Square root of 24 over 2 + square root of 12 over 2 = ? Basic Algebra Math!
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- Опубликовано: 1 окт 2024
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Thanks, Math Man. I'm 80 years old with an undergraduate degree in math. I taught statistics in graduate school. My career took me away from anything but basic math or Excel did it. I enjoy relearning basic math. Thank you.
I rearranged it to get 2 x 12^0.5 = 24^0.5, which obviously is'nt so, so incorrect
Yeah, I have no idea why he didn't just do that. All his factoring out the square roots is so unnecessarily cumbersome.
No. You don't multiply inside the square root when creating equivalent fractions.
Lets look at the numerators first and simplify them down:
(2√6) / 4 + (2√3) / 2
I can reduce the first term further:
(√6) / 2 + (2√3) /2.
Both denominators are now the same and we can NOT add the numerators together so we "combine" them into two parts. This means the answer is:
(√6 + 2√3) / 2
Note that ( ) is used to show that everything is divided by 2
got it NO factor not combine. thanks for the fun.
The last time I did algebra was 1958, it’s starting to come back a little
JIM 🤩
There's no algebra in this video. Which is weird, because he mentions it in the description, and you COULD solve it very quickly with a bit of simple algebra but he goes about it a completely different way.
Yay, I got it right! I left my engineering school 40 years ago to follow my dream of being a Chef. Shoulda stuck with engineering.
Well, the answer to the first is 2.9567956789604663426260883788588.
and the second is 2.4494897427831780981972840747059
So no. presuming that the upper 2 and lower 4 divide out to be sq rt of 24 /2. But I forgot this stuff sixty years ago.🙄
That's the engineer's approach. Reduce it to hard numbers and compare.
V24 = 2V6 V12 = 2V3 so the answer is 2V6 / 4 + 2V3 / 2 = V6 / 2 + V3
Convert Sqrt integer to prime and then nonprime factors, and simplify the three radicals to a comon denominator.
Eq1: Sqrt(24)/4❓
= Sqrt(2*3*4)*1/4
=Sqrt(2*3)*2/4
=2*Sqrt(6)/4
=1*Sqrt(6)/2 ✅
Eq2: Sqrt(12)/2❓
=Sqrt(3*4)/2
=Sqrt(3)*2/2
=2*Sqrt(3)/2✅
Eq3: Sqrt(24)*2/4❓
=Sqrt(2*3*4)*2/4
=4*Sqrt(6)/4
=2*Sqrt(6)/2✅
Eq1 + Eq2. = Eq3
Sqrt(6) + 2*Sqrt(3) = 2*Sqrt(6)
-----------------------------------------------✅
2
If you wanted, you could break the radicals from the common denominator:
Sqrt(6)/2 Sqrt(3) Sqrt6)✅
Eric
1/2 sqrt 6 + sqrt 3
Another way to solve this problem is to reduce the fraction on the left giving us (✓6/2) + (2✓3/2) which simplifies to (✓6 + 2✓3)/2.
Uh, I think that last square root should be sqrt(3)
@@keithharbaugh2594 You're right. Thanks for catching that.👍
I ended up factoring the result to: √3(√2 + 2) / 2 I believe that's an equivalent answer?
I initially ended up with the square root of 6 times (1 + square root of 2)/2 and then manipulated that to get your answer.
9/2 I think 🤔 but I just did this quickly in my head. Let’s see. I’m at 0:47 now.
Thank you
[sqrt(24)/4]+[sqrt(12)/2]
=[sqrt(24)/4]+[2sqrt(12)/4]
=(1/4)[sqrt(24)+2sqrt(12)]
NOTE
sqrt(24) = sqrt(2×12)
ALSO
2sqrt(12) = sqrt(4×12)
SOLVE FOR...
AND
sqrt(12) = sqrt(3×4)
= 2sqrt(3)
=(1/4)[sqrt(24)+2sqrt(12)
screw it
=(1/4)[sqrt(24)+2sqrt(12)]
=(1/4)[sqrt(24)+sqrt(48)]
=(1/4)[sqrt(24)+sqrt(2)sqrt(24)]
=[sqrt(24)/4][1+sqrt(2)]
=[sqrt(24/16)][1+sqrt(2)]
=[sqrt(3/2)][1+sqrt(2)]
=sqrt(3/2)+sqrt(3)
=sqrt(3)[1+sqrt(1/2)]
S h e e s h.
The use of 24 and 12 sort of convinced me I would be able to find a common root to then add together.
I eventually arrived at John's answer but was sure I was wrong .
√12 / 2 is 2√12 / 4, so the expression on the left is equivalent to
(√24 / 4) + (2√12 / 4)
which is
(√24 + 2√12) / 4
That would only be equal to 2√24 / 4 if 2√12 equalled √24. Which it does not. So no, the equation is not correct.
But why does the video description call this basic algebra??? There's no algebra here!
Greetings. No. 2(24^1/2)/4 =6^1/2. The actual answer is
(6^1/2)/2+3^1/2 or
((6^1/2+2(3^1/2)/2. Lovely.
I can remember taking this in school and I can also remember not understanding it. This, made it a little easier to understanding it. I'm going to have to rewatch again.
I didn’t solve it in my head but your proposed answer was clearly wrong.
👍👍👍
No
The answer to the title is ‘no’. I’ll skip the roots🤪. 2/4is 1/2, so no, the answer can be simplified. Let’s watch 🤓and yes this comment is counter to the purpose of the vid. I.e. take out the most obvious first step answers. Unless, a teacher wants to be tricky, which I would generally not appreciate unless it was discussed in class before.
This seems to be a video about factoring square roots and combining fractions. Nothing wrong with that as a topic in general, but it's weird here. Firstly because that's a very cumbersome way to go about solving this particular problem, and secondly because the video description says this is algebra yet there's no algebra in the video (despite the fact that you can solve it quickly and easily with a bit of simple algebra)
The algorithmic method
Great tips! Great posts!
Oops
No
No.
Yes
No. 2 x 3^(1/2)
5 imaginary squared is -25 not -5
You commented on the wrong video.
No simply put the first fraction simplified is 2✓6/4 the second is 2√3/2 cancelling common factors gives us √6/2+√3/1 at which point you can't combine them