Pls Vote for next ch - Physics Force and Law of Motion NB:- Pls vote, So sir can understand and take the ch that we want the most. As this ch is lil difficult. Thank u
@@naitikworld07Bhai tum asis hi kisi ko motivation channel mein nahi keh sakte, idhar bacche, class 9 ke bacche including me aye hai tum inappropriate bat nhi kar sakte yeh below 18 ke liye hai, yeh accha hua mera bhai jo yeh video dekh raha tha woh iss comment mein reply dene walah tha usse phele meine dekh liya warna woh kya sochta 😤
40:48. Note that to convert speed unit from km/h to m/sec, we multiply it by 5/18. We need to convert it in terms of seconds as the given time is in seconds. Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.22 m/sec Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.66 m/sec Acceleration a = (V - U) / t = (16.66 - 22.22)/5 = -5.56/5 = -1.112 m/s2 May this answer helps you 🎉💐
@@Insurgentsolvesmaths Bhai 16.67 kyu nai hua bata doge please kyunki decimal ke baad 1 ank ke baad ka ank agar 5 se bada hota hai toh uske saath 1+ karte hai . Ho sakta hai Mai galat hu so pls mujhe bata do ❤
1:37:13 Let me do it for ya So, perimeter of the square=10×4=40m The farmer needs 40s to complete=40m therefore, he needs 1 sec to complete=40/40=1m So,in 2min20s/140s he completes=1×140=140m Now total round he completed= 140/40=3.5 round In 3 round his initial position is same as final position so its displacement will be 0 and since he completed 3.5 round he is standing across the diagonal so his displacement=diagonal. Now to find the length of diagonal, AB²+BC²=AC² 10²+10²=AC² 200=AC² AC=√200 =14.14 *English not my first language* ty ^-^
@@durgeshkasaudhan806So since the ball is thrown vertically upward and its going against the gravity so we take the acceleration in negative (-10m/s²) and the final velocity will be 0m/s since it will stop in a position. It is thrown with a initial velocity of 5m/s . Now the height attained, 2as=v²-u² 2×(-10)×s=0²-5² -20s=-25 s=-25/-20 s=5/4 Now time, v=u+at 0=5-10t 10t=5 t=5/10 t=1/2sec Hope u understand now
What I feel like is we all are selfish. Everybody is demanding some chapters but nobody noted dark circles under his eyes. It proves his dedication to teach us. His sleepless nights could just be repayed by us scoring good marks in science.
Top 5 Questions 1:35:01-1(b) Speed is a scalar and velocity is a vector 1:35:04-2(a) Positively accelerated 1:35:46-3(d) Graph-A 1:36:35-4(b) m 1:37:14-5 Ans:-14.14m If it helps you like please 👇
40:27 ANSWER IS....1.11m/sec.sq. Sol... 80kh/h multiply by 5/18=22.22m/s 60km/h multply by 5/18=16.66m/s. a = (v-u)/t = 16.66 - 22.22 /5 = -5.56. -5.56/5 = -1.11 m/s sq. By the way best teacher evr Thanks Prashant bhaiya for motivating us ❤❤😊
40:50 Q. A BUS DECREASES ITS SPEED FROM 80KM/H-1 TO 60KM/H-1 IN 5 S. FIND THE ACCELERATION OF THE BUS. SOLUTION- 80×5/18=22.2 60×5/18=16.6 SUBTRACT BOTH 22.2-16.6=5.6 NOW DIVIDE IT BY 5 (ACCELERATION FORMULA V-U/T) ANSWER - 5.6/5=1.12 1.12 IS A RIGHT ANSWER...
@@Jayantaaswarhere, initial is 22.2 and final is 16.6 . Tough you sub 22.2 from 16.6 then you get 5.6 .So you can write as =>a=v-u/t a=16.6-22.2/5 a=5.6/5 a=1.12
00:04 Understanding and mastering the concepts of motion in Class 9th Science. 01:56 Understanding the concept of motion and its basics 05:32 Motion is relative, perceived differently by different observers. 07:33 Difference between scalar and vector quantities 11:42 Understanding displacement and distance 13:47 Understanding displacement as a scalar or vector quantity. 17:47 Calculating distance and displacement on a circular path 19:55 Understanding speed and distance concept in simple terms 23:44 Velocity is the rate of change of displacement. 25:51 Velocity changes with direction change 29:38 Understanding speed, velocity, and direction in motion 31:31 Importance of being punctual in class 35:22 Acceleration is defined as the change in velocity per unit time. 37:12 The unit of acceleration is the second square on the meter 41:33 Understanding uniform and non-uniform motion and the concept of acceleration 43:27 Understanding the Equation of Motion and its Numericals 47:10 Teaching through creative visualization 48:59 Calculating acceleration using time and velocity 52:50 Understanding the formulas for distance, velocity, and acceleration. 54:49 Understanding the concept of free fall is crucial 58:26 Understanding positive and negative values in motion 1:00:15 Calculation of time and displacement in motion 1:03:47 Understanding the concept of free fall and uniform circular motion 1:05:43 Understanding uniform circular motion and graph importance 1:09:26 Understanding relation between line height and speed 1:11:24 Understanding acceleration in velocity-time graphs. 1:15:08 Understanding the difference between uniform and non-uniform motion 1:16:55 Understanding non-uniform motion 1:20:25 Understanding displacement and distance calculation 1:22:09 Understanding motion graphs: distance-time and speed-time 1:25:52 Understanding velocity time graph and calculating distance 1:27:42 Understanding the concept of equations of motion 1:31:18 Understanding the equation v = u + at 1:33:10 Understanding the derivation of the equation 1:36:51 Understanding free fall physics and solving related questions 1:38:38 Explanation of negative displacement and applying formulas for quick solutions. 1:42:34 Prashant bhaiya saying goodbye
He is our brother. He is our teacher. He is our best motivator❤ Like for prashant bhaiya😊👇 Edit:thanku everyone for 1k likes First time itna sara likes😊
The video covers the concept of motion, including distance, displacement, speed, and acceleration. It emphasizes the relative nature of motion and provides examples to illustrate the differences between scalar and vector quantities. The video also explains the equations of motion and their derivations, and discusses free fall and uniform circular motion. Key moments: 00:00 Understanding motion and rest is crucial in physics. Motion is relative and varies based on the observer's perspective, impacting the understanding of concepts like velocity and acceleration. -The importance of maintaining high energy levels and enthusiasm while learning about motion and rest in physics. -Explaining the concept of motion through everyday examples like school routines and train travel. -Differentiating between scalar and vector quantities in physics and understanding the significance of direction in vector quantities. 