Enroll into the Power Prep Week Grade 9🔥 : Master MOST REPEATED questions from India's TOP SCHOOLS' question papers with our YT Teachers LIVE🔥 Click on the Link Below 😍 shop.byjus.com/products/power-prep-week-exam-crash-course-grade-9?
Why do u guys always keep.on promoting your institute ?? Padhate kam hoo bakwas zyada karte ho baccho ke parents ko manipulate karte rehte hoo ki hum aapke bacche ko analyse karenge etc.. pu6e bina kabhi bhi hamare ghar ghus jaate ho bas ek baar no.. mill jana chahiye to din me 1000 bar call krte rehte ho magnate ki tarah bas chipak hi jaate ho !!!!!!!! Pls change your policies otherwise I am sure I will be the one who will ban this rubbish institute of yours in future........
Thank you 🙏🙏❤🙏🙏 so much mam for the session. I really enjoyed the session 😍🙂. Homework: - Cords DC Subtented angle DBC and DAC ,Both Will be equal ( Angles in the same Segment are Equal Theorem 9.8 ) that is 55° , As ABCD is a cyclic Quadrilateral therefore Angle A + C =180, that is Angle DAC (55°) + Angle BAD (45°) + Angle BCD =180° , 55°+45° +Angle BCD =180° 100°+ Angle BCD =180° Angle BCD =180°-100° =80° Hence,Angle BCD =80° Answer. Thanks 🙏🙇 A lot Mam. 🙏🙏❤🙏🙏🙂🙂.
Home Work Question-> Mesure of Angle BCD=80° Thank You Mam for this class, I liked it alot even though, it was a bit long than usual classes and Questions were tricky... Excited for next class...
Mam, inex9.2 ,1st problem, They given that distance btn two centers is 4cm ,how can u take center of second circle is out side of first circle ,then the distance between two centers will be more than 5cm
THANK YOU MAM FOR IS AMAZING SESSION 😊😊😊 HW ANS: Given:angle DBC=55°,angle BAC=45° to find=angle BCD PROOF =If DC is the chord then,angle DBC =angle CAD=55° (angle in the same segment are equal) Angle DAB=45°+55°=100° Also, In an cyclic quadrilateral opposite angle are supplementry Therefore,angle BCD=180°-100°=80°
Thanks mam for this amazing session 😌💕 HOMEWORK QUESTION :- angle DBC =angle CAD(Angles in the same segment) angle CAD=55° angle DAB = angle BAC+ange CAD angle DAB =45°+55° =100° Since ABCD is a cyclic quadrilateral angle DAB +angle BCD= 180°(opposite angles of cyclic quadrilateral are supplementary) 100°+angle BCD =180° angle BCD =180°-100° angle BCD =80°
Mam, in q8, can’t we say that the trapezium is a parallelogram since opposite sides are parallel and equal? And since it’s a parallelogram, opp. sides would be supplementary?
Angel dac,=angle dbc=55degrees(angles made by the same chord of a circle are equal.) So, angel BCD= 180-100=80degrees.by cyclic quadrilateral theorem which tells opposite angles of a cyclic quadrilateral are suplementary. 🎉❤mam I didn't listen the but I know this chapter very well.
Mam my class teacher solved the question no.1 of exercise 9.2 by another method We should draw the figure then, (5)ka square=(3)ka square+(4) ka square 25=9+16 25=25 Hence, it is satisfied Pythagoraes theoram so angle C = 90° Since we know that the line 1 or from centre to chord AB bisects the chord. AB=2×3=6 cm Mam , does this method was right 👍
Long live the Byju's Learning App. All the best for successful days ahead. We miss your services in the form of customer care call & mentor. Only online classes are there now as the Premium app installed in the tab was not responding due to its updation. We unfortunately uninstalled it too😞😔😔😟
HW ANS: Given:angle DBC=55°,angle BAC=45° to find=angle BCD PROOF =If DC is the chord then,angle DBC =angle CAD=55° (angle in the same segment are equal) Angle DAB=45°+55°=100° Also, In an cyclic quadrilateral opposite angle are supplementry Therefore,angle BCD=180°-100°=80°
Hiii ma'am thanks for the session really amazing🎉🎉 enjoyed it and it's makes the better sense of🎊🎊⭐ understanding all the things thanks a lot ma'am 🥰 Homework questions ansewer : angle :- BCD =80 degrees
Mam ek doubt in 1:31:59 Can't we use theorem perpendicular from center bisected chord and prove RN = NM instead of proving it congruent pls Clarify mam
Home work question answer is 45 degree.. Mam I really loved the class. Since so many months I am struggling to find a good teacher of maths and finally I found you.. You are indeed great.. Mam thank you so much for being here!!
