Defects of Vision Numericals Physics CBSE Class 10 Abhishek Sir
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- Опубликовано: 5 сен 2024
- 🟢Defects of Vision Numericals Physics CBSE Class 10 Abhishek Sir @VedantuClass910
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In this session, Abhishek Sir discusses "Defects of Vision Numerical Physics CBSE Class 10." He explains the different types of vision defects and the optics of the eye . The session includes numerical problems and step-by-step solutions, making it an ideal resource for CBSE Class 10 students who want to improve their understanding of the subject. The session is designed to help students prepare for their exams and gain confidence in their knowledge of this topic. Watch this session to learn from an experienced educator and strengthen your understanding of the defects of vision in Physics.
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Size of the object = Size of the image
Lens- Convex lens
So,the object is placed at centre of curvature.
So,object distance(u)=Radius of curvature(R)=image distance(v)
Image distance(v)=50 cm(Given)
So,R=50 cm
=>f=50/2 (R=2f)
=>f=25 cm
=>f= 0.25m
Power(P)=1/f
=1/0.25
=100/25
=4D
Thanks yaarrr
Session was awesome sir, enjoyed it!!!❤️
Focal length = 25cm and power is +4D.
If image is same size of object, |m| = 1. So, object is placed at 2F1, and |object distance| = image distance = 50cm.
R = 50cm
f = R/2, f = 25cm
P = 100/f(cm) = 100/25
P = 4D (option c)
Thank you sir 🥰🥰🥰
Brdr object at 2F1 hoga convex lens hai
@@Alpha-up3kh yes you are right thanks brdr
3:00 - 10:28 ALL the formulas of Human eye related numericals ,,,, THE CHEAT SHEET 🔥🔥🔥
Thank you 😁
@@ancygeorge3717 🙂🙌
Sir, you are my inspiration towards physics. You have not only taught us physics but you also have taught that how to imagine physics. Thank you, sir. And the answer to the homework is power= 4D focal length =25cm. peace ✌️ ✌️✌️😜😜😜🤭😜😜😜
Aacha bete
acha babu sona
Option C 4 D
Bcz object is at C then focal length will be 25 cm and power will be 4 D
Homework Answer:- 4 D! 😌
Thank a ton ❣️ for this amazing session sir! 🔥🔥
Kindly send the PDF of this session as well as of super 30 light! 🙏🏻🙏🏻🙏🏻🙏🏻
yes you are tight 😗
right
H.w. ans - option C i.e. +4D
Session was amazing as always 🔥🔥🔥
answer for the homework: as the image is the same size as that of the object
2f=50cm and f=25 cm
p=100/f if f is in cm
therefore p=100/25= 4D
option c
In first question, focal length should be -0.6m. Concave lens can not have a positive focal length.😢
WE HAVE GIVEN THE
V=50 CM
THEN SOLVING THIS. WE GET TO KNOW THAT 2f=50cm
Then Focal LENGHT =25cm
So power
P=100{cm)/f
Then P=100/25
Then power of conveX LENS IS
+4D
Really SIR LOVED THE SESSION ,HATS OFF TO YOU
Magnification is 1 so image is formed on 2f2 so v=u
Both 50 cm
So focal length= 25 cm
P=100/f= 4D
Thank you so much sir you are best techer of physic no one can teach like you all my all concepts are clear
Hw ans- (C ) 4D , focal length =25cm
Thanks a lot sir.
BALLE BALLE ❤🔥
HOMEWORK ANSWER :-
C) 4D
THANK YOU FOR THIS AMAZING SESSION SIR 😊....
HW QUESTION-
Toh ques mai tumhe v ki value given hai jo 50 cm hai, u ki value bhi -50 cm he hogi kyuki img ki size same hai(jaha pe hum object 2F1 pe rakhte hai or img 2F2 pe bnti hai).
Ab lens formula se F nikalo jo 25 cm ayegi.
Ab P=1 BY F lagake power 4D ajayegi.
