Laser Cooling - Sixty Symbols

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  • Опубликовано: 23 дек 2024

Комментарии • 399

  • @sigalig
    @sigalig 9 лет назад +113

    This professor, Dr. Bowley I believe is his name, is so gifted in teaching science. He may never see this comment, but I just started teaching labs as a graduate student and I have been constantly studying Dr. Bowley's teaching through Sixty Symbols. It is amazing.

    • @peterbrown6802
      @peterbrown6802 9 лет назад +4

      +sigalig I 100% agree. I think that he is one of the most gifted teachers! Bless his soul!

    • @n8lay
      @n8lay 8 лет назад +7

      I didn't realize scientist's had souls...i thought they removed their souls, at a young age, through the proper application of logic and experiment.

    • @bobbyt9431
      @bobbyt9431 5 лет назад +3

      The best scientists have souls, it's the only way to think for yourself.

  • @GrahamSiggins
    @GrahamSiggins 8 лет назад +86

    1 Baff should be a new SI unit of momentum

    • @katzen3314
      @katzen3314 8 лет назад +7

      We should change everything else to fit with the baff more nicely.
      eg: Units of force: *baffs per second*.

    • @rayniac211
      @rayniac211 7 лет назад +3

      It would actually be an unit of work or impulse.

    • @HappyBeezerStudios
      @HappyBeezerStudios 7 лет назад +3

      1 Baff is the amount of work needed to bring a particle reacting to light of 671.005 nm into a state where it instead reacts to light of 671.000 nm.
      It is all explained in the video :D
      And it ffints nicely into the SI system where every unit is calibrated to basic laws of physics.

  • @Slarti
    @Slarti 12 лет назад

    The professor is so good at explaining science because he has a humility and understanding of the lack of understanding of his audience - I wish I had had him as a lecturer at university!

  • @MrOldprof
    @MrOldprof 14 лет назад

    @ByakuyaZERO
    No it is significant: this is where the kinetic energy of the atom is lost bit by bit so that the atom loses its kinetic energy. It recoils when it absorbs the photon and goes into an excited state; then it re-emits a photon which can go in any direction so on the average there is no recoil, and some of the kinetic energy is lost.
    Also the entropy of the gas goes goes down as well as it cools, but the entropy (disorder) of the photons increases so all is well.

  • @Lavabug
    @Lavabug 14 лет назад

    @RupertsCrystals
    I think he said the energy of the photons when absorbed by the atoms turn into the "momentum" of their electrons, making the atoms change into an excited state. The professor said there's a recoil or "nudge" or "push" whenever this happens.
    What I want to know is: how do photons -massless- hitting an atom have an effect on its kinetic energy? Why do the lithium atoms slow down when they become excited?

  • @ObjectManipulator
    @ObjectManipulator 12 лет назад

    Yes, that is correct. When the photon hits the atom it does so with some momentum, this will impact the movement of the atom slightly,thus slowing it down. In doing so the photon causes an electron jump into a higher energy state, and because electrons don't like being in this state it will return to its original energy level, though the emission of energy, taking the form of a photon...

  • @maekern
    @maekern 14 лет назад +1

    I have always wondered how that works! Also, you folks are getting better and better at editing together videos that do a good job of leading the viewer into ideas. You are excellent.

  • @echosystemd
    @echosystemd 14 лет назад

    @IngeniousSheep the atom does absorb the photons, and later the spontaneous emission of these photons will contribute to cooling atoms, while induced emission of such photons does not help. Wiki page about "laser cooling" gives same explanation as seen in the "Doppler cooling" part.

  • @Fordi
    @Fordi 14 лет назад

    Nifty thing about this: because the nature of laser cooling is that the mass of the target atoms are directly related to their resonance, this technique can be used for (and has been adapted to) isotopic enrichment.

  • @bobster451
    @bobster451 14 лет назад

    @mr0myster Yes!
    Also it is improper to state "degrees kelvin"
    Both rules are often broken.
    It is sufficient to state "zero kelvin" without the absolute or the degrees.

  • @ObjectManipulator
    @ObjectManipulator 12 лет назад

    ...This emission is in a random direction, and carries with it its own momentum, meaning that it also affects the movement of the atom. This may be either slowing it down or speeding it up, but because of the large numbers of photons that are being shot at the atoms by the 3 lasers, and the random nature of the direction of the photon's emission, the result is a net cooling of the substance. Hope I've explained that well... If not let me know :)

  • @BrandonCourage
    @BrandonCourage 12 лет назад

    @rogerdotleethe exclusion principle doesn't apply to bosons, they have integer spin

  • @LeafyDavid
    @LeafyDavid 11 лет назад

    Mass and energy are interchangeable so you just look for the energy required for a particle to have an effective mass so great the particles individual gravity causes the escape velocity from the particle is greater than the speed of light.

  • @HENJAM48
    @HENJAM48 12 лет назад

    This Sixty-Symbols Series is brilliant! And to a Fellow Aussie, (I think Meghan gave that away a couple of vids ago) Well done. You've made me sound smart again.

