11th PHYSICS | UNITS AND MEASUREMENT | DIMENSION | LECTURE 03 | PRADEEP GIRI SIR
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- Опубликовано: 21 сен 2024
- 11th PHYSICS | UNITS AND MEASUREMENT | DIMENSION | LECTURE 03 | PRADEEP GIRI SIR
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Dimensions of Force
Force = m × a
= [L⁰M¹T⁰] × [L¹M⁰T-²]
= [L¹M¹T-²]
12:02 : HW 👆👆
Dimension of Pressure
Pressure = F / A
= [L¹M¹T-²] / [L²M⁰T⁰]
= [L¹M¹T-²]× [L-²M⁰T⁰]
= [ L-¹M¹T-²]
16:27 : HW👆
Dimensions of Area
Area = [L²M⁰T⁰]
THANK YOU SO MUCH SIR FOR YOUR SUPPORT AND TEACHING❤❤❤
PLEASE CHECK MY ANSWER 🙏🏻
🎉
GT Systmm 😎🙌
Physics Becomes easier when Pradeep Sir starts teaching 😊❤
Thank you sir ji
True
Dimension of force = ( L¹ M¹ T-² )
Dimensions of force
Force=m×a
=[L⁰ M¹ T⁰]×[L¹M⁰T-²]
=[L¹M¹T-²
Dimensions of pressure
Pressure =F/A
=[L¹M¹T-²]/[L²M⁰T⁰]
=[L¹M¹T-²]×[L-²M⁰T⁰]
=[L-¹M¹T-²]
Dimensions of area
Area=[L²M⁰T⁰]
[L¹M¹T-²]\[L²M⁰T⁰] =[L-¹M¹T_²] dimension of pressure
12:00 L1 M1 T-2
AREA'S unit = meter square
Pressure= L-1 M1 T-2
12:19 force dimension- [ M¹ L¹ T-² ]
P=F/A
P= [ M¹L¹T-² ] / [ M⁰L¹T⁰ ]²
P=[ M¹L¹T-² ] / [ M⁰L²T⁰ ]
P=[ M¹L-¹T-² ]
🎯
Thankqq soo much sir for your efforts...!
Isleye main sib AAP ka dekhta hu giri tutorials
Thanks sir aapka lecture mujhe acha laga
Your Explain Very good And Easy ❤
Thank you sir for making videos for us
Force dimension : [ L1 M 1 T-2 ]
Area dimension: [ L2 M0 T0 ]
Pressure= [ L-1 M1 T-2 ]
❤❤❤
Impulse
J=f. [L¹M¹T-¹]
Sir toda confused hai volume ka litre hota hai na please reply me m3 kaise aaya😊
Volume ka unit m³ hota hai, jise cubic meters mein measure kiya jata hai. Ek cubic meter ek cube hota hai jiska har ek side 1 meter ka hota hai. Ek cubic meter mein 1000 liters hote hain. Iska matlab hai ki 1 cubic meter = 1000 liters. Is tarah se, agar aapko liters se cubic meters mein convert karna hai, to aap liters ko 1000 se divide kar sakte hain. For example, agar aapko 5000 liters ka volume hai, to aap ise 1000 se divide karke 5 cubic meters mein convert kar sakte hain.
Dimension of pressure= L-1,M1,T-2
the answer for pressure is P=[M1L-1T-2] plz reply if correct
1.6.1 uses of Dimensional Analysis
Thx sir
P = F/A
A = [ L M T ]
AS A = m²
therefore,. A = [.L² M⁰ T⁰ ]
As ,. P = F/A
= [ L¹ M¹ T-² ] /. [. L² M⁰ T⁰ ]
= [ L-¹. M¹. T-² ]
THANK YOU SO MUCH SIR ❤❤❤❤
Dimensions of force:- L¹M¹T-²😊❤
I love you too sir 🧠💪❤️
👍
[L¹M¹T-²] dimension of force......
force dimension -[ L1 M1 T-2]
Dimensions of force [L1M1T-2]
force = [ L1 M1 T-2 ]
Dimensions of force =
F= m×a
=[L⁰M¹T⁰]×[L¹M⁰T‐²]
=[L¹M¹T-²]
L१m-१t-२
Thank you Sir❤✨
Area = square [M²]
Pressure= L-1 M1 T-2
Sir please chemistry ka aufbau principle, hunds rule & pauli's rule ke bare may lecture upload kijiye na its a request
Dimensions of pressure=L-1 M 1 T-2❤
Force= [L¹ M¹ T-²]
Good video ❤
Dimension of P=L-¹M¹T-²
Sir, dimension of Force :- [L¹ M¹ T-²]
Force ka dimension L' M ' T -2
Sir plz dimensions me word problem ke liye Kuch Batao na plzzzz
Dimensions of Force =m×a
[L°M¹T] x [L¹M°T-2]
= [L¹M¹T-2]
Dimension of Force =[L¹ M¹ T-²]
[L¹ M¹ T-² ] ‹------force dimension
Sir help us in 11std also like 10th std
Area=meter square (m^2)
The Dimension Of Force L1 M1 T-2
Dimension of force L¹M¹T-²
sir I salute for your efforts
joule - full name
J - symbol
Thanks sir 😊
sir aaja video bohot late aaya
but aacha aaya
thank you sir😊
Area = length × breadth
Dimension of force :[L¹ M¹ T-²]
Force = [L¹ M¹ T-²]
Pressure = [L-¹ M¹ T-²]
Area = [M²]
Thank you sir ❣️✌️
Maza aa gaya sir
🎉sir dimensions aa gaya
12:03 F = [L1 M1 T-2]
P=F/A
[L1 M1 T-2]
----------------
[L2 M0 T0]
=[L-1 M1 T-2]
M2
L1 M1 tminus 2 force
Area -m2
Force dimension is [ L¹ M¹ T-² ]
Force dimension- L1 M1 T-2
Area- [L2 M0 T0]
pressure - [L1 M1 T-2
Sir dimension sabka learn karle to chalega na ... Exam mai derive karne nhi bolenge na
Force dimension=[ L1 M1 T-2 ]
Area dimension =[ L2 M0 T0 ] (because area unit is m2 so L2)
Pressure dimension=[ L-1 M1 T-2 ]
Force=L1 M1 T-2
Thank you so much 👍😊
Thank you sir❤
16:18 SI unit of area is m²
Thanks sir
Pressure=[L-1 M1 T-2]
Dimension of force L1 M1 T-2
P = f/A ka ( L1 M-1 T-2)
Dimension of Pressure
[ L-1 ME T-2]
Force- [L1 M1 T-2]
Dimension of force=[L¹M¹T-²]
Dimension of pressure
P=F/A
=[L¹M¹T-²]/[L²M⁰T⁰]
=[L-¹M¹T-²]
Force dimensions = L¹ M¹ T‐²
Force Dimension = [ L1 M1 T -
2]
L2 M1 T-2
Area {2}
aao sir direct vishay ya vrr zatay amhala kay kalanay
not underpant
Dimension of force= [ L1 M1 T-2
Force dimension L1 M1 T-2
force [l1 m1 t-2]
[L-1 M1 T-2] DIMENSION OF FORCE 👈👈
Bhai Systummm Hai GT Ka 😎💪🏻🔥
Pressure = ML-1T-2
Area =m²
m2
pressure =[l-1 m1 t-2]
13:11 dimension of force=[L¹ M¹ T-²
Dimension for Pressure=Force/Area=[L-¹ M¹ T-²]
[L1M1T-2
Area =L2,M0,T0
Area m²
Sayad m^2
F=L¹M¹T-²
MLT-2
(L' M' T-2)