Sir I think the integration is wrong.. 1/(ax+b)^2(bx+c)=A/(ax+b) +B/(ax+b)^2+C/(bx+c).. Moreover the rate expression is -dx/dt =k(a-2x)^2(b-x) Why don't you consider the negative sign? If I am wrong please excuse me..
this derivation is not correct. I wasted an hour following this procedure and in the end answer wasn't correct. You made a mistake while dissolving the partial fraction
Thanks sir....pichli video ki tarhaa yee b bhaot zabrdast h
Sir
I think the integration is wrong..
1/(ax+b)^2(bx+c)=A/(ax+b) +B/(ax+b)^2+C/(bx+c)..
Moreover the rate expression is
-dx/dt =k(a-2x)^2(b-x)
Why don't you consider the negative sign?
If I am wrong please excuse me..
Sir, Is the moleculararity and order of a
reaction are always same for for a complex chemical reaction
No
Sir please plot graph for this particular case too. I can't find it anywhere.
Greeting can you explane How you take px+q and 2 ?
Sooo good
Hindi m videos bna do
Yes, the rate expression is wrong. This thing confused me.
Hello sir
Hello
You put wrong value of q in integration
this derivation is not correct. I wasted an hour following this procedure and in the end answer wasn't correct.
You made a mistake while dissolving the partial fraction
Can you send me correct derivation?
Incorrect