  • @cabrita309
    @cabrita309 14 лет назад

    Very good job editing.
    I was able to easily understand what they were talking about. If you remove 1 key scene from this video, it doesn't make any sense.Well done Brady!

  • @Gorteenminogue
    @Gorteenminogue 11 лет назад

    What an excellent video! Less than 10 minutes and I now understand how lasers cool. Wow.

  • @galerius07
    @galerius07 9 лет назад +1

    Have they tried forming a condensate with rubidium to compare it to the lithium condensate?

  • @ElTurbinado
    @ElTurbinado 7 лет назад +1

    does this mean, if you accidentally start with a laser frequency that's too *low*, you'd heat them up instead? since they might catch the light as they're moving away from it instead of towards it?

  • @Amin.Askari
    @Amin.Askari 4 года назад +1

    - How cool is to put your name on a bizarre state of matter?
    + Bose-Einstein cool
    - That would be my first most enjoyable thing

  • @BlueberryJamPie
    @BlueberryJamPie 14 лет назад

    I have some questions:
    1. If its in space or somewhere with 0 gravity, does its time to cooling off increase or no?
    2. If you made a sphere of lasers would it go faster, or the time is the same even if you use just 2 mirror pointing at each other back and forth?
    3. So it's affected by the Doppler effect? And what would happen if you...put your hand of an object on the middle where its cooled off?
    Very interesting video btw. ^.^

  • @snakefang1863
    @snakefang1863 10 лет назад +7

    How long 'til I can put one in my PC? :P

  • @MrOldprof
    @MrOldprof 14 лет назад

    @gamesbok
    The photon is absorbed by the atom and an electron goes to an excited state. The electron goes back to the ground state and a photon is emitted isotropically, that is all directions of emission are equally probable. On the average (the photon can be emitted in any direction) the atom loses momentum, and also a bit of its kinetic energy is taken away by the photon. Repeat the process ten thousand times and the atom slows down and nearly stops. A Nobel prize results for this idea.

  • @Duncan_Idaho_Potato
    @Duncan_Idaho_Potato 12 лет назад

    Professor Bowley should host popular science documentaries. He's really something else.

  • @angusrobert8992
    @angusrobert8992 9 лет назад +18

    How dare you put atoms in a cage?! P.E.T.A. will hear about this!

  • @SomeSickDingus
    @SomeSickDingus 12 лет назад

    This may or may not be relevant but I think it's inverted temperature rather than actually physically bringing it down in steps below zero, so not the intuitive thought of below zero, probably something much different. I can't post a link to the article directly but google "temperature below absolute zero' and you should have some good leads.

  • @DrDoe1
    @DrDoe1 14 лет назад

    I never thought it would be possible to make laser cooling sound any more complex but that guy just did it.... Bravo! not so much complex as it was long but still hahaha. Great video.

  • @Atrix256
    @Atrix256 12 лет назад

    I wonder if there is any sort of "feedback" or detectable effect on the laser's side from the atoms resisting the force of the laser beams?

  • @dangahhrus
    @dangahhrus 12 лет назад

    It's great to see someone so passionate about their work, it's a shame he's retired.

  • @thewiseowl
    @thewiseowl 13 лет назад

    @bmbirdsong There's no such thing as an 'absence of molecular motion'. Molecules will still possess a zero-point energy, and can never reach absolute zero. On the other hand vibrational energy levels go from v=0 to v=∞, so there is no maximum temperature. Or put another way, to get something to the speed of light would require infinite energy. Thus unless you can get to ∞°C you won't get an atom/electron or any particle with mass to the speed of light.

  • @OnlyOneNagaBABA
    @OnlyOneNagaBABA 7 лет назад +1

    "getting JIGGLY with it", Dr. Bowley's favorite song :)

  • @systemofapwne
    @systemofapwne 12 лет назад

    Are those Radiant Dyes Laser Mirror-Mounts and a Toptica Photonics Laser.

  • @ReedCSings
    @ReedCSings 14 лет назад

    I understand mostly everything going on here with the doppler effect and the shifts which occur, but why do the photons add on once the particle matches the frequency of the laser?

  • @525047
    @525047 14 лет назад

    Laser cooling is awesome. You can call it laser compression. You're using an electric field to counter the motion of another electric field.
    It works, and it still has stuff to tell us.

  • @Kalywonkas
    @Kalywonkas 12 лет назад

    Basically it's a theory that states that as you pass below absolute 0, (you cannot obtain 0, itsself, either +/- temperatures) that as you make the temperature more negative, entropy decreases rather than increases. It's not quite the natural way of thinking about 'temperature'

  • @Eay5paev
    @Eay5paev 12 лет назад

    One thing I don't understand: once the atom has absorbed a photon, it is indeed slowed down since it has received the impulsion of the photon which was going in the opposite direction. Ok, but at some point the atom must reemit this photon, doesn't it? And then it will get a recoil and thus regain the lost impulsion, won't it?

  • @bmbirdsong
    @bmbirdsong 13 лет назад

    If absolute zero is the absence of molecular motion, is there a corresponding opposite temperature? A point beyond which you can no longer add heat to a system? Would that be the temperature of gas molecules moving at the speed of light?