Thx a lot for the session sal
❤❤
AMAZING SESSION SIR!!! 😊❤
Homework answer: option(c) 4D
Answer -
u = -50 cm
f = + 25 cm
P = + 4 D
Option C) 4D
Hw ans 50 cm and 4 d
Amazing session❤❤❤mazza
HW Question:-
Ans-c)
object distance=-50cm
focal length= 25cm
power=4D
Thank you sir for this amazing session! 👍👍
sir, isn't the focal length negative in the first question? 18:26
Hw answer- option c) +4 D is correct ans.
Soln- v=50cm and u=50cm( Mention same as object size) 1/f =1/v-1/u = F=25cm
P=1/f 100/25m =4D is correct ans.
Hw ans:
(C) +4D
Thank you Sir for boosting our confidence... Wonderful Session❤❤❤♥
I was a part of this stream last year during my board exams... nkw i hv entered class 12th and finished geometrical optics... and i wonder how we took these easy [toooo easy] questions as burden
Thats the thing we should learn the problem we are facing now is nothing infront of experience and stiff problems that are waiting for u in future, so be positive and chill
H.w. ans -> focal length=25 cm
power=4D
Amazing session sir ye questions krke maja agya😄
and yaa happy shivratri sir🥰
H.w question
Option c -- +4D
It was an amazing session sir 😊
H.W ans - c) 4 D
Thank you so much sir for all these amazing sessions ☺️☺️
Homework ans:-+4D
Focal length:-+25cm
Object distance:- -50cm
Session was awesome
Focal length = 25cm
Power=4D
Thankyou sir , this helped me alot ❤
Sir session was best , all the numericals are now easy after watching this🔥🔥🔥
Thank You Sir❤️❤️❤️
HW Ans:-(C) 4D
Distance of object placed is 50cm
Focal length is 25cm
N power is 4D
Thank you for the wonderful session. Abhishek sir op!!!!🔥🔥🔥
Thank you Sir. This was The first video which I saw of your's.I Was having a lot of trouble in solving questions on this topic. You saved me Sir! Thanks a lot❤❤❤❤❤❤
H.W ans, = +4D , object is placed at -50 cm and focal length= -25 cm.
Very helpful session 🥰 Thank you Sir 😊😊 Myself Shanvi Sharma ✨✨
HW
1:00:02
V=+50cm
f=25cm =0.25m
P=1/f = 1/0.25 = 4D
Thank you
Hw ques ans: 4D
Focal length: 25
U= 50
Ans of the homework question is 4D
Sir, the session was amazing! I never enjoyed this much while solving physics numericals...
Finally this topic is easy now!!
H.w. ans is option c that is 4D
Sir session was really amazing. ..
H.W. ans 4D option c
Easy
Sir maza aa gya session me in
Balle Balle
Thanks for your so much efforts
I think words are not sufficient to thank you!
Before one day of my mid term examination your video had cleared all my doubts that helped me a lot...
Thank you sir😊
Majjaaa aagya sir 🔥🔥🔥♥️,,,
HOMEWORK ANSWER:-
V= 50cm
F = 50/2 = 25cm because the image and the object both are kept on Centre of curvature ,, hence F=R/2
P= 1/f(in m)
= +4D
Session majaa agya sir ,, ab lag raha hai aapne itne swaal kar wa diyee hai ki ab inmse se aane ki probability zayda hogyii sir ♥️🔥🔥🔥🔥🤗🙏
thank you bro....
@@soniyajain8793 welcome 😇
2:42 starts
Appreciated
Thanks
C is the answer and session was lit 🔥🔥🔥🔥maja aaya mujhe aaj volunteer ban ke
Lord of physics 🔥🔥👍👍👍❤️❤️❤️❤️
This is not a lord of physics the Lord of physics is Mr sir 😎😎
@@kaminisingh8895 for class 10th buddy😉
Majduri se duri mr * hai jaruri
Try Rakshak and Ashu Sir
But no hate to Abhishek Sir he is also great
@@barcelonaandmsnfanboy4825 han bhai thik h😆 abb me 11me aa gya hu toh meko Saleem sir lord lagte h😘😘🤫🤫🤫
Amazing session✨👍👍
Hw answer = 4 D
f = 25cm
Thank you sir ❤
Homework answer is +4D option c
Thank you so much for the amazing sessionvahh sir ji✨
Sare solve karke full confidence aagaya sir ji✨🌻
answer of homework question is 4D.
