Lag Operator & AR(p) Stationarity

[@henriquefbarbosa]

really good stuff. thanks for your work

[@economaths]

Thank you, I am glad that you found it useful.

[@KarriemPerry]

Very useful lecture.

[@kennethmutwiri1045]

great work. Very helpful

[@mustafizurrahman5699]

Too good. Thank you very much sir

[@leoraivonen7992]

Thanks a lot! great and clear teaching!

[@ratnaabhishekmamidi80]

Super explanation.

[@lexparsimoniae2107]

This is fantastic. Thank you!

[@enceladusbg]

17:49, you say (1-L)^-1 = 1 + L + L^2, but that geometric series doesn't converge like that since lambda_2 = 1.

[@economaths]

(1-L)^{-1} or any function of L isn't actually a polynomial function in L. But it will behave the same way, if you take (1-L)Y_t=e_t and keep recursing back, it will expand out the same. Y_t=Y_{t-1}+e_t can be expressed as all past lags going back forever, which in lag operator form is (1+L+L^2+...)e_t

[@franklv370]

very clear and helpful!

[@theinstigatorr]

Love you great stuff mate

[@GurukulWisdom]

Thanks bro for this Tutorial.

[@alexcrescentini9154]

thank you!

[@jeffreyanderson5333]

missing the exciting part with complex roots.