Mam i have a doubt mam exercise 9.2 me agar o,o se jo ap ne ek line draw keya hai usase mam ek trangle ban raha hai to ham use chord bol sakte hai🙏🙏🙏🙏🙏🙏🙏
Homework question Given : ABCD IS A CYCLIC QUADRILATERAL WHERE ANGLE DBC = 55° AND ANGLE BAC = 45° TO FIND : ANLGE BCD FOUNDATION : ANGLE DBC = ANGLE DAC = 55° {ANGLES IS SEGMENT OF CIRCLE ARE EQUAL THEREFORE ANGLE BAD = ANGLE BAC+ANGLE DAC ANGLE BAD = 55°+45° THEREFORE AMGLE BAD = 100 ANGLE BAD + ANGLE BCD = 180 (ABCD IS A CYCLIC QUADRILATERAL) 100 + ANGLE BCD = 180 THEREFORE ANGLE BCD = 80°
mam in excercise 9.2 ques 5 cant we draw the perpendicular first cause then RN will be equal to NM. and we there wont be any need to prove the triangles congruent
Mam apne bht hard sikhaya hai ye chp kuch smjha nhi aadhe mein hi kitne baar re watch kia tab bhi hamare school mein jaise aap sikha rhe ho uska pura ulta sikhaya hai mein itne ummid se aai thi ki smjh jaega pr nhi smjha or app jo kuch krwa rhe ho bht long method mein hai hamare yaha bht chota karwaya hai mam marks nhi dengi exam mein kal ab kya kru mein 🙁
Enroll into the Power Prep Week Grade 9🔥 :
Master MOST REPEATED questions from India's TOP SCHOOLS' question papers with our YT Teachers LIVE🔥
Click on the Link Below 😍
shop.byjus.com/products/power-prep-week-exam-crash-course-grade-9?
Why do u guys always keep.on promoting your institute ?? Padhate kam hoo bakwas zyada karte ho baccho ke parents ko manipulate karte rehte hoo ki hum aapke bacche ko analyse karenge etc.. pu6e bina kabhi bhi hamare ghar ghus jaate ho bas ek baar no.. mill jana chahiye to din me 1000 bar call krte rehte ho magnate ki tarah bas chipak hi jaate ho !!!!!!!! Pls change your policies otherwise I am sure I will be the one who will ban this rubbish institute of yours in future........
Bhaii byjus is the best institute
@@abcdefgh-wt6iv
@@abcdefgh-wt6ivBhai magate nahi , magnet hai . Spelling mistake 😂😅
Yrr byjus is the best institute 😊😊
@@abcdefgh-wt6ivBhai to tu Mt dekha kr.. tution se pdhle .. free me dekhna bhi h fir complain 😒
Im surprised no one can teach at anypalce home or phone this hard math in easy peasy way, respected mam you are 👍😃🎉 great
Aise ma'am mil jaye to math hamara fav subject ho jaye ❤😂
@@akshorts291 pdh le bhai
Mam hmara schl ma aa jao😂😂.. Actually muja maths pasand nhi hai pr apki video ko dekh kr ; yk-yk question smaj aa gaya.. 🙏🙏Thanku😊
😂😂
Hello kids! Check your understanding of the Circles chapter by answering these 5 quick questions in the form: forms.gle/cJDuDN7q4dqXhNqQ6
Thank you 🙏🙏❤🙏🙏 so much mam for the session. I really enjoyed the session 😍🙂.
