Intersections of Three Planes Part 1

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  • Опубликовано: 3 дек 2024

Комментарии • 21

  • @paul1964uk
    @paul1964uk 12 лет назад +4

    It works because of operator precedence: cross products comes first, dot products second.
    It's just like in ordinary arithmetic if someone asks you: "what is 'A plus B times C'?" The operational precedence forces parentheses around 'B times C', which must be the first stage even though it doesn't 'appear' first.

  • @mingfeng6963
    @mingfeng6963 3 года назад +1

    Very good. I learned useful knowledge. Thanls

  • @Killuminatismd
    @Killuminatismd 13 лет назад +2

    Thanks very much, very clear explanation.

  • @ganeshramg.s7715
    @ganeshramg.s7715 4 года назад +1

    Super explanation.Understood consistency,inconsistency and number of solution to system of three variable equation

  • @kled6566
    @kled6566 4 года назад

    Very useful video, thanks!

  • @supadupadupakunt278
    @supadupadupakunt278 5 лет назад +1

    excellent video!! thank you so much

  • @xotweetypiexo
    @xotweetypiexo 13 лет назад +1

    Should that be the cross dot product and not the dot cross product? Because cross dot product would be vector cross vector = vector and then dot vector, but dot cross product is vector dot vector = scalar cross vector, and that would be nonsense. Wouldnt it?

  • @supadupadupakunt278
    @supadupadupakunt278 5 лет назад

    What do you mean by "linear combination" in case 3 and 4? Does it still apply if in a different exercise I would use subtraction? E.g. Plane 3 = Plane 2 - Plane 1 ? Or can it only be a sum of the two other ones?

    • @jjewitt3
      @jjewitt3 5 лет назад

      It can be subtraction too.

  • @eldir700
    @eldir700 4 года назад

    god bless your soul good sir

  • @anuragtiwari2723
    @anuragtiwari2723 8 лет назад

    How do we determine if there are 3 pairs of line of intersection (Shown in case 3 of this video) or its just 1 line of intersection (shown in case 4 of this video) ?

    • @AlRichards314
      @AlRichards314  8 лет назад +1

      +Anurag Tiwari If the 3 planes (2 of them at a time) intersect in 3 parallel lines, then one of the normal vectors can be written as a linear combination of the other 2 normal vectors. That's not always easy to see by just looking at them.

    • @anuragtiwari2723
      @anuragtiwari2723 8 лет назад

      +AlRichards314 Is that the only way we can determine that ? And in linear combination can we use negative numbers as the scalar multiple ?

    • @anuragtiwari2723
      @anuragtiwari2723 8 лет назад

      +AlRichards314 If there is only one line of intersection (i.e. Case4); the normals will be a linear combination of other 2 normal vectors too right ?

    • @AlRichards314
      @AlRichards314  8 лет назад +1

      +Anurag Tiwari I don't know of any easy test to determine if the 3 normals are dependent (1 is the linear combination of the other 2). Yes, the scalars can be negative numbers.

    • @AlRichards314
      @AlRichards314  8 лет назад +1

      +Anurag Tiwari Yes, in fact the entire planes equations are dependent. There is a test that might help sometimes (I'm using *" to represent the dot product). If you call n1, n2 & n3 the three normals, then if n1*n2Xn3 is any non-zero value there must be a unique point of intersection. If n1*n2Xn3 = 0, then there may be a line of intersection or not solution at all.

  • @xotweetypiexo
    @xotweetypiexo 13 лет назад

    Oh never mind! I wrote that before the end of the video, its just the way you wrote it. DURR

  • @gaminguchiha3763
    @gaminguchiha3763 3 года назад

    ly man