08:03 Understanding the concepts of displacement and distance is crucial in physics. Displacement is a vector quantity, while distance is a scalar quantity. -Differentiating between displacement and distance in physics. Displacement involves direction and magnitude, while distance is the total length traveled without considering direction. -Exploring the significance of displacement and distance in real-life scenarios. Understanding these concepts helps in analyzing motion and position accurately. 16:07 Understanding distance, displacement, and speed concepts is crucial. Converting speed to velocity involves multiplying by a conversion factor. Average speed is total distance traveled divided by total time taken. -Importance of understanding distance, displacement, and speed concepts. Conversion of speed to velocity. Average speed calculation. -Explanation of converting speed to velocity by multiplying with a conversion factor. Average speed as total distance divided by total time. -Defining velocity as the rate of change of displacement. Understanding the representation of velocity with the formula v = s/t. 24:13 Speed and velocity are different concepts in physics. Speed is a scalar quantity, while velocity is a vector quantity, and understanding their difference is crucial for grasping physics concepts. This distinction impacts calculations involving displacement, time, and direction. -Understanding the difference between speed and velocity is fundamental in physics education. -The concept of displacement, speed, and velocity helps differentiate scalar and vector quantities. -The relationship between speed, velocity, and direction impacts calculations and understanding of physics principles. 35:44 Understanding acceleration and its relation to speed and distance is crucial in solving physics problems. Acceleration is calculated based on changes in velocity over time, and mistakes in unit conversions can lead to errors. -Acceleration and its significance in physics problem-solving. It involves changes in velocity over time and requires accurate unit conversions for correct calculations. -The impact of unit conversions on determining acceleration. Errors in unit conversions can result in incorrect calculations and solutions in physics problems. 46:56 Understanding equations of motion through a storytelling method can help students memorize and apply them effectively in physics. Visualization and step-by-step processes are key to solving numerical problems confidently. -Importance of storytelling in teaching equations of motion for better retention and application in physics. -The significance of visualization and step-by-step processes in solving numerical problems to build confidence in physics. 48:24 Understanding the concept of free fall in physics involves initial velocity being zero and final velocity determined by gravity. Calculations and formulas help solve physics questions effectively. -Emphasizing the importance of calculations and formulas in solving physics questions accurately. -Exploring the concept of free fall in physics with initial and final velocities explained. -Discussing the significance of acceleration and gravity in understanding physics concepts. 56:29 Understanding the concept of acceleration due to gravity is crucial in physics education. It determines the direction of acceleration based on the object's motion relative to gravity. -Differentiating between positive and negative acceleration based on the object's motion relative to gravity. -Explaining the convention of assigning positive and negative values based on the object's direction of motion relative to gravity. -Discussing the importance of understanding uniform circular motion and its implications in physics education. 1:04:33 Understanding the relationship between speed, velocity, and graphs is essential for physics concepts. Graphs visually represent speed, acceleration, and constant velocity in a clear and informative manner. -Differentiating between speed and velocity, and understanding their impact on circular motion. -Exploring the concept of acceleration through graph interpretation and its relevance to physics calculations. -Analyzing velocity-time graphs to grasp the concept of constant speed and acceleration visually. 1:12:38 Understanding velocity-time graphs helps in determining acceleration. Differentiating between uniform and non-uniform accelerations is crucial in analyzing graphs and solving related questions. -Importance of recognizing acceleration from velocity-time graphs. -Distinguishing between uniform and non-uniform accelerations from the graphs. -Calculating displacement from velocity-time graphs by understanding area under the graph. -Utilizing geometric shapes like triangles and rectangles to calculate areas for better comprehension. 1:20:40 Understanding velocity-time graphs is crucial in physics as they depict motion accurately. Solving problems related to distance, time, and speed on graphs helps in grasping concepts effectively. -Importance of velocity-time graphs in physics education. Solving problems on graphs aids in conceptual understanding of motion. -Significance of solving distance, time, and speed problems on graphs. Mastery of graph problem-solving enhances comprehension of physics concepts. -Encouraging perseverance and belief in hard work to comprehend challenging concepts. Parental support plays a vital role in nurturing a positive learning environment. 1:28:46 Understanding the concept of differentiation in physics can be simplified by learning and applying the basic formulas for acceleration and velocity. It is essential to grasp the relationship between position, time, velocity, and acceleration to solve physics problems effectively. -Acceleration and velocity formulas can help simplify the understanding of differentiation in physics, aiding in problem-solving. -The relationship between position, time, velocity, and acceleration is crucial for effectively solving physics problems involving differentiation. -Interpreting graphs representing physical quantities like velocity and time can enhance comprehension of displacement and aid in problem-solving. 1:36:52 Understanding physics concepts like velocity, displacement, and acceleration in free fall can be challenging but rewarding. It's important to remember the direction of motion and negative values to get accurate answers. -Importance of velocity, displacement, and acceleration in physics. It's crucial to grasp these concepts for solving problems accurately. -Emphasizing the significance of understanding the direction of motion and negative values in physics calculations. Correct application leads to precise solutions. -Encouragement to practice and verify physics concepts independently to excel in exams. Sharing knowledge with friends is also recommended.
