An entire year of AP Physics C... and this made so much more sense than anything my teacher ever said. Hopefully now I actually pass the AP exam tomorrow!
Im a college student in physics at the moment and your tutorials are immensely helpful. I cant stomach the textbook nor my professor, but this makes it so easy to grasp
Just learned torque yesterday in AP Physics and I felt like I was really stupid after that lesson. I got a B/A in our school’s Honors Physics(which everyone says is the easiest honors science class at our school ) and that made me really sad. I thought I am maybe too dumb for science and stem especially because I haven’t gotten any As in science since my freshman year(it was online). Maybe I’m still too dumb for AP Physics but after watching your video I have a little confidence that I will be able to ace our unit test and the AP Test as well.
thank you so much for this! I will definitely be using your videos now for every chapter =) I started searching youtube out of desperation, but thank goodness I found this!
Hi Excellent explanations and videos as usual, couple of typos - when describing the Right Hand Rule the Slide says: "Your thumb then points in the direction of your thumb" (should be torque vector). Also with the tortoise and hare the downward force should be 98N and 19.6N respectively whereas it shows 10g and 2 g
Yes, I did misspeak with regard to the right hand rule. I'm good with the tortoise and hare slides, though, with 10g and 2g illustrating where 98N and 19.6N comes from.
@@warrenziegler4695 Understood, but there are occasionally trade-offs made in making the videos. I could have written that as 10kg*g and 2kg*g, or 10kg*9.8m/s^2, etc., but in the interest of space my judgment call was to go with the 10g and 2g. I agree there may be solid debate on other ways to go about it, depending on where your students are and what you're focusing on, but I wouldn't call that a typo, but maybe an area where you would have taught it differently. :-) Thanks for the input!
So we can imply that the acceleration of the mass m equals the tangential acceleration of the pulley? Can this be solved by using the angular acceleration alpha and the relation a = R*alpha?
It's in there. Look at the green free body diagram in the upper left. Since it's applied at the center of the pulley and not at any distance from the point of rotation, however, it adds no net torque.
It's not rotating about its midpoint, its rotating about its end. I could have also done a derivation of the rod about its end, or just memorized it, but I figured this was a good opportunity to review the parallel axis theorem. For more information on this one, watch the video on moment of inertia!
An entire year of AP Physics C... and this made so much more sense than anything my teacher ever said. Hopefully now I actually pass the AP exam tomorrow!
Glad you like them... AP-C Physics is tough the first time through -- hang in there!
Im a college student in physics at the moment and your tutorials are immensely helpful. I cant stomach the textbook nor my professor, but this makes it so easy to grasp
Thrilled to hear you're enjoying the videos!
Glad you like them, and you're welcome!
These videos help out a lot when I'm confused, they are clear and explicit. Keep up the good work!
Glad you liked it. Unfortunately, I can't e-mail it to you (way too big), but you can watch it here to your heart's content!
Yes. I'm a full-time high school teacher, and an adjunct engineering professor.
Saved my life. Had an AP Physics test, thank you
Cristopher Guzman Hope the test went well!
Best of luck to you, and feel free to share with students taking physics next year!
Just learned torque yesterday in AP Physics and I felt like I was really stupid after that lesson. I got a B/A in our school’s Honors Physics(which everyone says is the easiest honors science class at our school ) and that made me really sad. I thought I am maybe too dumb for science and stem especially because I haven’t gotten any As in science since my freshman year(it was online). Maybe I’m still too dumb for AP Physics but after watching your video I have a little confidence that I will be able to ace our unit test and the AP Test as well.
Hi Justine. The video on "Moment of Inertia" should help answer your question.
thank your all videos I am gonna have AP physics C tomorrow
Good luck on your exam!
thanks
Glad to hear it helped!
Thank you! This is great for reviewing and you make it simple! Perfect for a slow physics student like me
Good luck and have a blast!
My pleasure!
Dan... these videos are extremely informative and logical.. wonderful review for a 3 unit AP Physics C test..
+Joe Kulikowski Good luck on your exam!
+Dan Fullerton (APlusPhysics) thank you!
thank you so much for this! I will definitely be using your videos now for every chapter =) I started searching youtube out of desperation, but thank goodness I found this!
Thrilled to hear it's helping you out!
it’s been 7 years since this comment what are you currently doing in life?
you're the man dan fullerton
your videos are fantastic. Thanks for the help!
You are such a nice person!!! Thanks for helping me learn to love physics :D
Wow, that just made my day, thanks!
Hi Excellent explanations and videos as usual, couple of typos - when describing the Right Hand Rule the Slide says: "Your thumb then points in the direction of your thumb" (should be torque vector).
Also with the tortoise and hare the downward force should be 98N and 19.6N respectively whereas it shows 10g and 2 g
Yes, I did misspeak with regard to the right hand rule. I'm good with the tortoise and hare slides, though, with 10g and 2g illustrating where 98N and 19.6N comes from.
@@DanFullerton Yes but to be picky 2g and 10g looks an acceleration rather than a force
@@warrenziegler4695 Understood, but there are occasionally trade-offs made in making the videos. I could have written that as 10kg*g and 2kg*g, or 10kg*9.8m/s^2, etc., but in the interest of space my judgment call was to go with the 10g and 2g. I agree there may be solid debate on other ways to go about it, depending on where your students are and what you're focusing on, but I wouldn't call that a typo, but maybe an area where you would have taught it differently. :-) Thanks for the input!
hmmm just a question on the beam question, why there is no torque?
this cleared my concepts .thanks sir a lot .you re damn good
Thank you SO much, you're a life saver!
When it comes to Torque, why exactly do we define it as a vector and not a scalar? What is the meaning of its direction?
Btw at 2:38 your slide I think mistakenly says your thumb then points in the direction of your thumb.
how does the fulcrum apply a force? Is it distributed using trig functions?
+Ethan Chapman I'm not sure I understand the question... can you elaborate?
So, is torqued considered a force? Or is it a measure of like how much a force will cause something to rotate?
Torque is different from a force, though it is in many ways the rotational equivalent of a force.
So we can imply that the acceleration of the mass m equals the tangential acceleration of the pulley? Can this be solved by using the angular acceleration alpha and the relation a = R*alpha?
Absolutely you can use a=R*alpha!
sir..what to do about mobiles? is this gonna help?
whats the equation for equilibrium of 3 beams?
For the pulley with mass ... what happens to the normal force of the pulley, you did not have add in your solution..
It's in there. Look at the green free body diagram in the upper left. Since it's applied at the center of the pulley and not at any distance from the point of rotation, however, it adds no net torque.
Hey do you teach in high schools or universities?
im about to take honors physics for my last year of school
Can dynamic equilibrium also imply no net torque but constant angular rotation? Does it have to include no net force and constant linear velocity?
AuthenticKaiser It does, otherwise it would just be in rotational equilibrium.
For the beam problem, why is the lever arm L/2?
Because the weight acts on the center of mass which is at L/2 or half the length of the beam
@@HHhhh-yf9ji thx
why is it that I=1/2mr^s?? i thought its I=mr^2
Why isn't the moment of inertia for the lever on the wall problem 1/12... Why did you have to use the parallel axis theorem?
It's not rotating about its midpoint, its rotating about its end. I could have also done a derivation of the rod about its end, or just memorized it, but I figured this was a good opportunity to review the parallel axis theorem. For more information on this one, watch the video on moment of inertia!
No, you are! ;-)
Thanks -- working on Thermodynamics as I type...
time to go ace the physics test tomorrow =D
Good luck!
sorry i got it thanks ya ! =D
Twerk Vector :D
Quentin Johnson I cannot un-hear it now...