Sir 1÷x integration Between 0 and infinity Clearly it is improper and it diverges can we say it is integrable or any other method to integrate it Explain clearly every question Also when can we say integrable ?
Hello sir, I need your help kindly see the problem given below :- Q. Let Z denote the set of integer and Z>=0 (0,1,2,3,...). Consider map f:( Z>=0)×Z to Z given by f(m,n)= (2^m)(2n+1) then we have to check the function is one to one and onto ..? Thanks
Actually , I show the function is onto by taking, m=0 and n=(y-1)/2. Which shows function is onto but what about one one I tried by putting different inputs and getting different outputs ... Is this correct ?
Yes. That's the problem. See, cauchy integral formula it required winding number but winding number of a boundary point is not defined. Also, see cauchy residue thm, isolated singularity inside the region. So this is problem with such types of problem.
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Fourth part ans: 1-i
Ans of H.W. : 1. (2/3)+2i
2. (8/15)+(32/15)i
3. (1/3)+(7/3)i
4. (1/3)+(7/3)i
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Thank you Sir.👍 Sir please upload video of Complex Residue.
Ok
Clear con॰ सर
Residued class सर
Sir 1÷x integration Between 0 and infinity
Clearly it is improper and it diverges can we say it is integrable or any other method to integrate it
Explain clearly every question
Also when can we say integrable ?
The integral which we get in the complex
What is the picture of that
As we have area in case of real
For fourth part answer is 1-i
Does complex integration represent area
Sir integral sinx÷x from 0 to ♾️
Why can't we use by parts method
V: [0,1]--C be defined by v(t)=e^4πit
Then, 1÷2πi integration (e^z÷z^3 dz) = ? Plss sir can you explain how to solve ????
Ans is 1
Sir if integral is from (1,1) to( _2,0) thn wt wil be the ans
Hello sir,
I need your help kindly see the problem given below :-
Q. Let Z denote the set of integer and Z>=0 (0,1,2,3,...). Consider map f:( Z>=0)×Z to Z given by
f(m,n)= (2^m)(2n+1) then we have to check the function is one to one and onto ..?
Thanks
Actually ,
I show the function is onto by taking,
m=0 and n=(y-1)/2. Which shows function is onto but what about one one
I tried by putting different inputs and getting different outputs ... Is this correct ?
Take f(m,n)=f(r,s) then check equality of m and r, n and s
@@RahulMapariBasicMaths ok sir
Really appreciate thank you Take care 😊☺
How to calculate
Int f(z) on |z|=a where f(z) has a singularity at z=a
Singularity On boundary then we can't use any thm.
@@RahulMapariBasicMaths then how can we evaluate that.....suppose for e.g.
Int (e^z)/(z-2) & domain |z|=2
Yes. That's the problem. See, cauchy integral formula it required winding number but winding number of a boundary point is not defined.
Also, see cauchy residue thm, isolated singularity inside the region. So this is problem with such types of problem.
Where are the next videos of this chapter????
Plz explain in hindi ...we all indian knows Hindi
Great sir. May i get you email please
Thank you sir👍
Thank you sir
Thank you sir