1:27:49 Is the sad reality. Prashant Bhaiyya sirf aap hi ho jisko mai apna Bhai manti hu.🥹 Mujhe siblings nahi hai 🥺🥺. Mai 7th me hu aur NSO ki preparation kar rahi hu Thankyou sooooo much Prashant Bhaiyya ❤❤❤🥹☺️😊😊🥰💖💝
Simple trick VASTU V: final velocity A: acceleration S:speed/ distance T=time U=initial velocity 👑Prashant Bhaiya really i am thankful to you by my heart you are my hope to score good marks💗
Pls Vote for the next ch - is matter around us pure NB:- Pls vote, So sir can understand and take the ch that we want the most. As this ch is lil difficult. Thank u
P=power🎉 R=rock🎉 A=awesome 🎉 S=supportive 🎉 H=helpful🎉 A= adoptable 🎉 N= nurturing 🎉 T=talented🎉 You are great Prashant bro Jo jo isko sahi manta hai to like karoo😊
1:37:07 Let abcd be the boundary of field Time= 2 mins 20 secs = 140 sec If he take one round in 40 second Then in 140 sec = 140÷40 = 3.5 rounds Therefore the final position of former will be see after 140 second The displacement = AC ² = AB²+BC² =root 10² + 10² =10 root 2 = 10 × 1.414 = 14.14 m
1:37:07 You are wrong if the side of the square field was 10 m then your answer will be right but the side of the square field is 2.5 m Coz, there is given 'A farmer moves Alon a square field of 10 m. The ans is 12.5 m. Explanation: field abcd = 10 m Therefore,1 side= 2.5 Round covered by the farmer is 3.5 m So, the Final position of the farmer is on C so the displacement from Point A to Point C is 12.5 m. I explained in short so you will be confused anyway, I hope you will understand 😊
Bhaiyaaa Please make videos on Tissues ( Biology) Is matter around us pure ( chemistry) Force ( Physics) Please bhaiya make videos on these topics bcz my unit II are coming soon ...
Thank you Prashant bhaiya aapki vajha se mai apni class ka science topper me se ek hun. Love you bhaiya, 8th Tak mai science se darta tha par apki vajha se ab to Mera Science bhi favourite ban gaya.😊
Pls vote for next chapter Force and law's of motion Pls vote so that sir can know about our difficult chapter...so sir can take the chapter as his next lecture Who all want 🔻🔻 Like this comment So sir can come to know
1:37:13 the answer will be the length of the diagonal of the square field as the the final position will will be diagonal to the initial position so h^2 =p^2 + b^2 , h^2 = 100 + 100 , h^2 = 200 , hypotenuse = root 200 whicch can be written as 10 root 2 : ) ez
Sir, your explanation is very good. But I have a doubt. When we multiplied Velocity and time in the velocity-time graph, how did distance will come, I thought that it would be displacement. So, I want to know that tha area in the velocity-time graph is distance, or displacement? And Why?😢😢
As a senior(Bhaiya), I want to say something Sab kehte h class 9 hard h lekin agr uspr halka s focus dekar padhoge toh ekdam halwa h kyuki mai khud PT-2 exam k baad ache s padhaai suru kiya or usme 83.8% laya Or half yearly mai 69.7% sirf....🥲 Bhatak gya th..😅 isliye Lekin halki si mehnet or class 9 khtm... Or h aise padhna ki December tk pura syllabus khtm hojaye all the best..... Some teachers for class 9:- 1. Science:- abhi jisse padh rhe ho usse hi padho 2. Maths :- shobhit bhaiya/ Ritik sir (as your wish) 3. Sst:- Always DSR or revision ke liye sunlike 4. Hindi :- khel khel mai gyan or gr. ke liye Hindi adhyapak 5. English:- khel khel mai gyan or gr. ke liye dear sir 6. IT ke liye score shala or book ko read krna bahut jaroori h... Mere opinion s yhi best h baaki aapki marzi...
When will chapter of chemistry "Is matter around us pure? " would come. There should be a calendar in which sir should tell when and which chapter will be uploaded. Like if you agree 👍👈👇
Pls Vote for next ch - Physics Force and Law of Motion
NB:- Pls vote, So sir can understand and take the ch that we want the most. As this ch is lil difficult.
Thank u
Yesss I want ch 2 phy.
@@subhmishra_sports me too, lets vote and sir can understand our mindset and he can take according to it
Yes I want it
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Yess I want chapter 2
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2:30 : Topics to be covered
2:41 : Motion
3:47 : Motion is relative
6:43 : Physical Quantity
9:32 : Distance and Displacement
20:12 : Speed
23:52 : Velocity
35:49 : Acceleration
41:04 : Uniform Motion and Non-Uniform Motion
43:46 : Equations of Motion
55:29 : Free Fall
1:04:14 : Uniform Circular Motion
1:07:16 : Graphical Representation of motions
1:28:49 : Derivations of Equations of Motions
1:34:48 : Top 5 Questions
Like if fhis help you ✨
Also pls subscribe 💗
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@@Asrar-gS I didn't need it brhh 🙄
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Thanks it helped a lot dear ❤
1:07:03 here is answer
2×22÷7×42250=44×603571÷100
=26557124÷100×24
=1106546.83÷100
=11065.46 Km/h
Bro you do really so much hardwork and thank you if you don't commented I will remain as confused.
