Fluorescence Spectroscopy Intro (Lumina Fluorometer)

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  • Опубликовано: 4 янв 2025

Комментарии • 7

  • @acr92651
    @acr92651  11 лет назад +3

    The goal of the emission scan is to detect light emitted will be at a longer wavelength than the excitation photons. If the emission scan were to start at 480 nm, the spectrum might be dominated by scattered 490 nm excitation photons, which are not the result of fluorescence events. If NO fluorescence occurs, the ONLY photons which will be detected are the original 490 nm excitation photons.

  • @collegegirlchemistry7756
    @collegegirlchemistry7756 4 года назад

    I am literally the dumbest graduate student ever so thank you so much for this video now I know how to design my experiment

  • @Rungus27
    @Rungus27 11 лет назад +1

    if the molecule excites at 490 nm, why did you start the scanning at 500 nm? I just did a lab on this and im still confused.

    • @Meinan4370
      @Meinan4370 7 лет назад +2

      an excited molecule will emit at a longer wavelength usually minimum around 30+ nm more.

  • @biyabi87
    @biyabi87 9 лет назад

    You mentioned that as you increase the voltage, you increase the intensity and the sensitivity. So, why you didn't use the highest voltage available? Is there a rule for what value you should use. Thank You

    • @acr92651
      @acr92651  8 лет назад

      Increasing PMT voltage increases the noise apparent in the spectrum. Therefore, it is advantageous to use the lowest voltage that will result in several thousand counts. Also, the detector has an upper limit of about 65,000 counts, so increasing the PMT too much will result in readings that are off scale.

  • @soubhikdas8130
    @soubhikdas8130 10 месяцев назад

    You don't know how hold a cuvette