Class 11th - Bending of a Cycle on Turning | Laws of Motion | Tutorials Point

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  • Опубликовано: 3 дек 2024
  • Laws of motion - Bending of a Cycle on Turning
    www.tutorialsp...
    Lecture By: Mr. Pradeep Kshetrapal, Tutorials Point India Private Limited

Комментарии • 40

  • @nashp1694
    @nashp1694 Год назад +4

    Best physics teacher in the universe. We will always miss you sir.

  • @supreemdahal4277
    @supreemdahal4277 10 месяцев назад

    Thankyou sir, appreciated it ❤❤

  • @bhuvaneshwargoram
    @bhuvaneshwargoram 5 месяцев назад +1

    Fantastic explanation

  • @stylebgmi
    @stylebgmi Год назад

    Fantastic explanation. Thankyou sir.

  • @krishna-ng8ge
    @krishna-ng8ge 4 года назад +1

    Thank you so much sir

  • @shabnam_sajida
    @shabnam_sajida 6 лет назад +4

    Thanks a lot . Sir . Well explained

  • @bishalhamal2020
    @bishalhamal2020 2 года назад

    Thank you sir ♥️♥️♥️

  • @rishabhtripathi4453
    @rishabhtripathi4453 3 года назад +1

    Thank u so much sir
    U are great🙏

    • @kishore5311
      @kishore5311 3 года назад

      @Sushant Chauhan straight

  • @ms.lavanyathanigainathan9301
    @ms.lavanyathanigainathan9301 5 лет назад +4

    Thank you sir...

  • @sunandashukla6303
    @sunandashukla6303 3 года назад

    easy to understand sir

  • @prashantverma6323
    @prashantverma6323 4 года назад

    Thanks sir

  • @riteshpanth7041
    @riteshpanth7041 5 лет назад +3

    Thank you very much sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

  • @sohanisharma628
    @sohanisharma628 4 года назад

    Thanku sir...

  • @kannadachemistryradhika8699
    @kannadachemistryradhika8699 4 года назад +1

    What's about friction?????

    • @ercop215
      @ercop215 4 года назад +1

      which is very less the the contact between tyres and road is very low
      but in case of car friction will act

  • @saikumaramaan7772
    @saikumaramaan7772 3 года назад

    🙏🙏

  • @alphonseerlich239
    @alphonseerlich239 3 года назад

    R (uppercase) as what and the units?

  • @Green_3.14
    @Green_3.14 2 года назад

    Where is frictional force ?

  • @thethirdview513
    @thethirdview513 5 лет назад +2

    Sir figure me centripetal force ki direction bhi dikhaate to easy pad jata ... Abhi samjh nahin aa raha ki centripetal force kahan lag rha hai

  • @Vijaykumar369S
    @Vijaykumar369S 4 года назад

    Good sir..Thanks a lott sir

  • @adhavan.a7964
    @adhavan.a7964 2 года назад

    ggs my boi passed me

  • @blakshmi2858
    @blakshmi2858 4 года назад +2

    Sir can you start live classes

    • @prakharsatyam6259
      @prakharsatyam6259 4 года назад

      Ye sir expire kar gaye

    • @among_AI
      @among_AI 4 года назад +1

      He passed away 😔

    • @HaamroNotes
      @HaamroNotes 2 года назад +1

      @@among_AI how did he die? Please reply if y know

  • @kkpandey6458
    @kkpandey6458 2 года назад

    Sir please iska note se available kara dijiye sar please I request tutorial point

  • @jaunpurpointtechhd3100
    @jaunpurpointtechhd3100 6 лет назад +4

    Thank u sir.I also teach physics

  • @namangupta1010
    @namangupta1010 5 лет назад +8

    sir the derivation is completely wrong but the ans is somehow correct. You have changed the definition of the contact force in your derivation, the contact force is always perpendicular to the the surface of contact .We usually bend the cycle to overcome the torque due to friction. we shift our center of mass to overcome the torque because if we go straight the frictional torque will throw us back. the contact force is perpendicular to the surface and there is a frictional force acting inwards. If you want the exact derivation I can mail you.

    • @bmworld8046
      @bmworld8046 4 года назад

      It is not normal reaction it is only reaction

    • @sciencedost4903
      @sciencedost4903 4 года назад

      Can any one tell me that for 2 wheeler banking of road is necessary or not

    • @Physics_Show
      @Physics_Show 4 года назад

      @@bmworld8046 bhag chutiye

    • @keyconcept1248
      @keyconcept1248 3 года назад

      We can increase θ in a certain angle which is depend on the coefficient of friction between the two surface , here N(normal reaction) =Rcosθ=mg
      and Rsinθ=mv²/r =μmg

  • @apurvasharma13
    @apurvasharma13 3 года назад

    Thanks sir👌

    • @apurvasharma13
      @apurvasharma13 3 года назад

      @Sushant Chauhan brother r cos is on upward direction and its work done is zero 😁