Gas Laws - Free Formula Sheet: bit.ly/3TOMhhb Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
Just remember why he uses different constant instead of 8.3145 it's because when you are asked to find ATM you should use the R=0.08206 constant and when asked to find Kilopascal you use R=8.3145 constant. Even if you convert Torr to kPa and change constant from 0.08206 to 8.3145 the answer will still be the same.
I platonically love you and adore you for doing this! I always feel so stupid when my teacher discuss these kinds of lessons in class, but with yours I can understand it perfectly! So, thank you so much for doing this!
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Professor Organic Chemistry Tutor, thank you for an outstanding explanation of the classical Ideal Gas Law in AP/General Chemistry. The problems are simple to follow and understand, however conversions can be problematic. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.
started watching your videos when I was in high school and now doing masters your videos really helped pass my exams..thank you so much for your videos!
Can you please 🙏 explain why you converted the pressure from kPa to atm in question number 3 which was about CO2? I am confused 😕 because in some instances you continued using kPa without converting to atm. Can you help me understand why you did that? I am really struggling to comprehend it.
Hi there JG! Could you help me factor these polynomials? It's so hard my nose started bleeding. Anyways, here are the questions: 1. bc(b-c)-ca(c+a)+ab(a+b) 2. a^2b-a^2c-ac^2-ab^2-b^2c+bc^2+2abc Please help me! Thanks
i expanded a lot in this topic and i wonna know is the ideal gas law is in physics or chemistry, and another thing is this for igcse students, plz Answer me ( i need help! )
5:20 I got 33550ml in the second question. He got 33540ml i realised that the difference was from our multiplication of the right side values where it's supposed to be 32.0034 but he only used the 32. While i rounded mine off to three significant figures he didn't, do you think that could be a big case in A-level chem?
should I have gotten the same answer If instead of using 0.0821 I used 8.31 to keep the kPA units? I also converted the mL to Liters so im not understanding how I got 0.44g of CO2 .
I like the videos but you get sloppy on a few terms like R is for the constant R=0.08206 and there are people who are beginners it's like where the heck he got that long number, I recommend doing steps on your videos like this especially problem-solving.
R is always constant so its just something you memorize. In the Ideal Gas Law equation, PV=nRT where R is either 8.3J / (mol * K) OR 0.082 (L * atm) / mol * K). Which one you use depends on the question, if asking for pressure/atm we use the 0.082 wheras kilopascal its 8.3
how would you structure an equation if the equation is asking for molar mass of the gas? I understand the rewrite of r= PV/RT but the answers don’t add up.
the R constants are so confusing, one question mentions torrs, but he uses the constant for atm, another mentions kpa, but he uses the constant for atm again. how am i supposed to know when to use which?
Liquefied natural gas (LNG) is mainly methane with molecular weight of 16 g/mol. A 10 m3 tank is constructed to store LNG at -164°C and 1 atm pressure, under which conditions its density is 415 kg/m3 . Calculate the volume of storage tank capacity of holding the same mass of LNG as a gas at 20°C and 1 atm. Argh can someone help me solve this
Gas Laws - Free Formula Sheet: bit.ly/3TOMhhb
Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
Just remember why he uses different constant instead of 8.3145 it's because when you are asked to find ATM you should use the R=0.08206 constant and when asked to find Kilopascal you use R=8.3145 constant. Even if you convert Torr to kPa and change constant from 0.08206 to 8.3145 the answer will still be the same.
You answered my question thank you
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I actually confused about that ... Why did he use 0.0826 ??? Bcs i read from somewhere else and they use 6.24 instead ..
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I platonically love you and adore you for doing this! I always feel so stupid when my teacher discuss these kinds of lessons in class, but with yours I can understand it perfectly! So, thank you so much for doing this!
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Sir, May I know your name cause from the very bottom of my heart I really want to personally THANK YOU for every single one of your videos. Without these videos I would've probably went to summer classes, so THANK YOU SO MUCHHHHH!!!! :)
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Professor Organic Chemistry Tutor, thank you for an outstanding explanation of the classical Ideal Gas Law in AP/General Chemistry. The problems are simple to follow and understand, however conversions can be problematic. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.
The view starts at 10:15 . After you finish the video, go back to the beginning
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started watching your videos when I was in high school and now doing masters your videos really helped pass my exams..thank you so much for your videos!
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Why ideal gas are applicable for only to dry gas not moist gas?
