L2 | Chp14A, Measures of Central Tendency | Statistics | CA Foundation For Nov 2022 | Pranav Popat
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- Опубликовано: 21 авг 2024
- In this session, educator Pranav Popat will be discussing Chp14A, Measures of Central Tendency For CA Foundation Nov 2022.
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#centraltendency #statisticsfoundation #meanmedianmode #cafoundationcentraltendency #dispersion
Percentage of skilled workers = 40%
How to do it
@@anandsharma6369
Unskilled workers = x
Skilled workers = y
10000x + 15000y = (x+y)×12000
10000× + 15000y = 12000x +12000y
10000x - 12000x = 12000y - 15000y
2x = 3y
2/3 =y/×
Y = 2/5×100 = 40 %
Good solved Aarti.
0.1134 sir thank you so much for this valuable lecture
Properties of AM. 2 when we take an example of x - 4,6,5,9,1 then mean is 4. Then deviation of a set is 0,2,1,4,-3. Then their AM is not zero.
Please instruct me sir
4,6,5,9,1 then Mean is 5 so Deviation is -1,1,0,4,-4 then Am is zero.... Simple
Thank you sir aap bahut achhe padhate h ❤
Love you sir great teaching.....😊😊
sir agr class interval
20-29
30-39
aise na hokr aagr
20-30
30-40
aagr aise ho taab bhi hm log mid value nikle ge?
Yes
Thank you sir for this wonderful session ❤ 40% aaye ga answer
Thank you sir 🙏.... For all classes 😊
Mind-blowing classes sir
Thank you sir, AM complete 💯✅
thank you❤
Superb session sir
thank you sir
Que.11
Ans=Option a
A 40%
Sir aapki teaching style bhut acchi h
Or sab acche se smj aata h
Thank you sir 🙏🙏👍👍
Sir apki Playlist ki site nhi hoti hai open in chrome Browser
Sir how you calculate class length 20 ??
upper class -lower class
But 369-350 is 19 so how 20 came?
Class length = UCB - LCB
(in chapter 13 u will study : UCB - Upper class boundary LCB - lower class boundary
(UCB = UCL +0.5 )
(LCB = LCL -0.5)
Hence ,
369.5 - 349.5
= 20
Hope , this will help u
This is called "TEACHING" 👑
Bhaukal maja diye aap to
Sir option A (40%)
how did u solve
Thank you sir🥰 HW DONE
Sir aap bht acha gaana gaate h 🤭😍🤗
Or aap majak
Bahubali team me saare teachers OP singer hai😁
40% sir
24:02
0.1134
36:37 mein sir??
40%
Option-A
Manisha will you please tell me that how 40% came ?....
@@prithvisingh9108 In question average salary of unskilled and skilled workers are given ₹10,000 & ₹15,000 respectively. X1 = 10,000 and X2= 15,000.
And combined salary is ₹12,000.
Formula :- x = n1x1 + n2x2÷ n1+n2
By put the value
12,000= 10,000n1+15,000n2÷ n1+n2
Then by cross multiplication 12,000(n1+n2)=10,000n1+15,000n2
Separate n1 and n2 values
12,000n1- 10,000n1= 15,000n2- 12,000n2
2000n1 =3000n2
n1:n2= 3:2
Total percentage of workers=100
Percentage of Skilled workers= 2÷5×100 = 40%
Option (A).
@@manisha1101tysm ❤
34:36 no mein female kq
60%a n s
82×0=82 😂
O.1134
61.416
.????
Sir AP IPCC exam ke bhi online class lete ho
40 % aa rha h kya ?
0.1134