Surface Area of Spheres (1 of 2: Finding the Surface area of spheres and hemispheres)

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[@manjistharawat9144]

You've made it not only understandable but enjoyable too! Thank you, Sir!!

[@papilionig123]

can't thank you enough!! no every teacher is as competent in teaching like you. love it!!!

[@kbailkeri]

finally someone who explalins how the formula makes sense. Thanks a lot sir!

[@HoshikawaHikari]

Now I understand, thank you! (My teacher never explains in detail like you do)

[@oitheremate]

You are marvelous sir. Just like Ramanujan. I like the way you teach, its fabulous. I want to know where did you study from and in which country do you teach mathematics, and importantly are you really a school teacher?
Hope you will reply.
Thank you

[@francisong5083]

Mohit Jassi
He really is a teacher here in a local school in Sydney Australia.

[@dannyzeke]

He's the best!!!

[@christopherellis2663]

Great Circles, the key to competent navigation! Passing through opposite points of the surface. It don't mean a thing, if it got that spin...because there is some interesting physics that happen on the surface of a rotating sphere.

[@RexCorpuscle]

Hey what's wrong with the antarctic circle? You're an Australian!

[@KamuStoku]

When looked to an hemisphere on top you can see it like a circle so it must be 2πr^2 a sphere`s surface area. Isnt it?

[@Twocubic2228]

Don't know why I am replying ,you need to proof it using Conformal map(I think)

[@auckcouncil2168]

So why don't you simplify it? Use the diameter. A= pi times D squared. Much easier.

[@casimirronnlof7396]

The radius is more used for example area of a circle = pi*r^2 and area of circle = 2pi*r

[@prabinlimbu3860]

Lucky students who could sit in his classes

[@greatsky8226]

Using the integral by thinking, it's easier:
surface = 2 * integral { [ 2 * pi * (R^2 - z^2)^0.5 ] dz | (0, R) }

[@user-kz8qo5ki7w]

Hello , please can you explain how to convert the surface area of the sphere to the area of rectangular

[@Twocubic2228]

Conformal map

[@mach1553]

Cylinder first, then turn it into a rectangle.

[@srivatsav9817]

you are the marker walter lewin

[@ViMi1]

2:50 theory and practice are two completely different things :) :)

[@angel_ia]

Due to abandoned tiny curved areas, the real magnitude must be MORE than "12.56".

[@aaravgulati2]

But it is extremely small...so makes no sense at all

[@danielmacarthur7208]

🙏🙏🙏🙏🙏

[@RomzProductions]

coool

[@samueltoledorobledo2419]

hola

[@that_billu_guy]

2nd comment