Homework: -
Cords DC Subtented angle DBC and DAC
,Both Will be equal ( Angles in the same Segment are Equal Theorem 9.8 ) that is 55° ,
As ABCD is a cyclic Quadrilateral therefore Angle A + C =180, that is Angle DAC (55°) + Angle BAD (45°) + Angle BCD =180° ,
55°+45° +Angle BCD =180°
100°+ Angle BCD =180°
Angle BCD =180°-100° =80°
Hence,Angle BCD =80° Answer.
Thanks 🙏🙇 A lot Mam. 🙏🙏❤🙏🙏🙂🙂.
🤓🤓🤓🤓🤓🤓🤓
Ok
Noobda saala 😂😂
Home Work Question->
Mesure of Angle BCD=80°
Thank You Mam for this class, I liked it alot even though, it was a bit long than usual classes and Questions were tricky... Excited for next class...
All the best for tomorrow's paper🎉🎉😂😂😂😅😅
Mam, inex9.2 ,1st problem, They given that distance btn two centers is 4cm ,how can u take center of second circle is out side of first circle ,then the distance between two centers will be more than 5cm
THANK YOU MAM FOR IS AMAZING SESSION 😊😊😊 HW ANS: Given:angle DBC=55°,angle BAC=45° to find=angle BCD PROOF =If DC is the chord
then,angle DBC =angle CAD=55°
(angle in the same segment are equal)
Angle DAB=45°+55°=100°
Also, In an cyclic quadrilateral opposite angle are supplementry
Therefore,angle BCD=180°-100°=80°
9.2 question 1 ka fig wrong h mam
yes
Yess😢
Mam I am learning from you for the past few days the classes are amazing
Click on timer ➡️4:53 without wasting your time
Thanks mam for this amazing session 😌💕
HOMEWORK QUESTION :-
angle DBC =angle CAD(Angles in the same segment)
angle CAD=55°
angle DAB = angle BAC+ange CAD
angle DAB =45°+55°
=100°
Since ABCD is a cyclic quadrilateral
angle DAB +angle BCD= 180°(opposite angles of cyclic quadrilateral are supplementary)
100°+angle BCD =180°
angle BCD =180°-100°
angle BCD =80°
Homework question :-
Angle BAC = Angle BDC ( angles in a same segment are equal ) .
Consider triangle DBC
Angles DBC + BCD + BDC = 180°
55°+Angle BCD + 45° = 180°
100° +BCD = 180°
BCD = 180° - 100°
Angle BCD = 80°. Ans.
Hats off to you for standing 3:14:44 hours ⌛ staright! Thanks a lot! ❤
*Answer of H.W ques : 80°*
Mam you are super duper us se bhi uper ...,.in maths 😂🎉
Mam exercise 9.2 ka question no 1 ka solution apka wrong hai because vahapar abhi bhi 8x hai to kasa x ka value 0 hogaya 35:34
Yes I also in same doubt
Its 0 = 8x so x=0/8 which is 0
Mam, in q8, can’t we say that the trapezium is a parallelogram since opposite sides are parallel and equal? And since it’s a parallelogram, opp. sides would be supplementary?
Angel dac,=angle dbc=55degrees(angles made by the same chord of a circle are equal.) So, angel BCD= 180-100=80degrees.by cyclic quadrilateral theorem which tells opposite angles of a cyclic quadrilateral are suplementary. 🎉❤mam I didn't listen the but I know this chapter very well.
1:48:10 The meeting point of three medians is known as centroid.
Mam my class teacher solved the question no.1 of exercise 9.2 by another method
We should draw the figure then,
(5)ka square=(3)ka square+(4) ka square
25=9+16
25=25
Hence, it is satisfied Pythagoraes theoram so angle C = 90°
Since we know that the line 1 or from centre to chord AB bisects the chord.
AB=2×3=6 cm
Mam , does this method was right 👍
Hello friends how many are watch this video just before exam
THANK YOU Maam for a fabulous session . You made every question simple and interesting.
