UPSC CSAT - Basic Concept Of Number System (संख्या पद्धति ) | UPSC IAS 2024 | Short Tricks | OnlyIAS
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Day by day this Coaching institute is shining between who can’t afford coaching 🙏 thanks to all teachers especially Rishab sir🎉
For those who don't understood last question 👍👍✍️
See we have two digit number
ab means 10a +b according to representation rule
After reversing it becomes
10b+a and the difference between them is 27 ,so
Evaluate
(10a+b) -(10b+a)=27
9a-9b =27
Take 9 common
a-b = 3
So we get an condition
In question they said two digit numbers means digits are from 1 to 9
So place all numbers in obtained equation
1) (a=3,b=0) =3 after (a-c)
2) (4,1)
3) (5,2)
4)(6,3)
5)(7,4)
6) (8,5)
7)(9,6)
7 possible values
I hope you got it❤❤
East to West Rishab Sir is the Best🎉🎉🎉
Mind changes time to time
@@abhayjha2390yes but some people are special and they gave a big contribution in our life ❤ so some teachers are very special and equal to god 😍
1st PQ (C) 511/333
2nd PQ (D) 8
3rd PQ (D) None (6)
thank you so much sir
Can you explain last one
@@ronitk2044 Find difference a-b like sir did which will be 3 , like that the nos are 14, 25, 36,47, 58, 69 satisfy the condition , total 6
@@chaya9119 can u explain how 14, 25 till 69 has been calculated please
@tanishagupta4302 which question?
@@prativasingh7905 it shall be (4-1=3), (5-2=3), (6-3=3), (7-4=3)..... It is 41,52,63,74,85,96
Sir aaj ke video ke liye aapko bhut bhut dhanyavaad
. Aise hii aashirvaad rahe aapka. ❤🙏🙏❤
Tonnes of thank u sir 🙏 pls continue this series every Sunday ✌✨🙏
Rishab sir always support. Our upsc journey.. Thank you so much💖💖💖💖💖😊😊😊 sir🙏🙏🙏🙏🙏🙏🙏
Undoubtedly here is doing great. Loads of thank you
Practice questions -
1) option c (511/333)
2) option d (8)
3) option d (none) (6)
Thank you so much sir for this session. Hope that you continue this session.
Respected,how you solve last practice questions?
It is 12 for the last ...we have to count the reversed (numbers) also🤔
@@None-lr2cy ok 👍🏻
@None-lr2cy bro, we have to identify the differences between numbers
The difference is 3, so 6 pairs formed out of 12 numbers
sir please continues this series for full preparation 🙏🙏🙏🙏
last question solution: let original no be xy i.e, 10x+y so reversed no = yx i.e, 10y+x. given that xy-yx=27, so 10x+y-10y-x=27 => 9x-9y=27 => x-y=3 => y=x-3. now start substituting values into x from 0 and respective value of y will be (x-3) like if x=3 then y=0 so no.=30 similarly we'll get 41,52,63,74,85 and 96. So, total 7 such numbers.
6 numbers, nicely explained 👍👌 found helpful 👍
@@divyaupadhyay9311total -7 numbers because 30 will also be included
30 include nhi hoga because agar iska reverse number lenge 03 to wo single digit number ho jayegi ...@@anamikarao1010
03 is single digit
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Sme😊
Thankyou sir. Pls continue this series
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very good initiative
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Sir aap Itna clear batatey ho Nice class sir 😊
1)C
2)B
3)C
Thankyou sir for this effort
C
D
D
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Sir ji thankyou for yours efforts💯💯🙌🙌
waiting for next session 🙇♀🙇♀🙇♀🙇♀
44:21 d is correct
49:35 option d is correct
Very much thank sir
PQ - 511/333
PQ - 8
PQ - difference is 3
Thank you so much sir 😊😊
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@@Muskan70953 ya
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Sir my request is that ki we are beginners and we want you to go basic bit by bit in steps by explaining steps and concsepts
i hope that my request will be incorporrated thank you
Good explained sir
Thanks sir
Very very nice sir,
But one request mid me dropped nahi karna,
CSAT also completed
Please sir continue classes for CSAT in RUclips itself 🎉❤❤
Ofcourse 🎉🎉🎉🎉it's so important
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14:55- answer c 511/333
SHIVRAAM
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Thanku sir kafi a6ha lgi class pls continue series sir
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thank you so much sir you taught so well
Pta nahi kyu हर टीचर अपनी सीरीज को बीच में छोड़ देते है
Please sir aap मत छोड़ना
Sir plz continue this series 🙏
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Please continue this topic till end sir.
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The sum of two digit of number is 7.if 27 added to interchange number . what is the number? ( Please give details explanation if possible)
Thank you so much Sir😊🙏🏻
It's really helpful.
14:54 Q1 - 511/333
44:23 Q2 - 8
49:40 Q3 - None (7)
Sir please make a vedio of 2023 csat paper solution 🙏🙏🙏🙏🙏🙏
1) 511/333
2) 8
3) none
Excellent sir ji
Smart 🤓 guy 😮😮
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Thank u sir...
Sir I failed in prelims again because of csat, apki videos bht relevant thi bt sayad practice km rh gai...plz is bar ap abi se continue rkhna series to bht ache se practice ho jaegi .. thanku sir
q1. answer = c) 511/333
q2. answer = d) 8
q3 answer = d ) none
Good Afternoon sir
Thank you so much sir
Last question unable to solve, please help.
❤❤❤
thank u so much sir ji
Thank you so much for this session 🙏❤️
The last one question's answer is 3
a+b= 10a+b------- equation (1)
b+a= 10b+a-------- equation (2)
So, the difference between two digits is 27:-
Then,
(10a+b)-(10b+a) = 27
10a+b-10b-a = 27
9a-9b = 27
Let's take 9 common;
9(a-b) = 27(divide by 9)
a-b = 3
So, there are 3 numbers.
😊❤
I hope you understood.
BUT further its asking how many such digits will form???sirf digit nai puchi hai..how many possibilities puchi hai
@@ayu24222 so, it would be three either.
shukriya shukriya dear sir
Continue this series...
Thank you so much sir 🙏
14:56 option c==>1533/999=511/333
Nice content
Sir thankyouuuuuuu sooooooooo muchhhhhhhhh 😘😅
Last ans is 9 (D none ) difference is 3
(10a+b)-(10b+a)=9(a-b)
9(a-b)=27
a-b=27/9=3
How did you determine it to be 9 ? Pls explain, thanks
Thank you so much sir❤❤❤
Nice 👍
thanku very much sir
Thank you !
Ans.
1- 511/333
2- 8
Answer 1. 511/333
2. 8
3. There are 3 two digit no.
👍👍👍👍👍👍
Pq:
1-511/333
2- 8
3 - not able to solve 😒
1) option C 511/333
2) option D 8
Thanks a lot
sir pls continue and complete CSAT tq sir
15:18 option b is right answers
Option c is the answer
14:45 C
44:52 option b is right answers
14:53 c
44:29 d
49:40 d