Quantity of sewage in combined sewer Problem | numerical in waste water engineering | sewer problem

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  • Опубликовано: 4 ноя 2024

Комментарии • 7

  • @RAGGIL-SAHILYA
    @RAGGIL-SAHILYA 10 месяцев назад

    A town has a population of 1,50,000 persons with per capita water supply
    of 200 litres/day. Assuming 85% of water usage is appears to be sewage,
    design a sewer running 0.7 times full at maximum discharge. Take a
    constant value of N = 0.013 at all depths of flow. The sewer is to be laid at
    a slope of 1 in 500. Take a peak factor of 3.

  • @subhadominator
    @subhadominator Год назад +2

    Anna .... a town has a population of 100000 persons with a per capita water supply of 200 Lpd . Design a sewer running 0.7 times full. take n=0.013 and slope 1 in 500 and peak factor of 3. assume 85% of water supply turns into sewer. .....intha sum ku answer venum na Anna .. pls Anna

    • @aamirahmed7404
      @aamirahmed7404 Год назад +1

      Step 1: Determine the total water supply to the town per day:
      Total water supply = population * per capita water supply
      Total water supply = 100000 * 200 = 20,000,000 Lpd
      Step 2: Determine the amount of water that will turn into sewer:
      Water that turns into sewer = 85% of total water supply
      Water that turns into sewer = 0.85 * 20,000,000 = 17,000,000 Lpd
      Step 3: Determine the peak flow rate using the peak factor:
      Peak flow rate = Peak factor * Average daily flow rate
      Peak flow rate = 3 * (Water that turns into sewer / 24)
      Peak flow rate = 3 * (17,000,000 / 24)
      Peak flow rate = 1,275,000 Lph (liters per hour)
      Step 4: Determine the diameter of the sewer pipe using the Manning's formula:
      Q = (1.486/n) * A * R^(2/3) * S^(1/2)
      where:
      Q = flow rate (m3/s)
      n = Manning's roughness coefficient
      A = cross-sectional area of the pipe (m2)
      R = hydraulic radius of the pipe (m)
      S = slope of the pipe (m/m)
      Since the sewer is running 0.7 times full, the cross-sectional area of the pipe will be:
      A = Q / (0.7 * V)
      where V is the velocity of the flow in the pipe. We can assume a velocity of 0.75 m/s.
      A = 1.275 / (0.7 * 0.75) = 2.427 m2
      Assuming a circular pipe, the diameter can be calculated as:
      d = sqrt(4A/π) = sqrt(42.427/π) = 1.77 m
      Therefore, a sewer pipe with a diameter of approximately 1.77 meters should be used to carry the peak flow rate of wastewater in the town.

  • @arnav_srivastava
    @arnav_srivastava Месяц назад +2

    Why are you multiplying with 1/36 in rational formula?

    • @abhishekkumar0397
      @abhishekkumar0397 Месяц назад

      Full tyari kar rha hai kya bhai🤣🤣🤣

    • @arnav_srivastava
      @arnav_srivastava Месяц назад

      @@abhishekkumar0397 Bhai bhai 😂😂

    • @arnav_srivastava
      @arnav_srivastava Месяц назад

      @@abhishekkumar0397 reason pata hai to bata do Bhai 😂