I have a question for you 🙋♂, in colleges and universities, which math courses talks about Continuous Probability Distribution? Which courses talks about this? Which courses? The reason why I wanted to know which courses talks about Continuous Probability Distributions in colleges and universities because I don't know which courses talks about that? Please give me an answer to the question of which courses talks about Continuous Probability Distribution. Please answer my question.
A very good lesson..thank u for this sir,but i have a question In question 1c Is there no way it could be solved direct without solving solving for 0,1 and 2...
Thanks very much but I have a lot of questions regarding part b of the second example. If I use Pr(x=0) + Pr(x=1) + Pr(x=2) + Pr(x=3) + Pr(x=4), I get an answer which is greater than 1. This arises from the fact that Pr(x=4)=10/9 which is impossible in probability. If I try your method, I still wonder why you did not subtract Pr(x=6). Otherwise the video was very helpful.
You may need to watch the introductory videos on probability for clear understanding of binomial probability distribution. See the link of the playlist containing all the videos on Probability and Probability Distribution: ruclips.net/p/PLYwM9CzPztOkBlVGFRjyxyZLu4UcI-moj
Remember coin has two sides ,, that means head is one side and other side there's a tail ..therefore if we toss it once one may get head or tail which is 1/2
Thank you for your feedback. On your question, we didn't include p(x=6) because there is no need for it since the number of trials in the question is 5 (n = 5). You may need to watch the video again for further clarification. Warm regards.
Thank you for your feedback. There are 4 options for each multiple choice question in which only one option is correct. Probability of answering each question correctly is ¼ which is equal to p. Probability of answering it wrongly is ¾ which is q. You may need to watch the video on basic problem on probability for further clarification. Warm regards.
i use a casio fx-82za plus calculator so for me is just put in 6-shift (the devide button which is your C) 4 that will give you 15... hope this helps XD
A coin has two faces, head(H) and tail(T). p = Pr(H) = ½ q = Pr(T) = ½ Please watch the video below for further clarification. ruclips.net/video/Z49J9lLCtm4/видео.html
You just have to think of a number that will make the number of success whole or complete. For example, u were given a success or (p) of 2/5 then think of a number that will make 2 a 5 and that is 3. So, your failure or (q) is 3/5
Thanks sir, much appreciated from south Africa here.
your lessons are just incredible. thank you so much for sharing with us
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This is really good
Explained in such the simplest way 🙂🙂
I have a question for you 🙋♂, in colleges and universities, which math courses talks about Continuous Probability Distribution? Which courses talks about this? Which courses? The reason why I wanted to know which courses talks about Continuous Probability Distributions in colleges and universities because I don't know which courses talks about that? Please give me an answer to the question of which courses talks about Continuous Probability Distribution. Please answer my question.
probability and statsics
Probability and statistics, at the University of Zambia Mat2901/2602
Also data management course
amazing
Thank you! Cheers!
A very good lesson..thank u for this sir,but i have a question
In question 1c
Is there no way it could be solved direct without solving solving for 0,1 and 2...
Yes, you can but it will be cumbersome.
Thanks a lots for very good explanation 😊
WELL DONE!
Thanks 😊 for sharing
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Thanks very much but I have a lot of questions regarding part b of the second example. If I use Pr(x=0) + Pr(x=1) + Pr(x=2) + Pr(x=3) + Pr(x=4), I get an answer which is greater than 1. This arises from the fact that Pr(x=4)=10/9 which is impossible in probability. If I try your method, I still wonder why you did not subtract Pr(x=6). Otherwise the video was very helpful.
Hello good day. Why does in example 1 letter C you included Probability of 0? We are talking about of having a head right?
Sir please how did you get the probability of success as p and q as a failure from the given question
You may need to watch the introductory videos on probability for clear understanding of binomial probability distribution.
See the link of the playlist containing all the videos on Probability and Probability Distribution: ruclips.net/p/PLYwM9CzPztOkBlVGFRjyxyZLu4UcI-moj
Sir how are we getting 1/2 for p and q?
Thank you so much sir.
This helped me alot
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We are glad you enjoyed the video.
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On atmost question.. it is possible to use combination of 2 itself and only? Excluding 0?
