Gradients - composition | MIT 18.02SC Multivariable Calculus, Fall 2010

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  • Опубликовано: 11 окт 2024
  • Gradients - composition
    Instructor: David Jordan
    View the complete course: ocw.mit.edu/18-...
    License: Creative Commons BY-NC-SA
    More information at ocw.mit.edu/terms
    More courses at ocw.mit.edu

Комментарии • 7

  • @omaraymanbakr3664
    @omaraymanbakr3664 9 месяцев назад +1

    Drawing the dependency graph between variables will make this problem trivial.
    f
    / \ \
    x y z
    /\
    x z
    with g= f ( x,z), you have to calculate partial derv. w.r.t x and z.

  • @ricardo4fun922
    @ricardo4fun922 7 лет назад +11

    This part of the course is very confusing.

    • @jeffreyanderson5333
      @jeffreyanderson5333 3 года назад

      This part is the juice of this course.

    • @jaepark8475
      @jaepark8475 3 года назад

      same

    • @seungchullee221
      @seungchullee221 Год назад

      I think knowing DAG in graph theory is very helpful(inevitable?) to apply chain rule to composition of functions.

  • @middlevoids
    @middlevoids 4 месяца назад

    Because it's a new material to me i write it like this (using the chain rule):
    gx or dg/dx (means fixed z) = df/dx*dx/dx + df/dy*dy/dx + df/dz*dz/dx
    The same but for gy.
    From the constraint i find dy/dx and dy/dz respectively