L2 | Chp14A, Measures of Central Tendency | Statistics | CA Foundation For Nov 2022 | Pranav Popat

In this session, educator Pranav Popat will be discussing Chp14A, Measures of Central Tendency For CA Foundation Nov 2022.
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➤ About the Educator: Pranav Popat is studied at ICAI. Cracked all levels of CA Exams Both Groups in first attempt & holds 3 Years of experience in teaching. He is a well-known educator for CA Business Mathematics, Logical Reasoning & Statistics
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#centraltendency #statisticsfoundation #meanmedianmode #cafoundationcentraltendency #dispersion

[@aartipareek5152]

Percentage of skilled workers = 40%

[@anandsharma6369]

How to do it

[@aartipareek5152]

@@anandsharma6369
Unskilled workers = x
Skilled workers = y
10000x + 15000y = (x+y)×12000
10000× + 15000y = 12000x +12000y
10000x - 12000x = 12000y - 15000y
2x = 3y
2/3 =y/×
Y = 2/5×100 = 40 %

[@tenlisriller5381]

Good solved Aarti.

[@abhisheksoni6323]

0.1134 sir thank you so much for this valuable lecture

[@carp9560]

Properties of AM. 2 when we take an example of x - 4,6,5,9,1 then mean is 4. Then deviation of a set is 0,2,1,4,-3. Then their AM is not zero.
Please instruct me sir

[@sayeedhaider1547]

4,6,5,9,1 then Mean is 5 so Deviation is -1,1,0,4,-4 then Am is zero.... Simple

[@priyanshumaurya5055]

Thank you sir aap bahut achhe padhate h ❤

[@caaspirantprince7966]

Love you sir great teaching.....😊😊

[@Iamjyoti986]

sir agr class interval
20-29
30-39
aise na hokr aagr
20-30
30-40
aagr aise ho taab bhi hm log mid value nikle ge?

[@papakaflyingchappal1]

Yes

[@sanamallick1491]

Thank you sir for this wonderful session ❤ 40% aaye ga answer

[@SushmitaKashyap-zj2ob]

Thank you sir 🙏.... For all classes 😊

[@sakshi6075]

Mind-blowing classes sir

[@siddhantgandhi2512]

Thank you sir, AM complete 💯✅

[@bishtayushi04]

thank you❤

[@anjaralam366]

Superb session sir

[@yashgolchha1811]

thank you sir

[@anamnaaz5942]

Que.11
Ans=Option a

[@rajchaudhari549]

A 40%

[@Railwayupdate-z9o]

Sir aapki teaching style bhut acchi h
Or sab acche se smj aata h
Thank you sir 🙏🙏👍👍

[@utsavmishra8689]

Sir apki Playlist ki site nhi hoti hai open in chrome Browser

[@NishaYadav-nl1mb]

Sir how you calculate class length 20 ??

[@adarshkumaryadav1431]

upper class -lower class

[@vedatrayeethakur109]

But 369-350 is 19 so how 20 came?

[@Nitingill-pk7er]

Class length = UCB - LCB
(in chapter 13 u will study : UCB - Upper class boundary LCB - lower class boundary
(UCB = UCL +0.5 )
(LCB = LCL -0.5)
Hence ,
369.5 - 349.5
= 20
Hope , this will help u

[@Manishjagtap07]

This is called "TEACHING" 👑

[@prince_vloger_]

Bhaukal maja diye aap to

[@tohidkhanapuri1607]

Sir option A (40%)

[@CA-Wali]

how did u solve

[@edwinsebastian1557]

Thank you sir🥰 HW DONE

[@prithvisingh9108]

Sir aap bht acha gaana gaate h 🤭😍🤗

[@Factsbyrahish]

Or aap majak

[@rpmRajat005]

Bahubali team me saare teachers OP singer hai😁

[@saanumalik1469]

40% sir

[@vedatrayeethakur109]

24:02

[@studyalive.]

0.1134

[@riyashaw5231]

36:37 mein sir??

[@ayushdubey165]

40%

[@manisha1101]

Option-A

[@prithvisingh9108]

Manisha will you please tell me that how 40% came ?....

[@manisha1101]

@@prithvisingh9108 In question average salary of unskilled and skilled workers are given ₹10,000 & ₹15,000 respectively. X1 = 10,000 and X2= 15,000.
And combined salary is ₹12,000.
Formula :- x = n1x1 + n2x2÷ n1+n2
By put the value
12,000= 10,000n1+15,000n2÷ n1+n2
Then by cross multiplication 12,000(n1+n2)=10,000n1+15,000n2
Separate n1 and n2 values
12,000n1- 10,000n1= 15,000n2- 12,000n2
2000n1 =3000n2
n1:n2= 3:2
Total percentage of workers=100
Percentage of Skilled workers= 2÷5×100 = 40%
Option (A).

[@Nitingill-pk7er]

​@@manisha1101tysm ❤

[@riyashaw5231]

34:36 no mein female kq

[@prashantyadav3501]

60%a n s

[@Jitupharmacy]

82×0=82 😂

[@priyankabairwa5050]

O.1134

[@22vanitapal01]

61.416

[@bhawaniprajapat197]

.????

[@flearning8264]

Sir AP IPCC exam ke bhi online class lete ho

[@adarshbalvidhyamandir]

40 % aa rha h kya ?

[@user-yv6vq3he8s]

0.1134