We don't actually know the particular question you are referring to. Meanwhile, any other way will give you the same answer.
In the example 2 sir how did you get the success(p) and failure (q).
Have gotten it
Please example 1 how did you get the probability to be 1\2
In example 1 how did you got the 32 and 64?
God bless you
Amen
How did you get P1/2??
Hi
Remember coin has two sides ,, that means head is one side and other side there's a tail ..therefore if we toss it once one may get head or tail which is 1/2
Thanks so much.
Thank you for this wonderful tutorial, well explained 😍
You’re welcome 😊
We really appreciate your feedback and compliment.
Warmest regards.
This is well explained 🥰🥰
Thank you so much!
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We appreciate your feedback and compliment.
But a good concept
thanks sir
What do you mean by 6c4 is 15 I'm not getting it clearly
the example 2 / b id didn't understand very well why you didnt inclidees even the probabibilty p(x=6) when calculating p(x>,=4 )?
Thank you for your feedback.
On your question, we didn't include p(x=6) because there is no need for it since the number of trials in the question is 5 (n = 5). You may need to watch the video again for further clarification.
Warm regards.
@@OninabResources thank you
Thank You Sir
You are welcome.
Thanks so much
You're welcome!
You're welcome!
Thanks
You are welcome
We have seen what is p as probability of success but we don't know how we seek a number P
Thank you for your feedback.
The value of p is either given in the question or use the information in the question to calculate it.
How did you get 1/4 and 3/4 in the third question
Thank you for your feedback.
There are 4 options for each multiple choice question in which only one option is correct.
Probability of answering each question correctly is ¼ which is equal to p. Probability of answering it wrongly is ¾ which is q. You may need to watch the video on basic problem on probability for further clarification.
Warm regards.
Pls how did you get 1/2 in the first example
How did u get failure 0.2
P(success) = 0.8
P(failure) = 1- 0.8 = 0.2
Success and failure are complementary events and their individual probability sum up to 1.
Pls how did you get p=1/2 and q=1/2
How is 6c4 15
i use a casio fx-82za plus calculator so for me is just put in 6-shift (the devide button which is your C) 4 that will give you 15... hope this helps XD
how is in (b) 6*1/(1/32) is equal to 6/64? it is wrong
Thank you for your feedback.
You may need to watch the video again. What we have in b is 6× ¹/32 × ½ which gives 6/64.
Warm regards.
How did you derive 6 combination 5 to be 6?
Thank you for watching.
We appreciate your feedback. You can input 6C5 in your calculator.
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Sir pls how did you get you success (p) and failure (q) in question 2&3 its confusing
He got 1/2 from the sides of a coin (head and tail)
how did you get 1/2??
In the examole 2, 2/3 to the third is 2/27, not 8/27. Reputability check. Unless my calc has got an internal issue.
(2/3)³ = 2³/3³ = 8/27 sir.
Change your calculator or check your input.
Thanks sir
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Moral is good
Thanks bro
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How you came out with 1 half and the rest
I don't know how get the 0.2 but u are doing very well
q is obtained by the equation (1-p), so p is 0.8 hence (1-0.8)=0.2
@@sheriweri thank you
3:49 how do u get 1/2
A coin has two faces, head(H) and tail(T).
p = Pr(H) = ½
q = Pr(T) = ½
Please watch the video below for further clarification.
ruclips.net/video/Z49J9lLCtm4/видео.html
❤❤❤❤❤
Pls how is 6c4 =15
recheck Q1
Pls the final answer how do we do it
Pls how can I get the failure
You just have to think of a number that will make the number of success whole or complete.
For example, u were given a success or (p) of 2/5 then think of a number that will make 2 a 5 and that is 3. So, your failure or (q) is 3/5
Okay of this one
p: it rains
q: there will be flood
Sorry at least 5 it supposed to be 0,1,2,3,4,5
Consult with your English teacher for more clarification on at least and at most. Thank you.
At least means the smallest figure should be 5 which implies that it's only 5 and 6.
This is for at most 5 not at least 5
@@OninabResources u should have just corrected him, instead of saying that. What is the essence of being the teacher?
John M Sesay
Thank you so much for your feedback.
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Yeah
Good but too long solutions ..
oh i got it now
recheck Q1