thank you for your beautifull lessons , i have a question please : i understood that for strong acid [H+]=[HA] since complete dissociation occured , but to be precise isnt [H+] = [HA] + 10(-7) ? , where 10(-7) is the concentration of hydronium ions already in water ? , is my logic true ? , are we ignoring this 10(-7) since it is small number ?...thank you
Correct logic but as you say, since the [H+} from the dissociation of water is so insignificant in comparison, we ignore it. This is more relevant with weak acids - if you haven't already, check out my videos on those, especially the approximations video I've made. Hope that helps and thanks for the kind words :)
![Calculate the pH of a Strong Acid and pOH, [H+] & [OH-]](/img/1.gif)
8 years on and still saving lives
Thank you very much sir. God bless you and your family. I wish you best.
+MaChemGuy Isn't it called Monoprotonic, Diprotonic..etc due to it being an acid
That's a new one on me.
thank you!!
thank you for your beautifull lessons , i have a question please : i understood that for strong acid [H+]=[HA] since complete dissociation occured , but to be precise isnt [H+] = [HA] + 10(-7) ? , where 10(-7) is the concentration of hydronium ions already in water ? , is my logic true ? , are we ignoring this 10(-7) since it is small number ?...thank you
Correct logic but as you say, since the [H+} from the dissociation of water is so insignificant in comparison, we ignore it. This is more relevant with weak acids - if you haven't already, check out my videos on those, especially the approximations video I've made. Hope that helps and thanks for the kind words :)
@@MaChemGuy thank you for your fast reply , much appreciated...i will watch your lessons about weak acids very soon...thx again
no entropy videos?