General Aptitude | CSIR NET | Numerical Ability | Life Science / Chemistry / Physics / Maths/ Part-I
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- Опубликовано: 9 июл 2024
- This video lecture of General Aptitude | CSIR UGC NET | Numerical Ability | Life Science / Chemistry / Physics / Mathematics Concept/Problems/Solutions/Tricks/Questions | Examples & Solution By Definition | Problems & Concepts by GP Sir will help Engineering and Basic Science students to understand following topic of Mathematics:
1. General Aptitude Series Part-1 For CSIR UGC NET For all Subjects Like Life Science / Chemistry / Physics / Mathematics
2. Previous Year Question Solution CSIR UGC NET With Short Tricks.
3. How To Get Good Score In Part-A Of CSIR UGC NET
4. Short Trick To Solve Question of Numerical Ability Of CSIR UGC NET
4. Tips and Tricks Of General Aptitude Of CSIR UGC NET
#CSIRNET #Aptitude #Part-1 #NumberSystem #ShortTricks
#EngineeringMahemaics #BSCMaths #GATE #IITJAM #CSIRNET
This Concept is very important in Engineering & Basic Science Students. This video is very useful for B.Sc./B.Tech & M.Sc./M.Tech. students also preparing NET, GATE .
Find Online Solutions Of General Aptitude | CSIR UGC NET | Numerical Ability | Life Science / Chemistry / Physics / Mathematics Concept/Problems/Solutions/Tricks/Questions | Examples & Solution by GP Sir (Gajendra Purohit)
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Time Stamp
0:00 - An introduction
1:04 - Q1. CSIR-NET DEC 2019
4:42 - Q2. CSIR-NET JUNE 2017
6:21 - Q3. CSIR-NET DEC 2014
8:15 - Q4. CSIR-NET JUNE 2017
9:51 - Q5. CSIR-NET DEC 2015
11:46 - Q6. CSIR-NET JUNE 2014
13:10 - Q1. CSIR-NET DEC 2014 Based on Numerical Ability (answer asked in Comment box)
13:32 - Q2. CSIR-NET JUNE 2017 Based on Numerical Ability (answer asked in Comment box)
15:04 - Detailed about old videos
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Dr.Gajendra Purohit
I have no money for purchase any course because of high costly system. So I trying for self study. Your channel give me a powerful motivation and helpful for my exams
I am trying also self study
Tumne 1 year ago ye comment kia tha , abtk toh csir crack ho chuka hoga n
@@jagratibauddha5848😂
ye to us moment ho gya bro 😅
Q1-A
Q2-D
Awesome session sir👍👍👍
Loved your teaching. Thank you sir✨
amazing video sir.recommending this to all csir aspirants
Sir now I got confidence for solving problems..Thanks for such a wonderful videos..
Q1. (a) is the correct answer.
Q2. (d) is the correct answer.
Thank you so much for the beautiful explanation, Sir! 💖😇🥰🙏🙏
Nice video. Found it very helpful.
Good job sir aapki video kafi helpful rehti he
Very Good Video Sir. Thank you. Answer of Q.1 is (a) and of Q.2 is (d).
Csir net mathematical science students are very lucky to have u sir ...
Mind blowing,,ur teaching way represents ur experience thanks a lot it will help lot of students sir ...😃
I agree
Thanks sir helpful content hai ye
Your teaching process is awsome! 🥰
Feeling well after looking at your video lecture.. Sir
Fabulous explanation sir, upload more videos
Sir aapke videos bahut jyada helpfull h thanks
Thanku so much sir...brilliant way to understand the concept
Q-1: A
Q-2: D
Superb sir
Hat's off to you 🙏🙏
Amazing sir helpful continue it tnk u somuch gurujii😍
Very good explanation sir, thank you so much
Excellent explanation sir,I am regularly follow Csir net maths
बेहतरीन सर ...👌👍👍
Q 1) a
Q 2) d
Superb explanation sir. I learnt much
Sir main ek life science student hu lekin apke jo aptitute ke maths k videos hai wo bohut a66e hai sir hume jaldi se samaj ata hai parai thank you so much sir! ☺
Wow sir u are really awesome 👌
Wonderful teaching ....thank you so much sir 🙏 ☺
I just started to prepare for NET exam. Its very useful and thank you
very well explained sir, thanku sir
Thanks so much sir . Wonderful lecture.
Wow,very helpful sir.....