Sir mujhe second equation ki derivation nahi samajh aai
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I wish to God all students have 99.99% in half yearly
Thank you bro 😊😊😊😊😊😊
Thanks bro but it is impossible for class 9 student
Thanks 😊
Yaar baki ka 0.01 bhi dedo 😅😊
Thx broo
I wish that everyone get 97% in their exam.
@@naitikworld07 limit mein bro
@@6c40shashwatpatel2 Nahi to
@@naitikworld07Bhai tum asis hi kisi ko motivation channel mein nahi keh sakte, idhar bacche, class 9 ke bacche including me aye hai tum inappropriate bat nhi kar sakte yeh below 18 ke liye hai, yeh accha hua mera bhai jo yeh video dekh raha tha woh iss comment mein reply dene walah tha usse phele meine dekh liya warna woh kya sochta 😤
@@TheJoyFulLifeYT bhai Jada mat bol.
@@naitikworld07 oo kya hogya
He is our big brother
He is our teacher
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He is all roúnder
1 like for bhaiya 😊
Thank u for 1k likes ❣️
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Haan Bhai
Yes
There was no comment option so I am commenting through reply.
Proof of km/h×5/18=m/s
Km/h=1000m/60×60s=10m/36s=5m/18s
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Tumhe tume 9th class ki kasam like nhai kiya to fail ho jayo ge (do not take risk)
Pagal ho kya
@@ramjaspatel7231 wah.....!
Chup!!
@@_arpitraj142 aur agar like kiye toh tm fail ho jaoo ge😁
Tujhe Kasam comment delete kar Varna fail ho jayega exams main fir repeat karna class 😅😅😅😅
40:48. Note that to convert speed unit from km/h to m/sec, we multiply it by 5/18. We need to convert it in terms of seconds as the given time is in seconds.
Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.22 m/sec
Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.66 m/sec
Acceleration a = (V - U) / t
= (16.66 - 22.22)/5
= -5.56/5
= -1.112 m/s2
May this answer helps you 🎉💐
300/18 is not 16.67
It's 16.66
Hence the answer will be -1.112m/s²
@@Insurgentsolvesmaths corrected the mistake 👍🏻 Thanks for telling
Thanks bro 👍🏽
It was a great help
@@Insurgentsolvesmaths Bhai 16.67 kyu nai hua bata doge please kyunki decimal ke baad 1 ank ke baad ka ank agar 5 se bada hota hai toh uske saath 1+ karte hai . Ho sakta hai Mai galat hu so pls mujhe bata do ❤
@@ronandrohanff7307 Bhai Maine to Aisa koi rule nhi padha
All the best to your paper i wish that everyone get 99%in your exam 😊
Exam is near😨
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When Prashant Bhaiya is here😄😉
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@@k.n2038 bro the derivation that sir has done is graphical?
@@k.n2038 pls tell
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@@k.n2038 plz tell
Force and laws of motion chapter 1:42:21
Vote 😮bhai
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Ch 2 chemistry
Is matter around us pure
Ch 2 biology - tissue
Ch 2 physics - forces and laws of motion
Yes
yes jaldi
Pls jaldi
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1:37:13
Let me do it for ya
So, perimeter of the square=10×4=40m
The farmer needs 40s to complete=40m
therefore, he needs 1 sec to complete=40/40=1m
So,in 2min20s/140s he completes=1×140=140m
Now total round he completed= 140/40=3.5 round
In 3 round his initial position is same as final position so its displacement will be 0 and since he completed 3.5 round he is standing across the diagonal so his displacement=diagonal.
Now to find the length of diagonal,
AB²+BC²=AC²
10²+10²=AC²
200=AC²
AC=√200 =14.14
*English not my first language* ty ^-^
Wahhhh!😅😅
no shit 🤯you're indian and english is not your first language???!!!! HOW ⁉
Bhai ye wala bta de 1:00:00 ki Displacement kaise nikali
@@durgeshkasaudhan806So since the ball is thrown vertically upward and its going against the gravity so we take the acceleration in negative (-10m/s²) and the final velocity will be 0m/s since it will stop in a position. It is thrown with a initial velocity of 5m/s .
Now the height attained,
2as=v²-u²
2×(-10)×s=0²-5²
-20s=-25
s=-25/-20
s=5/4
Now time,
v=u+at
0=5-10t
10t=5
t=5/10
t=1/2sec
Hope u understand now
@@Cry_abt_it_TTThanks bro mujhe bs displacement wala nhi aa rha tha lekin tabhi tumne mere ko time ka bhi bataya tu thank you 🥰
2:31 topics to be covered
2:41 motion
6:46 physical quantity
9:19 distance and displacement
20:11 speed
23:50 Velocity
28:48 Difference between speed and velocity
35:39 acceleration
38:56 retardation
41:02 uniform and non uniform motion
43:48 equations of motion
55:29 freefall
1:04:07 uniform circular motion
1:07:25 graphical representation of motion
1:34:47 top 5 questions
1:41:16 Gyan ki batein
Thanks a lot bro ❤
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Thx
@@ranjithmenon2114 welcome 😉
What I feel like is we all are selfish. Everybody is demanding some chapters but nobody noted dark circles under his eyes. It proves his dedication to teach us. His sleepless nights could just be repayed by us scoring good marks in science.