Homework :
Taking DC as the chord ,
Long live the Byju's Learning App. All the best for successful days ahead. We miss your services in the form of customer care call & mentor. Only online classes are there now as the Premium app installed in the tab was not responding due to its updation. We unfortunately uninstalled it too😞😔😔😟
Thank you so much mam🥰.. the best explanation ever☺️
Mam when you draw two circles perfectly then the common chord is diameter of the smaller circle i,e radius 3cm, so common is 6cm
HW ANS: Given:angle DBC=55°,angle BAC=45° to find=angle BCD PROOF =If DC is the chord
then,angle DBC =angle CAD=55°
(angle in the same segment are equal)
Angle DAB=45°+55°=100°
Also, In an cyclic quadrilateral opposite angle are supplementry
Therefore,angle BCD=180°-100°=80°
Thank you mam I am 1 in my class
35:35 Mam last me "X"ki value "8"hai apne "0" kyu likha❓❓
Cuz its 0=8x so x=0/8 which is 0 as anything divided by 0 is 0
Hiii ma'am thanks for the session really amazing🎉🎉 enjoyed it and it's makes the better sense of🎊🎊⭐ understanding all the things thanks a lot ma'am 🥰
Homework questions ansewer : angle :- BCD =80 degrees
mam in Ex-9.2-1 can I use herons formula and equal to 1/2bh to find AM. i tried and answer came, so can i use in exam
Mam ek doubt in 1:31:59 Can't we use theorem perpendicular from center bisected chord and prove RN = NM instead of proving it congruent pls Clarify mam
Its not given that ON is perpendicular so we have to prove it is perpendicular first.
mam i don't understand timestamp 1:36:32 because 36 - (5-x)^2 should be 36 - 25 - 5x +x^2
2:48:39
Home work question answer is 45 degree.. Mam I really loved the class. Since so many months I am struggling to find a good teacher of maths and finally I found you.. You are indeed great.. Mam thank you so much for being here!!
TOMORROW IS MY EXAM
Why we have not this type of teacher's in our schools
4:52 class starts from here 😊
Exercise 9.2
16:54
Mam you are best teacher of mathematics subject
Ma'am ap bhut acha padhate no doubt 😊
You are the best teacher in the world 🌍🌍🌍🌍💖
3:14:44 you have told 360-200=160 but the answer should be 10 also if we divide it by 2 it will come 80 not 10 .please solve my doubt
Ma’am your teaching is soooo amazing ❤
at 28:48 it is AM=BM according to CPCT naming is important in CPCT
FABULOUS WORK MAM!I KNOW HOW HARD IT IS TO TAKE A CLASS FOR 3 HOUR STRAIGHT
Mam thank you for your expalnation
You're having amazing talent
Once again Thank you very much mam
Thank you ma'am for clearing my doubts, and for this best video. Ma'am I request you to make a short video on how to find square root
Thanks mam kl exam hai sayad apke vge se pass ho jau ga😅😅😅
Mera aaj he exam😂
Nice mam Pura chapter smajh aagya😮😊
Thanks Mam It is Very Helpfull to me
Thankyou so much ma'am ❤😊 mein math me intrested nhi rehti thi kyunki mujhko samjh nhi aati thi but apka channel mila tab se acchi lagne lgi❤
Thanks a lot ❤
Mam last question which you have give to us
Ans. Angle bcd = 80 degree
Is it correct??
