Theory of Equation | Roots Diminished By h | Transformation Of Equation

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[@aman7726]

Sir what is the reason behind taking h negative when we have to increase the root....do tell me 😊

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Yupz

[@study-junction02]

Let's say the eq. ax^2+bx+c=0 has a root '¥'
This implies: a¥^2+b¥+c=0 ........(1)
We have to increase the root by 'h'
For that,we have to replace 'x' by 'x-h'
Then the new equation which has root '¥+h' will be:
a(x-h)^2+b(x-h)+c=0 .........(2)
I think here is your question that:
if we have to increase the root by 'h', then why we are replacing 'x' by 'x-h'
Now the eq(2) has root '¥+h'
You can observe it that '¥+h' satisfy the eq(2) , by putting x=¥+h

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Coz it's like eg: x+2 =0 hence the x will come out negative.

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By putting (x+h) or (x-h) on the place of x , can we do the same sir?

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mtlb add 0X^4 + 0X^1
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