Right
😢
1 like -=100/ in half yearly exam
Yesss
😂😂
Mai bhi ❤
1 like se hi kaam ban jayega toh lecture bnd hi kr dete hai 👍🏻😐
But mara paper 80 ka ha bhai😢
Top 5 Questions
1:35:01-1(b) Speed is a scalar and
velocity is a vector
1:35:04-2(a) Positively accelerated
1:35:46-3(d) Graph-A
1:36:35-4(b) m
1:37:14-5 Ans:-14.14m
If it helps you like please
👇
5th answer is wrong the answer will be 10× root2
40:27 ANSWER IS....1.11m/sec.sq.
Sol... 80kh/h multiply by 5/18=22.22m/s
60km/h multply by 5/18=16.66m/s.
a = (v-u)/t = 16.66 - 22.22 /5 = -5.56.
-5.56/5 = -1.11 m/s sq.
By the way best teacher evr Thanks Prashant bhaiya for motivating us ❤❤😊
Kaise mera to 5.10 aa raha hai please bata de yaar
@@jd7886 aapne 60 - 80 = -20 multiply by 5/18 and then divided by 5 kra hoga ya phir aapki calculation glt h
@@divyanshukumar2747 mera tho 5.55 aarha h.
40:50 Q. A BUS DECREASES ITS SPEED FROM 80KM/H-1 TO 60KM/H-1 IN 5 S. FIND THE ACCELERATION OF THE BUS.
SOLUTION- 80×5/18=22.2
60×5/18=16.6
SUBTRACT BOTH 22.2-16.6=5.6
NOW DIVIDE IT BY 5 (ACCELERATION FORMULA V-U/T)
ANSWER - 5.6/5=1.12
1.12 IS A RIGHT ANSWER...
answer is 1.112
You are wrong the answer would be in -ve as it is decreasing initial is 16.6 and final is 22.2
@@Jayantaaswar BHAI TUMHARA WRONG ANSWER HAI MERA SAHI HAI
@@shivamkannaujiya2878 thik bhai
@@Jayantaaswarhere, initial is 22.2 and final is 16.6 . Tough you sub 22.2 from 16.6 then you get 5.6 .So you can write as =>a=v-u/t
a=16.6-22.2/5
a=5.6/5
a=1.12
00:04 Understanding and mastering the concepts of motion in Class 9th Science.
01:56 Understanding the concept of motion and its basics
05:32 Motion is relative, perceived differently by different observers.
07:33 Difference between scalar and vector quantities
11:42 Understanding displacement and distance
13:47 Understanding displacement as a scalar or vector quantity.
17:47 Calculating distance and displacement on a circular path
19:55 Understanding speed and distance concept in simple terms
23:44 Velocity is the rate of change of displacement.
25:51 Velocity changes with direction change
29:38 Understanding speed, velocity, and direction in motion
31:31 Importance of being punctual in class
35:22 Acceleration is defined as the change in velocity per unit time.
37:12 The unit of acceleration is the second square on the meter
41:33 Understanding uniform and non-uniform motion and the concept of acceleration
43:27 Understanding the Equation of Motion and its Numericals
47:10 Teaching through creative visualization
48:59 Calculating acceleration using time and velocity
52:50 Understanding the formulas for distance, velocity, and acceleration.
54:49 Understanding the concept of free fall is crucial
58:26 Understanding positive and negative values in motion
1:00:15 Calculation of time and displacement in motion
1:03:47 Understanding the concept of free fall and uniform circular motion
1:05:43 Understanding uniform circular motion and graph importance
1:09:26 Understanding relation between line height and speed
1:11:24 Understanding acceleration in velocity-time graphs.
1:15:08 Understanding the difference between uniform and non-uniform motion
1:16:55 Understanding non-uniform motion
1:20:25 Understanding displacement and distance calculation
1:22:09 Understanding motion graphs: distance-time and speed-time
1:25:52 Understanding velocity time graph and calculating distance
1:27:42 Understanding the concept of equations of motion
1:31:18 Understanding the equation v = u + at
1:33:10 Understanding the derivation of the equation
1:36:51 Understanding free fall physics and solving related questions
1:38:38 Explanation of negative displacement and applying formulas for quick solutions.
1:42:34 Prashant bhaiya saying goodbye
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Next:
Ch-2 is matter around us pure?
Ch-8 force and laws of motion
no first the tissue chapter
Chapter 2
@@proman4781 no
Chapter2 physics
Chapter 2 20:14
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I wish that each and every student who is watching this video they all get 98% in there all exams
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Bhaiya mujhe jee mai dream hai
The video covers the concept of motion, including distance, displacement, speed, and acceleration. It emphasizes the relative nature of motion and provides examples to illustrate the differences between scalar and vector quantities. The video also explains the equations of motion and their derivations, and discusses free fall and uniform circular motion.
Key moments:
00:00 Understanding motion and rest is crucial in physics. Motion is relative and varies based on the observer's perspective, impacting the understanding of concepts like velocity and acceleration.
-The importance of maintaining high energy levels and enthusiasm while learning about motion and rest in physics.
-Explaining the concept of motion through everyday examples like school routines and train travel.
-Differentiating between scalar and vector quantities in physics and understanding the significance of direction in vector quantities.
08:03 Understanding the concepts of displacement and distance is crucial in physics. Displacement is a vector quantity, while distance is a scalar quantity.
-Differentiating between displacement and distance in physics. Displacement involves direction and magnitude, while distance is the total length traveled without considering direction.
-Exploring the significance of displacement and distance in real-life scenarios. Understanding these concepts helps in analyzing motion and position accurately.
16:07 Understanding distance, displacement, and speed concepts is crucial. Converting speed to velocity involves multiplying by a conversion factor. Average speed is total distance traveled divided by total time taken.
-Importance of understanding distance, displacement, and speed concepts. Conversion of speed to velocity. Average speed calculation.