So nice method of teaching sir
No time waste thanks a lot sir
✏️ perfect squares always end with digits 1,4,5,6,9
6 is succeeded by an odd number
5 is succeeded by an even number.
And always found two zeroes together at the end ( if we have zero at the end)
✏️ If NET14 and NET15 are 5d numbers st their sum is 175229 then N+E+T = 7+8+6 = 21
✏️If N,E,T are distinct positive integers such that N*E*T = 2013
Then maximum possible sum N+E+T = 671+3+1 = 675..
Assignment question
🖍️ Option a is correct
You are my fav गुरु जी
Q1-(a)
Q2-(d)
Thanks a lot sir nice teaching 👌🙏💕
Video bohut ascha laga sir ... keep it up sir ..
Sir ei se hi humlogo ke upor apni daya drishti banaye rakhiye sir..love you sir...
Extraordinary teaching..... 🙏🙏🙏🙏🙏🙏🙏🙏thanks sir
Thanku sir, your teaching method is best
Yours videos are very helpful sir.
Sir your teaching style is very nice 👌 I understand all the things very easily
That's such a good approach sir...please make more such videos sir
Sir, I am proud of you!
Thankx sir for ur valuable knowledge
Thank you for sharing your knowledge.
1-a
2-d
The second one is how you got ?
1. A
2. D
Thank you so much sir you are such an angel
Very good explanation of sir
Thnku sir ☺️ all your videos are always very helpful....
Best way of teaching 🤗
Sir, which method is to be used when how to know ? (in 4th question u used LCM). There can be number of methods to solve one sum..
Thanku sir for these class...really helpfull
Sir your teaching way is too good....
Thank u so much
This video is so helpful sir thank u so much
Wavvv sir g , nice explaination g
Excellent teaching sir
Way of explanation is superb
Thanks
Sir i hav solved ur h.w question so ..1 (A) and 2(D)thanku sir ur teaching way is awesome 😊 nd u r superb sir 😊
2 qwestion ko explain kariye pls mujhe samajh NAi aya
Please explain Q2
@@user-tz1jz6ef5r ek ek option ko uthao or value put kro ager ABC ki value C k equal aayi vhi ans hoga
@@user-tz1jz6ef5r 1 8 5
+ 1 8 5
1 8 5
------------
5 5 5
@@pragyaambore4692 kaise kiya
Infinite likes sir 👍👍
Thank so much for this session
Q1_A
Q2_D
Awesome sir mazaaa aa gyaaaa
nice Sir......salute❤
Biggest thanks to uh sir
Superb sir...Tq sir
Wonderful video sir
clear explanation.Thankyou sir
1.a
2.d
Thank you so much sir 🙏
Itana achha sikhane k liye
Sir u r really osm ❣❣❣
Khub valo
Great sir..
Sir your way of teaching is superv please make more Vedios that should be depends on concept
In option (B)-2 in units digit in perfect squares 2 won't come in units digit (C)-units digit 6 before number must odd D-8 won't come as unit digit in perfect squares so answer is (A)
Question (8):if we add the sum 3(100A+10B+C)=100C+10C+C
(D) only satisfy this equation
So answer (D)
Thank you very much for your explanation sir iam following your videos regularly
Thank you sir 👌🙏
Congratulations sir
Thankyou sir ..its helful for all students..🙏
Sir thank you very much sir.
Thank You sir for this knowledge
1-a
2-d
Thank you sir you are the best faculty
You are the best teacher
Awesome Sir
thnku so muchhhhh sir😊
Thank you sir
I enjoy in study
Sir thank uu aap bht acha pdhate h
Thanks alot sir...
Thankyou so much sir 👍😀
Super teaching please go ahead it's from Tamil nadu
Excellent 👍 Love and Respect from Pakistan
👍👍
Thank you sir 🙏
1.a,,2.d,, nice and very useful video,,well explained,,thank u sir,,
Sir, please update the correct step with an explanation
Q.1-(a)
Q.2-(d)
Sir, your teaching is awesome,wonderful, perfect.... All questions are easily understand
Thankyou sir❤️
1) a
2) d
Thanku sir for this video
Appriciating
Sir maine like kr diya h share v ..sir aur video daalye
Thanks a lot sir
Well explanation sir
GP is best teacher of maths
thanks a very lot sir
Thank you Sir👌
Very helpful class
Thanku so much sir ❤️
Thnku sr
Thank you sir❤️❤️
Nice explain sir👌