Evaluating a Limit at an Infinite Discontinuity { x/(x-4) }

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  • Опубликовано: 23 дек 2024

Комментарии • 11

  • @bradyquaglia1710
    @bradyquaglia1710 Год назад +9

    This just helped me clutch up my math final

  • @xadxtya
    @xadxtya Год назад +2

    good work

  • @DTLRR
    @DTLRR 7 месяцев назад +1

    What about DL Hospital Rule?

    • @hebertengineering
      @hebertengineering  7 месяцев назад +2

      L’Hopital’s rule? That only applies for 0/0 or inf/inf type indeterminate forms.

    • @DTLRR
      @DTLRR 7 месяцев назад +2

      @@hebertengineering Ohh yes. I can't believe I forgot that.
      Sorry.
      And that's one of the reasons I follow your channel.

  • @joefuentes2977
    @joefuentes2977 6 месяцев назад

    Ya gotta use epsilon delta bro 😂

  • @milukutusydney3123
    @milukutusydney3123 Год назад +6

    You differentiate the expression to get the limit

    • @NoovGuyMC
      @NoovGuyMC Год назад +11

      Not necessarily, and also you cannot use l'hopital's rule if you don't have 0/0 or infinite/infinite form or indeterminate form by doing it normally (plugging numbers and such)

    • @barberickarc3460
      @barberickarc3460 Год назад +3

      Only works for 0/0

    • @adrified9352
      @adrified9352 Год назад +1

      L’hopitals only applies for 0/0 or inf/inf