You are a blessing, you’re videos manage to get me from an E to a B at the end of AS, and I’m finding a-level so much easier now thanks to your videos!!
Thank you so much for the video sir, It's an Absolute Life Saver. However I just have one doubt If you dont mind clearing up. At 1:22:29 Why is Dissociation of the Salt an equilibrium, Isn't it Fully Dissociating so It just be an Arrow point to the right. I'm Most probably wrong but it would be helpful if you could clear it up. Thanks alot
1:04:08 How here in weak acids you are saying that [H+]=[acid] isn't that only applies to strong bases and acids whereas the weak acids we use the Ka like u have explained in your slide in the green box in 34:38 ? Plz help :) But thanks soo much for your video and for your massive hard work , your videos help me to a great extent :)
Not the hero we deserve, but the hero we need
You are a blessing, you’re videos manage to get me from an E to a B at the end of AS, and I’m finding a-level so much easier now thanks to your videos!!
You're very welcome!
I was on a c last year in chemistry and now I am achieving A and high a stars I couldn’t have done this without you
thank you so much , these videos are incredibly helpful as i'm learning chem a2 alone.
same
What did you get?
awesome video.easily understood buffers and you made these things look very easy. thank you!!
All credits to you if in my upcoming A2 exams i get an overall A
So um what did you get? 👀👀👀👀
@@yourleftkidney he got a U
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Thank you so so much I don’t think you understand how beneficial these videos are.
Happy to help!
at 29:00 isnt the conc of H+ ions = 2 x conc of acid instead of conc of acid = 2 x conc of H+ ions?
Your videos are amazing, they are incredibly helpful!!! Thank you
Glad you like them!
u are an absolute legend.
Thank you very much Mr Harris. These are very very useful indeed. I hope you are well.
You are very welcome
Thank you so much for the video sir, It's an Absolute Life Saver. However I just have one doubt If you dont mind clearing up. At 1:22:29 Why is Dissociation of the Salt an equilibrium, Isn't it Fully Dissociating so It just be an Arrow point to the right. I'm Most probably wrong but it would be helpful if you could clear it up. Thanks alot
same question
how may i express my thanks. this is amazing
Thank you so much!! I always use your videos, so helpful.
You're welcome 😊
Thank you so much for all these videos
You are so welcome!
Your my idol. Seriously video helped so much!
cant thank u enough for ur hard work
You're very welcome! 😀
Mr Harris you are an angel :)
at 41:05 shouldn't the answer for the concentration of methanoic acid be 2.96x10^-11 moldm^-3 instead of 2.96x10^-3 moldm^-3
About to go on a journey night before my exam
Hope it goes well! 👍
you are 'The Best' !!!!!
Can you make vidoes of worked solutions of recent past papers of edexcel ial chemistry unit 4,5 and 6?
You are a legend! I'm gonna ask all my friends to sub you
I think at around 1:50:00 there's a typo - methanoic acid only has HCOOH, not CH3COOH - but it doesn't matter for the calculations right?
thank u
Wow this was helpful
Thank you very much sir
thanks
1:04:08 How here in weak acids you are saying that [H+]=[acid] isn't that only applies to strong bases and acids whereas the weak acids we use the Ka like u have explained in your slide in the green box in 34:38 ? Plz help :) But thanks soo much for your video and for your massive hard work , your videos help me to a great extent :)
yeah i was stuck here too, what would you say, would you say that [H+] = sqrt(Ka * [Acid] to rearrange for H+?
1:05:04
cheers mate
legend bruh
my goat
the ads kinda ruin it but otherwise good job
Not his fault