Homework f 20 cm power 5D
sir, the session was awesome....i loved it. and the answer is 4D
Hw answer: option c session was 💛💛💛
Amazing session sir 🤩🤩🤩
Hw ans +4D
Session was amazing loved it.
Ans-C
ANS = +4D
SIR, I was able to solve this question in just *5 sec*. This is all bcz of you sir!
thank you so much sir, ❤❤
this was the most needed session for mee😇
Thanku sir for such a amazing session all my doubts are cleared after watching this loads of thanks ❤❤
Amazing session sir loved it
Homework answer: (c)
H/w answer
V= -50
U= -25
We know,
1/f = 1/v-1/u
Therefore focal length= 50cm
P=1/f(m)
P= 100/50 D
Therefore Power= 4D
💛💛💛💛💛
Ans = 4D,in the front of lens.
C-4D
Thank you so much sir for this wonderful session❤❤❤❤ 🙏🙏🙏🔥🔥🔥
Sir you are not only Lord you are the posidon of the physics ,😎
Ans 4D
Session was amazing as always n now I am confident for these numerical.. thanku💞✨
Wonder session sir ❤️❤️❤️
Hw ans :
u (object distance)=-50cm
f(focal length)=+25cm
P(Power)= +4 D
Sir, after attending this session I feel confident. Thank u for an incredible session. Answer is 4D
+4D option c
POWER IS 4D AND OBJECT IS PLACED AT 50 CM ON THE OPPOSITE SIDE OF LENS FOCAL LENGTH WILL BE 25 CM
52:31 i think v may be positive here because its convex lens
10:43 myopia defect
Sir homework question 4D 💯💯..
Tq so much for the practice sir 🥺🙏🏻🙏🏻..
amazing session sir , i understood all the concepts and now i can solve all the questions with confidence thank you sir
H.W ans - option C - 4D
Thnx of such amazing session
Homework Ans
u=-50 cm
v=+50 cm
Focal length = +25cm
Power=+4D
Session was great as always ANS - +4D
Bhai please explicitly kar do mara 2D aa raha hai
@@harsh3627 bro question me U ka position at 2f1 pe diya 50cm h... To focal uska half 25cm hoga.. phir Power ka formula se 1/0.25 kardo ans nikal jayega +4D
H.W answer
u=-50cm
f=+25cm
P=+4D
The session was fire🔥🔥🔥🔥
Very nice sir
Good job 🎉
Home work answer is option c and session was amazing sir ❤
HAMM LAKHON KA SAHARA AAP HO SIR JI 🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
Thank you so much for this video ❤ I really wanted this
Kaise ho mere Shero and shreniyon hits different ❤❤❤❤
ABSOLUTELY INCREDIBLE explanation as always sir!😃👍💪⚡️
In 1st question focal length is -0.598m.
Homework question
Sir option (c) 4D
Is correct
Thanks sir..🔥😁
Answer to the hw question;
v = 50 cm
u = -50 cm
f= 25 cm
p= 100/25= 4 D
Home work question answer:-
f=25cm and P=+4D
Homework
Ans - Option C (4D)
4D
AKR SIR ,take the video of HOW TO FILL OMR AS PER OUR 10TH NEW BOOKLET please sir
Lovely session sir ❤️❤️❤️
Hw ans : u=-50cm f=+25cm Power= +4D
The session was very nice and helpful too
Answer of homework question
C - 4d
Hw answer focal length = 25 cm therefore power of the lens =4D
Dear Teacher, thank you for inspiring me and igniting my passion. I will always be thankful to you for all the hard work and efforts you have put in me
last Q4 answer is (C) 4D and focal length is 25cm
made this chapter very easy
thx for the session
Thanks for the session sir ji..
H.w answer- (c) +4D
Thank you sir, for such questions. Helped me a lot
Sir option C is the right option i.e. 4D
Thank you so much sir for this video ❤️❤️🙏🙏
Answer is Option c
4dioptre
Sir you made physics more interesting
And now science is the most beautiful and interesting subject for us