Long awaited explanation that is really sticking down to earth rather than bumping here and there. Thank you Mr Zahi for making my life in understanding simple op amp subject simple ... rather than the simple op amp subject made complex!
After I read the comments, I realized he used improper word. When I heard, I couldn't think he was really using that kinds of word. I gave him a thumb up for his explanation.
@@pspmaster2071 because he explains his stuff very well, I have watched almost every video on circuit 1 playlist, and he is 100% better than my prof at University hahahha
this was very helpful, except that i think answering the phone during the video & having another guy guess the answers was time consuming. greatly helpful though
i have a question: i am using opamp in open loop configaration vcc=12v, vee=0v, v- =2v, v+=(0 to 5v) ac square wave output is=(3 to 12volts)ac sqr???? i am expecting output=(0 to 12 volts) ac sqr. what happened here please explain.i want 0 to 12 instead of 3 to 12
Form the diagram containing a voltage dependent current source,i can tell that the op amp is an inverting amplifier but your answer is positive.clarification please.
The circuit connected to the op-amp is the small signal model of a common emitter amplifier, which inverts the input. The op-amp again inverts this output, so the final output has the same sign.
The non inverting input has the more positive voltage 10v compared to the inverting input 9v. Gain in calculated using super position of both inputs. Gain will be noon inverted
the potentials are not zero. it starts from Vout potential and ends in the ground, so clearly there is a potential difference for the current to flow. As of why he writes 0 and 0, it probably would be 0 and some negative small number @AAMIR
Open circuit voltage is a potential difference thing. You only have one end of it the other end is no where there, if there would have been ground attached to it, Iz wouldn’t have to be zero necessarily
Why the current through the 1k resistor is 0? If you convert the current source into the voltage source then the current has to go through the 1k resistor, there is no any other way left.
Current will always choose the path of least resistance. Why go to the 1k resistor when you can go to a path with no resistance. It is also connected to ground
You're a super awesome instructor. I wish I was in you class but you posted on youtube anyway. Thank you sir!
thank you sir...
lol at beginning...
"you can combine the 850 and the 850 and make that what..? .... uhhh fuckin 1700?"
haha
I love this guy's videos THE BEST
He's single-handedly teaching me Circuit I by himself, through an online video platform, from the US. That's called progress.
that combined with the that's what she said joke, " Its not going to shrink it that much"
Long awaited explanation that is really sticking down to earth rather than bumping here and there. Thank you Mr Zahi for making my life in understanding simple op amp subject simple ... rather than the simple op amp subject made complex!
my mind blown on the last example.
"Fuckin 1700" haha. Lol, I mistook the "10k" resistors for "IDK" as in "I don't know."
Last question is very good you hybrid transistor equivalent circuit with opamp that was amazing you are a good teacher thank you
After I read the comments, I realized he used improper word. When I heard, I couldn't think he was really using that kinds of word. I gave him a thumb up for his explanation.
Extremely helpful video! thank you, sir!
best circuits teacher on youtube
I agree
6 years from undergrad I fully understood opamps through this video, didnt know what i did to get a A- then
This guy is very good!
@@hokuspokus5034 why do you say that?
@@pspmaster2071 because he explains his stuff very well, I have watched almost every video on circuit 1 playlist, and he is 100% better than my prof at University hahahha
@@clockw1se226 I think I replied to someone else whos comment disappeared.
@@pspmaster2071 is it a ghost?
@@clockw1se226 You tell me
Can a source transformation be applied on the noninverting side to get 10V?
original examples very well explained!
I have not seen any slow solving like this, if you increase your speed by 100 times, then this examples can be perfect. thanks for the video !
Much appreciated Sir😊
Basic
incredible. the best tutorial before my quiz. and can I ask you where do you teach?
6:00 From where you got 27V when rail to rail is +-9V so 18V difference?
That's not the power supply of the opamp! Just a voltage source at the Input.
