while the other sits idle.
I'm curious, why do you say centigrade instead of Celsius. Aren't they different measurements.
Celsius and centigrade are two names for essentially the same temperature scale. Centigrade is the old fashioned name for Celsius.
sir, input= 5v 2A then what will be the output current for 10V output i.e
input = 5v (2A) , output = 10v (?A).
Input at 5v 2A equals a power of 10 watt. So that would be the maximum power it could deliver in this case. So and output of 10v would deliver a maximum current of 1A but this assumes that the DC-DC boost converter is 100% efficient which is not the case, at best it would be about 90% or less. So for your 10v the maximum current would be about 800mA.
Thank you so so much sir :)
Interesting video. Been studying DC-DC Converters and this video is informative. From what I gather these modules work best with a ratio of 2 or less voltage difference input to output. Anything above that and your efficiency is going to decrease. For standard 3V to 5V phone charging circuits this would do just fine. Sourcing at least 500mA to the phone might take a little bit longer but at 93% or higher since it is less than 2V difference these modules will work great. Easy enough to get some thermal paste and an aluminum or copper fin on top of the IC and it should work just fine... One thing to think about is the isolation between input and output, ie how much ripple is sourced back to the input might start to heat up a set of batteries. Not sure how you test that but in my experience with boost converters the input batteries get really hot when they start to drop voltage. Would be nice to have some sort of protection circuitry to shut off the converter once input voltage drops too low.
+Jimmy King Thanks for you comments. The XL6009 DC -DC converter IC on the board has an Enable pin (pin 2) which is not used on this board. With a small modification you could sense the input voltage and and then use it to control the Enable Pin - If you take it low below 0.8v the IC switches OFF. When you take it HIGH, 1.4v or above the IC switches ON. If the Enable Pin is left disconnected (floating) it goes HIGH by default so the IC is ON.
XL6009 is the name of the chip. There are different designs and some of them uses two inductors. The model you got has only one. Did you have any chance to test the other version? They're not so much different in price.
I have tested a whole range of these DC to DC converters over the years. May be worth doing a video comparing some. Regards, Louis
Thanks for your response. That'd be very cool if you do.
I bought the model sold by czb6721960. Things like this are very easy to make. Anyone can find a factory and produce them. Quality can vary greatly depends on the manufacturer or the order requirement. So it's always a bit tricky.
Not sure whether this model will meet spec at all. But at least it got two inductors! Which should make quite some difference? Hope you can do one in your next video. Also looking forward to see other models.
Regards,
Eric
Thanks !.just want to buy one of this,that was helpfull.
Blahblox Gyuanox Glad it was of help.
Scullcom Hobby Electronics Same here, thanks for your video
sir pls guide how to design best li ion 18650 charging
Thank u sir. I request pls suggest an idea sir. How can I get a circuit of 2amps 6volta with 9 volt battery
You would need to use a LM2596S DC-DC Buck Converter Adjustable Power Supply Step Down Module. These can be found very low cost on eBay. Below is an example link for 5 modules:
www.ebay.co.uk/sch/sis.html?_itemId=null&_nkw=5pcs+LM2596S+DC+DC+Buck+Converter+Adjustable+Power+Supply+Step+Down+Module&_trksid=p2047675.m4100.l9146
Kamal , you can’t get 2 amps out of an standard 9volt battery, they are not designed for large currents.
niiiiiceeee review, love it
+Alien X Thanks.
Almost 7 years later and most of the modules you can find on amazon, ebay and the like are still more or less based on the same common chips with the same layout.
And they still have the similar flaws they had years ago. Aren't there any moderately inexpensive and reliable modules out there by now?
PROBLEMS REPLYING TO PIRATEMAN COMMENTS BELOW - So answered here instead:
Yes I did, there is some switching noise but quite small. I found adding extra capacitors in parallel with the output capacitor helps a lot. Its better to add several electrolytic capacitors, of the same value, in parallel rather than use one large capacitor as the total ESR (Equivalent Series Resistance) is then much lower.
Mr. Scullcom, what values would you recommend for these smoothing capacitors?
This module had a 220uF at the output so you could add another additional 220uf in parallel with it. This will increase the total capacitance to 440uF while keeping the total ESR (Equivalent Series Resistance) low. Alternatively you could replace the 220uF capacitor with 4 of 100uF (select ones which have a low ESR).
Thank you :)
why does the input voltage drop.....is it the loss of the current meter ?
Hi Bob,
This was mainly due to the fact that the power supply I was using at the time was going in to current limiting mode due to the fact that I exceed its current handling capability. I should have used a power supply that would handle the higher current demands.
Regards,
Louis
will it do .4 ohms at 40 watts with little loss? That is what i am looking for.
+JGBLADES You would have problems as 4 ohm at 40 watt would mean the current would be over 3 amps with a output voltage about 12 volt. It should handle a load of 4 ohm up to about 8 volt output (this would draw 2 amp so power would only be 16 watt). If you increase the output voltage that would be a problem - for example if the output was set to 20 volt and you connected 4 ohm then that would try to draw 5 amp (100 watt) which would exceed its maximum of 2 amp (or 3 amp with heatsink). You would be better off using a different higher power DC to DC Converter.
I tried something similar to those specs and it would not push .5 ohm without a huge voltage drop. It was called a Drok something or other.
+JGBLADES I see you meant 0.4 ohm which at 40 watts would imply you need to handle 10 amp, which is far to high for these modules. If you do a search on eBay for "10 amp DC to DC Converter" you may find something which would be suitable.
Nice video, thanks.
Robert Calk Jr. Thanks
very good job thank you!!
alchemist Thanks.
I like to use these in my Geiger counters in place of the 22.5 volt batteries using a 9 volt.
+Geiger Counter Virtual Museum That should work fine.
good stuff man
+Lord Marshall Thanks.
U KNOW UR STUFF MAN
nice explanation
its fine as long as it gets the job done
+talha rehman Yes agree.
I like your Video ,specially you don't touch the input value ,,that will show us how efficient is the circuit as a feedback accuracy as input voltage (stability ) ,also you show what kind of wattage this circuit can handle to me that was enough to know
Thanks for your comments.
what is the minimum amphs of input
These cheap modules on eBay are rated 2Amp (3Amp Max if heat sink added to control IC).
Very nice video indeed.
Christian Christiansen Thanks