Clinical refraction 4 │How to start performing retinoscopy

A practical approach to start performing retinoscopy is discussed with the help of the AAO online retinoscopy simulator

[@manchikantivijayakumari9906]

Thank you so much mam for teaching us refraction procedure. I follow your videos they are very helpful.

[@psh_yo]

Excellent video... Very easy to understand..

[@Hasan-pt9wr]

This was really very helpful

[@i.g.304]

incredible video.. thanks a lot

[@user-nf1vx2rh8b]

Good and easily catching method

[@RR-sv7gz]

Excellent video

[@ansarma659]

Thank you so much mam💘

[@dmdyahiya214]

Thank you mam

[@abhijitha4604]

Is rectinoscopy accurate maam?

[@sudhirdhyanidhyani9262]

Best

[@ARAV-bd4rh]

Ma'am , can you make video about subjective refraction.

[@ophthalmologypearls]

Sure thing

[@Traveller530]

If we are moving streak up & down , we are correcting 90 meridian?

[@ophthalmologypearls]

By moving the streak up and down (in vertical meridian), we are determining the refraction in the vertical meridian

[@Traveller530]

@@ophthalmologypearls thank you for your response, got it.
I have another question.
When we do ret on model eye with dummy lens. Let’s say I got reversal in 90 meridian which mean I got reversal at vertical and aganist in horizontal 180 meridian. My ques is that when adding negative cyl in which position do I need to put axis of cyl?

[@ophthalmologypearls]

Let me get this straight. I think you mean - After reversal and subtracting for distance and cycloplegic drug, you get a plus power in the vertical meridian & a minus power in the horizontal meridian. So if you want to put a negative cylinder (minus cylinder), we want that minus power in the horizontal meridian. We know that cylindrical lenses have their power perpendicular to their axis. So a negative cylinder has to be placed with its axis at 90°, for the effective minus power to be available horizontally

[@user-xn5mh5vr5q]

🌹💚