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1:47, we can also say 471 Kpa for the answer aswell? They don't specify which units to give the answer in
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Can you please 🙏 explain why you converted the pressure from kPa to atm in question number 3 which was about CO2? I am confused 😕 because in some instances you continued using kPa without converting to atm. Can you help me understand why you did that? I am really struggling to comprehend it.
Hi there JG! Could you help me factor these polynomials? It's so hard my nose started bleeding. Anyways, here are the questions:
1. bc(b-c)-ca(c+a)+ab(a+b)
2. a^2b-a^2c-ac^2-ab^2-b^2c+bc^2+2abc
Please help me! Thanks
did u get it at last
Anyone here 2024😊
1:47, the R is a universal constant which is 8.314, why did you put it as 0.08206?
8.314 is when the pressure is in terms of kPa while 0.08206 is in terms of atm
For the first question shouldn't the "V" be converted to m^3 ??
Nope
According to the gas constant 0.08206 L. atm/mole. K,
It shows that the V should always be in atm
@@rosette_renah you mean L cuz atm is for pressure
No. In order to cancel the units present in your constant R, L should be the only unit of V
Actually no it should always be measured in atm
i expanded a lot in this topic and i wonna know is the ideal gas law is in physics or chemistry, and another thing is this for igcse students, plz Answer me ( i need help! )
5:20 I got 33550ml in the second question. He got 33540ml i realised that the difference was from our multiplication of the right side values where it's supposed to be 32.0034 but he only used the 32. While i rounded mine off to three significant figures he didn't, do you think that could be a big case in A-level chem?
Can this lesson also apply on basic thermodynamics?....need reply
Thanks!!!!!!
should I have gotten the same answer If instead of using 0.0821 I used 8.31 to keep the kPA units? I also converted the mL to Liters so im not understanding how I got 0.44g of CO2 .
Yall all doing a chem and stuff my 8th grade teacher trippin and wants us to learn high school stuff in 8th
When to use the absolute pressure for the Ideal gas law?
The intro is the outro they are inversely proportional lol HAJAJJAJA
that's not what inversely proportional means.
good work son i am proud of you
Please make some sums taking the p as nm-2 plz plz 😭❤️
I like the videos but you get sloppy on a few terms like R is for the constant R=0.08206 and there are people who are beginners it's like where the heck he got that long number, I recommend doing steps on your videos like this especially problem-solving.
I'm struggling enough with this subject, where in the hell did this 0.08206 come from? Care to do any explaining at all?
R is always constant so its just something you memorize. In the Ideal Gas Law equation, PV=nRT where R is either 8.3J / (mol * K) OR 0.082 (L * atm) / mol * K). Which one you use depends on the question, if asking for pressure/atm we use the 0.082 wheras kilopascal its 8.3
amazing]
What are you supposed to do when the number of moles is written in scientific notation?
how would you structure an equation if the equation is asking for molar mass of the gas? I understand the rewrite of r= PV/RT but the answers don’t add up.
you don't need to change the equation, you need to use a data booklet and find them in there, itll tell you the mass of the molecules
PV=(mRT)/molecular weight such that m is the mass
Keep the equation. After you get the n, use stoichiometry to convert from moles to gas or vice versa
Nice
The intro is at the end
i have a question, what do we do with the s.f?
Why is pressure measured in atm instead of Pascal?
not sure waht calculator you're using but this 4:17 equals 30, not 32
why did you round the first one to 4 sig figs?
the R constants are so confusing, one question mentions torrs, but he uses the constant for atm, another mentions kpa, but he uses the constant for atm again. how am i supposed to know when to use which?
Why don't you use 237.15 in kelvin?
Question how did you get the o.o8206
Is 273 constant if the problem has torr
0.08206 is the gas constant.
If the pressure is given in torr convert to ATM before solving
Liquefied natural gas (LNG) is mainly methane with molecular weight of 16 g/mol. A 10 m3
tank is constructed to store LNG at -164°C and 1 atm pressure, under which conditions its density is 415
kg/m3
. Calculate the volume of storage tank capacity of holding the same mass of LNG as a gas at 20°C
and 1 atm.
Argh can someone help me solve this
Why aren’t you rounding to the number of sig figs ? 😢
why isnt the pressure rounded to 2 significant figures in the first problem?
where did the rest of the value of r constant go??(0.008206 * (L * atm / mole * k))
i thought we're going to add 273.15 in converting celsius to kelvin?