ı liked the first question it s very helpful and enough explanation
good explanation..thanks
this was very helpful, except that i think answering the phone during the video & having another guy guess the answers was time consuming. greatly helpful though
THANK YOU!
How can Vout be greater than the saturation voltage?
i have a question:
i am using opamp in open loop configaration
vcc=12v, vee=0v, v- =2v, v+=(0 to 5v) ac square wave
output is=(3 to 12volts)ac sqr????
i am expecting output=(0 to 12 volts) ac sqr.
what happened here please explain.i want 0 to 12 instead of 3 to 12
How do you suggest the Io current (current at Vout going inside the opamp) goes inside the opamp while Vout itself comes out of the Opamp.
Choosing the direction of current is arbitrary. Well, having negative answer suggests that the assumption of direction of current is wrong.
fuckin' 1700 loled
LMAO I JUST CAUGHT THAT
I replayed the video to verify I heard it lol!!!😂😂😂
@@pspmaster2071 Where does he say it?
where?
@@MoSweiti666 0:26
Good
could you please tell me book name which you showing this video?
Form the diagram containing a voltage dependent current source,i can tell that the op amp is an inverting amplifier but your answer is positive.clarification please.
The circuit connected to the op-amp is the small signal model of a common emitter amplifier, which inverts the input. The op-amp again inverts this output, so the final output has the same sign.
I love this guy
Thank you so much Sir
awesom class
Confused as to how you got a positive value for Vout if thats an inverting op amp. If Vin is (+), Vout should be (-)
The non inverting input has the more positive voltage 10v compared to the inverting input 9v. Gain in calculated using super position of both inputs. Gain will be noon inverted
why we know Iz=0 Can u explain me? thank you!
why v1=v out + iz*1m but not equal to v out -iz*1m
so Good...
ya 2nd question is clearly wrong ! how could they find non-zero current between two zero potential ?
the potentials are not zero. it starts from Vout potential and ends in the ground, so clearly there is a potential difference for the current to flow. As of why he writes 0 and 0, it probably would be 0 and some negative small number @AAMIR
Why is Iz just equal to zero?
Open circuit voltage is a potential difference thing. You only have one end of it the other end is no where there, if there would have been ground attached to it, Iz wouldn’t have to be zero necessarily
thank you!
where are we getting 10V when were are doing (9-10/100) @ 4:44
v-=v+. Since v- is 10V then v+ is also 10V.
-10 mv
I don't understand why the current value is negative?? anyone can help pls.
bless you man
Plz suggest me a book for critical problem on op amp
Fundamentals of Electric Circuits, 6th edition
although class is not boring
why is the current through the 1k resistor zero?
Path of least resistance.
Because its an open circuit
Voltage difference between 1k resistor is 0. Current is equal to (Voltage difference) /R.therefore 0/R=0
Why the current through the 1k resistor is 0? If you convert the current source into the voltage source then the current has to go through the 1k resistor, there is no any other way left.
Current will always choose the path of least resistance. Why go to the 1k resistor when you can go to a path with no resistance. It is also connected to ground
awsome :)
850 + 850 … what is that f*cking 1700 😂
2nd question is clearly wrong...
why is it not V+ = - V-?
Because Voltages have to be the same at the input of opamp
Why Iz = a 0????
Fateh Chakib because it's an open loop and there's no path for Iz to flow. Thus Iz=0.
FUKING 1700 LOL
+118 ma
I DONT UNDERSTAND WHY IZ IS ZERO (27-0/1M) IS NOT ZERO !
It's zero because it's an open circuit , no current flow means zero current
its an open circuit bro..
it's open bruh
why when Ix=Iy he multiply it with a 1700?
It's one of the steps he took to solve for V_out. He needed to multiply by 1,700 to clear the denominators.
do you really had to answer that phone call ? -_-
you know you are on the internet and can control time -- just forward.
arrogant and unhelpful manner, switched off
Try again. Better answer.
@@byllgrim6045 Perfection.
I disagree.