Linear Algebra: Orthogonal Projections and Orthonormal Bases (Full Lecture)

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  • Опубликовано: 16 ноя 2024

Комментарии • 26

  • @harshthebestcoolice4675
    @harshthebestcoolice4675 8 месяцев назад +2

    Thank you for posting this, helps with my college linear algebra class in terms of actually understanding the material.

    • @DrValerieHower
      @DrValerieHower  8 месяцев назад

      You are welcome. Thank you so much for the feedback!!

  • @ahmadsharifian
    @ahmadsharifian 3 года назад +4

    Tnx alot Dr. Hower
    I'M MS. Student at Computer Science minor Datamining.
    Your teaching in so useful funny and I'm not bored never ever to study your teaching
    I hope you will record more and more lecture for us
    Ahmad

    • @DrValerieHower
      @DrValerieHower  3 года назад +1

      thank you so much for your feedback :)

  • @thabolikotsi5765
    @thabolikotsi5765 4 года назад +2

    You are such a brilliant teacher I'm so glad and lucky I found you

    • @DrValerieHower
      @DrValerieHower  4 года назад

      Thank you so much!

    • @thabolikotsi5765
      @thabolikotsi5765 4 года назад

      @@DrValerieHower Yeah and I love how unique you are as a person and I love your tattoos I'm so honoured you took your time I'll ace linear algebra in 2021 thanks to you❣❣😇🎓I also want to be a professor one day

  • @vaguelyneeraj-18.
    @vaguelyneeraj-18. 7 месяцев назад +1

    thank you ma'am .... finally my doubts cleared 😀😀

    • @DrValerieHower
      @DrValerieHower  7 месяцев назад

      You are welcome! Thanks for the feedback.

  • @digantamajumder2599
    @digantamajumder2599 4 года назад +1

    Thanks, mam for this fascinating lecture!

    • @DrValerieHower
      @DrValerieHower  4 года назад +1

      You are welcome and thank you for your feedback.

  • @bongakhongota8226
    @bongakhongota8226 3 года назад +1

    Thank you Dr.. I really enjoyed the lecture

    • @DrValerieHower
      @DrValerieHower  3 года назад +1

      You are very welcome. I appreciate the feedback

  • @rebeccajin2973
    @rebeccajin2973 2 года назад

    Do you mind posting your notes packets as well in the description? Love to get some extra practice!

  • @yoshithaabalaji1278
    @yoshithaabalaji1278 3 года назад +1

    Thanks a lot Mam!

    • @DrValerieHower
      @DrValerieHower  3 года назад

      You are welcome. I appreciate the comment.

  • @climitod8524
    @climitod8524 6 месяцев назад

    Hi at 59:11. Why are we writing the matrix with rows as opposed to columns like we usually do?

    • @DrValerieHower
      @DrValerieHower  6 месяцев назад

      In this example I am discussing orthogonal complement. if V is the span of a collection of vectors. and we want a basis for the orthogonal complement of V, we can put those vectors as rows of a matrix M and find a basis for ker(M). that is what I discuss here.

  • @Marco-xn2sg
    @Marco-xn2sg Месяц назад

    In the last question, where we find a basis for the orthogonal complement, why do we need a vector in R3 pls? I thought it would go from R4 to R4?

    • @DrValerieHower
      @DrValerieHower  Месяц назад

      I believe you are asking about the example when I have V is the span of 2 linearly independent vectors in R^3. The orthogonal complement will be a 3-2=1 dimensional subspace of R^3. I am not sure where your reference to R^4 is coming from. Thank you.

  • @dtonysun
    @dtonysun Год назад

    Thank you for this lesson. Quick question: for the example finding "orthonormal complement", the first one for instance, couldn't we just "solve for kernel" and put [1 3 1 -1] as a column, so it becomes 4x1 matrix waiting to be reduced? but I guess it's not making sense yet...

    • @DrValerieHower
      @DrValerieHower  Год назад +1

      Hi. If you have a 4x1 nonzero matrix (meaning 4 rows and 1 column), this will be a rank 1 matrix. Its kernel will be the 0 subspace sitting inside the real line. To find the orthogonal complement of the span of (1,3,1,-1), we would put this vector as a ROW and solve for the kernel of that matrix. I believe this is what I discuss towards the end of this video. thank you.

    • @dtonysun
      @dtonysun Год назад

      @@DrValerieHower Got it, thank you - I was aware of putting this vector(s) as a Row, but I didn't understand it yet. By definition, 'orthogonal complement' is Ker(T), and I recall previously when solving for kernel, the basis vectors were put into Columns instead. Here also, I'm thinking the span of one single vector is a line in the space. That said, too many things covered and I couldn't get it all yet!

    • @DrValerieHower
      @DrValerieHower  Год назад +1

      @sndme by definition, the orthogonal complement of a subspace is the set of all vectors perpendicular to every vector in the subspace. Here are my current notes on this section (a bit different than the video) if this helps: drive.google.com/file/d/1mVAWCDhH7KydN5RLkUKz7F1VcpqSA9nH/view?usp=sharing

  • @mayrajloredo87
    @mayrajloredo87 2 года назад

    Which of your videos is sect 4.1linear spaces in the book?

    • @DrValerieHower
      @DrValerieHower  2 года назад

      Thank you for your question. In the current syllabus, we do not cover chapter 4 at Northeastern. So, I do not have videos on it. Some professors may teach it here if they have time in the schedule, but I have not yet had time for this chapter.