Ma'am you said triangles instead of circles -3:14:25
Ur ears are not proper
Mam thank you so much. You cleared my all doubts ❤
Jai shree ram
Thanks ❤️ ma'am you're thebest teacher 🎉
AM^2 = 25-16 - x^2 + 8x in this how come 8x came question 1 exersice 9.2
Mam i have a doubt mam exercise 9.2 me agar o,o se jo ap ne ek line draw keya hai usase mam ek trangle ban raha hai to ham use chord bol sakte hai🙏🙏🙏🙏🙏🙏🙏
Homework answer
Angle BCD = 80 degree
Pls take me on home work board list
Mam you are my favourite teacher ❤️❤️❤️❤️🫣
great explanation of this chapter tomorrow is my exam thankyou team byjuys
f
Homework question
Given : ABCD IS A CYCLIC QUADRILATERAL WHERE ANGLE DBC = 55° AND ANGLE BAC = 45°
TO FIND : ANLGE BCD
FOUNDATION : ANGLE DBC = ANGLE DAC = 55° {ANGLES IS SEGMENT OF CIRCLE ARE EQUAL
THEREFORE ANGLE BAD = ANGLE BAC+ANGLE DAC
ANGLE BAD = 55°+45°
THEREFORE AMGLE BAD = 100
ANGLE BAD + ANGLE BCD = 180 (ABCD IS A CYCLIC QUADRILATERAL)
100 + ANGLE BCD = 180
THEREFORE ANGLE BCD = 80°
2:44:43 Yes 🎉🎉
Mam how are you taking In Q 5 ex.9.2 . 10x
36-(5-x)² = (RN)²
36-25-x²+10x
Ex 9.2 Q1. Ko ham direct Pythagoras theorem sei prove kar sakte h kya mam??
Plz mam humara school ma aajao plz
Salary ₹95000
Beauty+brain,huge respect for uh ma'am😊
0:18 mam triangles nahi circles
thank you for the amazing class mam
mam in excercise 9.2 ques 5 cant we draw the perpendicular first cause then RN will be equal to NM. and we there wont be any need to prove the triangles congruent
Hi everyone ❤
Thanks maam for nice explanation ❤
I was totally liked and obsessed with this session she taught amazing thanku for this amazing and grateful classs
She looks 10 percent like shargun mehta
Ikr
Great explanation mam all doubts cleared 💖
The first teacher of maths, i liked ❤
Yrr kyi saare log ptani kis kis ka naam le rhe hai me to paper se 5 din phele khol rha huu😅😅
Mam apne bht hard sikhaya hai ye chp kuch smjha nhi aadhe mein hi kitne baar re watch kia tab bhi hamare school mein jaise aap sikha rhe ho uska pura ulta sikhaya hai mein itne ummid se aai thi ki smjh jaega pr nhi smjha or app jo kuch krwa rhe ho bht long method mein hai hamare yaha bht chota karwaya hai mam marks nhi dengi exam mein kal ab kya kru mein 🙁
30:20 , AOBO' is a kite so diagonals bisect at 90°
Can we just mug up the answer for this chapter only or ( geometry chapters)
Comment section community pls help
BCD =80. thank you mam for this live class i have understood all the chapter
Mam you are the most lovely ❤ and best teacher ❤❤
Best teacher of maths
Thanku mam💯 👩✈️
Thanks for O like
Your welcome
You taught very well❤
Best teacher
We can also do Q -1 and Q-5 pf ex-2 from very small method of equilatetal triangles a+b+c/2 and s formula
Third side is not given in Q 1
Queshan 1 to 9.2 ke answers ne samj nahi aye
80
Best Maths teacher ever❤
Mam todays class was very nice👍👍👍❤❤
Mam can we do this problem by directly taking 📐 ONR and 📐 ONM
Hey byjus! CAN U PLS DO A VIDEO OF HERON’S FORMULA
EX 12.2 (old ncert book)
It would be helpful for me cuz my board has this ex added yet.
Bro You can do by Yourself Most of the Questions are very Easy Only Formula based questions are there. I am you can do it by yourself.
@@TheRealAbhimanyu yups, i tried and I did all sums by my own :)
Now I'm stuck at areas of PARALLELOGRAM and triangles ex 9.3 🥲😂
m of angleBCD = 80 degrees
Mam pls continue on smartboard only🎉🎉🎉🎉
Mam how did u get (8x)in the first Pythagoras law ex 9.3 1 one
Same question
A-b) whole square
Mam your teaching is so amazing. I can understand easily. Thank you mam❤😊
Mam agar exam March mai ho to kya kare
Hii 🦋
You are good teacher for 9th standard ❤
Mam you are ttooo gorgeous