Ex 13.1 Q1 | Surface Areas & Volumes | Chapter 13 | Class 10 Maths | NCERT

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#Cube.
C.S.A = 4a²
T.S.A = 6a²
Volume =a³
#Cuboid.
C.S.A = 2h(l+b)
T.S.A = 2(lb+bh+hl)
Volume = l×b×h
#Cylinder.
C.S.A = 2πrh
T.S.A = 2πr(h+r)
Volume = πr²h
#Sphere.
C.S.A /T.S.A = 4πr²
Volume = 4/3πr³
#Hemisphere.
C.S.A = 2πr²
T.S.A = 3πr²
Volume = 2/3πr³
#Cone.
C.S.A = πrl
T.S.A = πr(l+r)
Volume = 1/3πr²h
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Volume of cone is 1/3πr²h

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Formula to be taken TSA or CSA depends upon what has been asked , whether simple structure or 2 structures attached/placed inside one another
Take formula as what portion after process (asked in Q) Can be touched or can be coloured.
Surface area Volumes
ruclips.net/p/PLUCY9EyBf63oKuECNJRBQQaUFV-MtqNic&si=Z4qv1OWEJ8RZFCKr

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