-Explanation of converting speed to velocity by multiplying with a conversion factor. Average speed as total distance divided by total time.
-Defining velocity as the rate of change of displacement. Understanding the representation of velocity with the formula v = s/t.
24:13 Speed and velocity are different concepts in physics. Speed is a scalar quantity, while velocity is a vector quantity, and understanding their difference is crucial for grasping physics concepts. This distinction impacts calculations involving displacement, time, and direction.
-Understanding the difference between speed and velocity is fundamental in physics education.
-The concept of displacement, speed, and velocity helps differentiate scalar and vector quantities.
-The relationship between speed, velocity, and direction impacts calculations and understanding of physics principles.
35:44 Understanding acceleration and its relation to speed and distance is crucial in solving physics problems. Acceleration is calculated based on changes in velocity over time, and mistakes in unit conversions can lead to errors.
-Acceleration and its significance in physics problem-solving. It involves changes in velocity over time and requires accurate unit conversions for correct calculations.
-The impact of unit conversions on determining acceleration. Errors in unit conversions can result in incorrect calculations and solutions in physics problems.
46:56 Understanding equations of motion through a storytelling method can help students memorize and apply them effectively in physics. Visualization and step-by-step processes are key to solving numerical problems confidently.
-Importance of storytelling in teaching equations of motion for better retention and application in physics.
-The significance of visualization and step-by-step processes in solving numerical problems to build confidence in physics.
48:24 Understanding the concept of free fall in physics involves initial velocity being zero and final velocity determined by gravity. Calculations and formulas help solve physics questions effectively.
-Emphasizing the importance of calculations and formulas in solving physics questions accurately.
-Exploring the concept of free fall in physics with initial and final velocities explained.
-Discussing the significance of acceleration and gravity in understanding physics concepts.
56:29 Understanding the concept of acceleration due to gravity is crucial in physics education. It determines the direction of acceleration based on the object's motion relative to gravity.
-Differentiating between positive and negative acceleration based on the object's motion relative to gravity.
-Explaining the convention of assigning positive and negative values based on the object's direction of motion relative to gravity.
-Discussing the importance of understanding uniform circular motion and its implications in physics education.
1:04:33 Understanding the relationship between speed, velocity, and graphs is essential for physics concepts. Graphs visually represent speed, acceleration, and constant velocity in a clear and informative manner.
-Differentiating between speed and velocity, and understanding their impact on circular motion.
-Exploring the concept of acceleration through graph interpretation and its relevance to physics calculations.
-Analyzing velocity-time graphs to grasp the concept of constant speed and acceleration visually.
1:12:38 Understanding velocity-time graphs helps in determining acceleration. Differentiating between uniform and non-uniform accelerations is crucial in analyzing graphs and solving related questions.
-Importance of recognizing acceleration from velocity-time graphs.
-Distinguishing between uniform and non-uniform accelerations from the graphs.
-Calculating displacement from velocity-time graphs by understanding area under the graph.
-Utilizing geometric shapes like triangles and rectangles to calculate areas for better comprehension.
1:20:40 Understanding velocity-time graphs is crucial in physics as they depict motion accurately. Solving problems related to distance, time, and speed on graphs helps in grasping concepts effectively.
-Importance of velocity-time graphs in physics education. Solving problems on graphs aids in conceptual understanding of motion.
-Significance of solving distance, time, and speed problems on graphs. Mastery of graph problem-solving enhances comprehension of physics concepts.
-Encouraging perseverance and belief in hard work to comprehend challenging concepts. Parental support plays a vital role in nurturing a positive learning environment.
1:28:46 Understanding the concept of differentiation in physics can be simplified by learning and applying the basic formulas for acceleration and velocity. It is essential to grasp the relationship between position, time, velocity, and acceleration to solve physics problems effectively.
-Acceleration and velocity formulas can help simplify the understanding of differentiation in physics, aiding in problem-solving.
-The relationship between position, time, velocity, and acceleration is crucial for effectively solving physics problems involving differentiation.
-Interpreting graphs representing physical quantities like velocity and time can enhance comprehension of displacement and aid in problem-solving.
1:36:52 Understanding physics concepts like velocity, displacement, and acceleration in free fall can be challenging but rewarding. It's important to remember the direction of motion and negative values to get accurate answers.
-Importance of velocity, displacement, and acceleration in physics. It's crucial to grasp these concepts for solving problems accurately.
-Emphasizing the significance of understanding the direction of motion and negative values in physics calculations. Correct application leads to precise solutions.
-Encouragement to practice and verify physics concepts independently to excel in exams. Sharing knowledge with friends is also recommended.
Bhai saab😂😂
Apki mehnat koi appreciate ni kar rha 😢😢 but main kar rhi hu 🎉🎉👏👏👏👏👏👏👏👏👏👏👏
Aapne video dekhi ya fir ye sab likha pure time par. jo bhi hoo I really appreciate you ❤️👍
Good 👍 @@DivyaGoyal-nm5pn
1:27:49 Is the sad reality.
Prashant Bhaiyya sirf aap hi ho jisko mai apna Bhai manti hu.🥹 Mujhe siblings nahi hai 🥺🥺.
Mai 7th me hu aur NSO ki preparation kar rahi hu
Thankyou sooooo much Prashant Bhaiyya ❤❤❤🥹☺️😊😊🥰💖💝
Same
Simple trick
VASTU
V: final velocity
A: acceleration
S:speed/ distance
T=time
U=initial velocity
👑Prashant Bhaiya really i am thankful to you by my heart you are my hope to score good marks💗
Nice
Please one like for the motion chapter 0:29
Boards ki Kasam jisne subscribe nahin kiya vo exam mai FAIL 😂😂 (Don't take risk) ☠️💀
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Deadliest combination 🤠
Vote for Chapter:- " GRAVITATION " 🙏
And ATOMS AND MOLECULES...... PLEASE 🙏
Haan gravitation pls
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Yes pls gravitation chapter class 9 pls
Bhaiya gravitation
Pls Vote for the next ch - is matter around us pure
NB:- Pls vote, So sir can understand and take the ch that we want the most. As this ch is lil difficult.
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58:29 gravitation mai v apne yehi kiya. g positive hota hai downward direction mai.
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Please bhaiya please please please
1:27:41 bhaiya triangle ka area (1/2 bh) hota hai naki (bh)
1:37:07
Let abcd be the boundary of field
Time= 2 mins 20 secs
= 140 sec
If he take one round in 40 second
Then in 140 sec = 140÷40
= 3.5 rounds
Therefore the final position of former will be see after 140 second
The displacement = AC ² = AB²+BC²
=root 10² + 10²
=10 root 2
= 10 × 1.414
= 14.14 m
Bro how??????😮
Bro it is a square not a triangle
Please explain
1:37:07
You are wrong if the side of the square field was 10 m then your answer will be right but the side of the square field is 2.5 m Coz, there is given 'A farmer moves Alon a square field of 10 m.
The ans is 12.5 m.
Explanation: field abcd = 10 m
Therefore,1 side= 2.5
Round covered by the farmer is 3.5 m
So, the Final position of the farmer is on C so the displacement from Point A to Point C is 12.5 m.
I explained in short so you will be confused anyway, I hope you will understand 😊
The right answer is 10√2 m.
Vote for next chapter "Force and laws of motion "(physics)❤
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99 likes
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Bhaiyaaa
Please make videos on
Tissues ( Biology)
Is matter around us pure ( chemistry)
Force ( Physics)
Please bhaiya make videos on these topics bcz my unit II are coming soon ...
Sahi kharia hai binod 😄👍🏻👍🏻
I need Tissue lesson
Please tissue
I also need tissue chapter
Explanation on tissue chapter pls...
Bhai you are very very very very very very amazing amazing amazing amazing amazing amazing amazing😍😍😍😍😍👍👍👍
vote for next chapter 'Is matter around us pure'
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dont like now
Like if you want Prashant sir to be your science teacher 😊😊❤❤
1:4:35 answer 25.125😊
Pls vote for class 9 force and laws of motion
Chapter - 2 Is matter around us pure
Noooooooooooooooooooo
Bhaiya plz kl hie video daal do Friday ko ppr hai
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Yesssss i want ch. 2
Yes thanks for this but I don't think every one will agree so let's do so much comments of is matter around us purse together ❤🎉❤
Vote for next chapter 'Is matter around us pure'
It is already uploaded 🎉
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@@MieAesthetic-Eraa. No the video is not available on RUclips my bad😢
1:27:47 how? 25 ana chahiye uska ans. like 1/2 *b*h = 1/2*5*10=50/2=25 ( ans)
Let vote for force and laws of motion 🎉🎉
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Vote for next chemistry chapter "Is Matter Around Us Pure"
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Bhaiya please ch 2 😢
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1:10:00 yes bhaiya concept clear h
1:42:17 "apka bada bhai hoon"
Love this line❤❤
Hmm mara ❤🌎
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D
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overused shayri + copied
👇Vote for force and laws of motion😊
Hi
1:07:03 here is answer
2×22÷7×42250
=2641571.43÷24
=110065.476= ANSWER
Like if it helped you...❤
Love from Punjab....
1 like= 90% in 9th final exams ❤❤❤❤️🔥❤️🔥❤️🔥
Without like 99.4 precent lekar aaya hu 😂😂
Me bhi😂😂
Without any like 96.89 percent lekar aaya hu 😅😅😂❤❤😂
Vote for Tissue chapter 👇🏻
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I always vote for tissue chapter
Yes baya plzz
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Plz bhaiya tissue 😢
Vote for "force and law of motion"😢
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Bhaiya please force and law of motion padhado 6 din baad mera quarterly exam hai please ❤❤❤❤
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Why to fear when Prashant bhai is gere❤
Pls vote for Class 9 Ch 2 Chemistry - Is Matter around us pure?
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bhiya plz tissue chapter samja do plz..........
BIOLOGY
leave a like if you need explanation and do not want to fail..........
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Bhai ro Mt me tujhe samjha dunga bs mujhe tu papa ji keh kr bola.....😅😅😂
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Thank you Prashant bhaiya aapki vajha se mai apni class ka science topper me se ek hun. Love you bhaiya, 8th Tak mai science se darta tha par apki vajha se ab to Mera Science bhi favourite ban gaya.😊
VOTE FOR NEXT CHAPTER : FORCE AND LAWS OF MOTION
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like for biology ch 2
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@@m.t.gaming-st3sg guys vote for physics chapter 2
Pls vote for next chapter
Force and law's of motion
Pls vote so that sir can know about our difficult chapter...so sir can take the chapter as his next lecture
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Like this comment
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1:04:07 uniform circular motion
Vote for Force and low of Motion
yes, thats the second chapter
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Please
Please bhaiya
-1:02:05
Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.22 m/sec
Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.67 m/sec
Acceleration a = (V - U) / t
= (16.67 - 22.22)/5
= -5.55/5
= -1.11 m/s2
1:37:13 the answer will be the length of the diagonal of the square field as the the final position will will be diagonal to the initial position so h^2 =p^2 + b^2 , h^2 = 100 + 100 , h^2 = 200 , hypotenuse = root 200 whicch can be written as 10 root 2 : ) ez
ruclips.net/video/jn-0d6rxeXc/видео.htmlsi=UqE3xcNWvDJWiP2o
bhai poori physics yahin nikal di
😂@@DevanshGoswami-r2z
@@DevanshGoswami-r2z yes sir
Respect for prashant bhaiyaa♥️🌷😭
Sir, next chemistry chapter- Is matter around us pure?
Please 😊
Yesss
40:58, acceleration= -1.11 m/s square
Mera bhi same aaya👍
It's a= -1.11m/s² not -1.11m/s coz si unit of a is m/s²
@@shashibhushan8313
Ye mera 1.11 aa raha ha -1.11 nahi aa raha
Ha
Pae bhaiya ne bola -20/18aa raha
Vote for FORCE AND LAW OF MOTION
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Haa bhaiya pls force and laws of motion ch par video banao
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Bhaiya plz force and laws of motion ke video bana do
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Bhaiya sound ka chapter nahi padhate ho kiya but aap bahut aacha padate ho
In Every Chapter The Last Line Was Really 💓 Touching Line.....😊
Vote for next chapter“ force and law of motion” (physics ) and “Tissues”( Biology ) piz bhaiya my exam is very near September 🙏🙏❤
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Low of motion 😳 😂
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Hope everyone get good marks in their class 9th 😊😊best of luck all ❤❤😊😊
Thanks for 100 likes never got this much in my life 😊😊
Thanks
40:56 ans is 1.11m/s²
1:07:24 GRAPHICAL REPRESENTATION OF MOTION
Who agrees that Indian society needs these kind of teachers.
hm
vote for *FORCE AND LAWS OF MOTION* in one shot
Easy chapter hai
@@DISTROYER_TV bhai h to easy pr ........ padana to padega sir se
@@priya11pcm hmm sahi bat boli aapne
Hi
@@DeepakBhapkar-e5t hii
2:16 200% josh❤
Tomorrow is my Science exam 😢 jis jis ka kal exam h vou 1 like karo😊 and comment it
mera bhi
Me
Me also
Joshmeter Infinity ♾♾
Vote for : Chapter Is Matter Around Us Pure
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already done. Check it
My joshmeter is definitely less than 70% 😢
Infinity ♾ Matlab tho Nahi Pata hota hai na😅
@@tilakchettri9035 infinte matalab pta nhi hai or motion chapter padhne aaye hai . Chapri log 😂😂😂😂
Vote for the ch.2 of physics, chemistry and bio
Is matter around us pure
Is matter around us puer
Tissue
Force and laws of motion
Is matter around us pure
Tissues and
Force and law of motion
Tissues
Sir, your explanation is very good. But I have a doubt. When we multiplied Velocity and time in the velocity-time graph, how did distance will come, I thought that it would be displacement. So, I want to know that tha area in the velocity-time graph is distance, or displacement? And Why?😢😢
Vote for next chapter “ Is matter around us pure "❤(chemistry)
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Hello
Yeah.
Chemistry is ❤
Explain kar diya 😊jake dekho
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@@LataBothra-n3h naaa
As a senior(Bhaiya), I want to say something
Sab kehte h class 9 hard h lekin agr uspr halka s focus dekar padhoge toh ekdam halwa h kyuki mai khud PT-2 exam k baad ache s padhaai suru kiya or usme 83.8% laya
Or half yearly mai 69.7% sirf....🥲
Bhatak gya th..😅 isliye
Lekin halki si mehnet or class 9 khtm...
Or h aise padhna ki December tk pura syllabus khtm hojaye all the best.....
Some teachers for class 9:-
1. Science:- abhi jisse padh rhe ho usse hi padho
2. Maths :- shobhit bhaiya/ Ritik sir (as your wish)
3. Sst:- Always DSR
or revision ke liye sunlike
4. Hindi :- khel khel mai gyan or gr. ke liye Hindi adhyapak
5. English:- khel khel mai gyan or gr. ke liye dear sir
6. IT ke liye score shala or book ko read krna bahut jaroori h...
Mere opinion s yhi best h baaki aapki marzi...
Thank you for your information 😊
@@shreya28710 wlcm
well, it actually is pretty helpful, so thanks :))
@@aesthetic_me2769 😊wlcm
@Vandi6263 wlcm.....😊
I wish all who like this comment will get 99.9999+0.000000000000001=100%😂😂 thank you for 243 like
Pagal tere wish karne sahi nhi pass hoge ham mehnat karni padti hai
Your Answer is wrong ,correct answer is this 0.000000000000099999 likhte pass ho ana fail karwayega
No you are wrong its still 99.9999
You can google
Ok bro 😂😂😂
1:31:38 me bhaiya yaha paas aapne 2ut ko gayab kar diya
But correction is here :-
S=2ut/2+at/2
Then
Ut+at²/2=s
Who else is very happy that prashant bhaiya is teaching science for class 9th too 😊🎉 his respect button 👇👇❤️❤️ don't down her respect 😊
Her 😂
Her😂
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@@avyuktamishra6589 Smartypie's fan
I am leaving at 1:16:06, not asking for likes to remind me because i have tension for my exam.
Padh le bhai
@@mahadevsahu2615 bhai wahi krne yaha aaya hu, kyunki pure saal to bakc**di krte rhe😂😂
😂😂@@Gaurav_cric_editz
Bhaii mera kal exam h😭
Same
When will chapter of chemistry "Is matter around us pure? " would come.
There should be a calendar in which sir should tell when and which chapter will be uploaded.
Like if you agree 👍👈👇
❤❤❤very interasting sir❤❤
Vote for gravitation.....