  • @defjam99b
    @defjam99b 14 лет назад

    Always enjoy learning something brand new, off to read-up a little on Doppler-cooling, which I guess is the whole point, so cheers.
    ... and Professor Roger is of course correct, nothing beats a really good sneeze.

  • @thewiseowl
    @thewiseowl 13 лет назад

    @bmbirdsong v=0 is just the vibrational quantum number. This isn't equal to T=0 or absolute zero. The reasons behind this are pretty complex, but it's due to anharmonic properties of molecular vibrations and fun things like that. Wikipedia is your friend on this. :)

  • @BrandonCourage
    @BrandonCourage 12 лет назад

    @RandyRedCactus The photons are absorbed by the electrons and raise them to another energy level

  • @sudarshanbadoni6643
    @sudarshanbadoni6643 3 года назад

    On a complex science subject there exists union of a subject expert and a joyful demonstrator expert to make us understand at least partially and also realize the complexity of such systems and situations. Thanks.

  • @run4urmony
    @run4urmony 9 лет назад +2

    What's the point of all the mirrors and lenses etc. if all that ends up happening is the lasers get routed through a fiber optic cable to some other spot? The lasers are already, presumably, coherent and everything, so what more needs to be done?

    • @gibbetify
      @gibbetify 9 лет назад

      +Ryan Lanzetta There is just one laser, but they need many beams from all directions... The apparatus is meant to split the beam into many beams that are then routed to the cooling chamber...

    • @jake1996able
      @jake1996able 9 лет назад

      +gibbetify
      And you can't just use simply three lasers, because you have to keep the coherence and so on?
      Is that right?

    • @gibbetify
      @gibbetify 9 лет назад +2

      +Jake K.
      I don't think coherence is the major issue here. The reason one laser is used is because the laser used here is expensive piece of equipment - so a mirror assembly is just more economical than having three lasers!

    • @RandomNullpointer
      @RandomNullpointer 8 лет назад +1

      Also, as I understand from the video, if a different frequency is needed, there's some arrangement that can shift the frequency of the laser a tiny bit.

  • @pschroeter1
    @pschroeter1 10 лет назад +4

    Where does the kinetic energy of the atoms go? When they absorb the laser photons doesn't it just put them into an excited state?

    • @8ung3st
      @8ung3st 10 лет назад +9

      No expert but I found somewhere that they almost immediately release a photon afterwards in a random direction, with a tiny bit more momentum than the original photon, thus everything is conserved.

    • @GordanCable
      @GordanCable 10 лет назад +4

      Alex is right, in fact this results in a cap to the amount of cooling you can achieve with lasers alone. This cap is called the "Doppler Limit". We can, however, cool atoms past the doppler limit by adding things like an external magnetic field as in a MOT (magneto optical trap), and polarization gradient cooling which uses polarized laser light to further cool atoms.

  • @satansquared
    @satansquared 11 лет назад

    Question: So the atom gets exited and gets slown down due to a "recoil".but does the atom emit an EM-wave with a higher frequentie than the incoming laser light frequentie ? because you'd otherwise be losing energy because the kinetic energy of the atom gets smaller. Hope my question is clear :p

  • @Patrick_B687-3
    @Patrick_B687-3 8 лет назад +28

    But what is the first most enjoyable thing that you know Dr. Bowley? :-)

    • @douglasdobson8110
      @douglasdobson8110 8 лет назад +8

      +P Bryce Alaska King Crab Legs is my guess. . . . .

    • @shomonercy
      @shomonercy 8 лет назад +4

      Didn't get the vid but his last sentence stuck with me. Maybe he just wanted us all think about whats most enjoyable to us personally. So romantic!

  • @CaptainZavec
    @CaptainZavec 11 лет назад

    I'm confused by something. So you need the right frequency for the atom to be affected, you need to change the laser light, like he said. But unless all of the atoms get hit and stay at the speed they need to be, won't some "fall off the bus," so to speak? In that if I need frequency X to slow the atoms down, and one of them doesn't get hit by any photons, and then the frequency is changed to Y which is no longer what it needs to be for those particular atoms, are they just left as they are?

  • @VenturiLife
    @VenturiLife 10 лет назад

    So if you have a laser cooling something very cold, and a laser heating something very hot, you could create a heat-exchanger (peltier arrangement) that allows you to re-capture the energy?

    • @rutgerdehaan5076
      @rutgerdehaan5076 9 лет назад +1

      shades2 Some of it. It's a cool experiment, but it won't be free energy.

  • @RufolfRakete
    @RufolfRakete 13 лет назад

    so you shoot a photon that has a certain amount of energy into another moving particle that has energy and and the resulting energy is less because the energy difference is stored in the particle itself by exciting an electron? is that correct? if not where does the energy go? and isnt the particle eventually going to go back into its ground state and emit a photon and thus start moving again? i hope i can get some answers! thanks for the great videos!! keep it up!!

  • @Kalywonkas
    @Kalywonkas 12 лет назад

    only in the very rare event (technically impossible) that the atom re-emits the photon in exactly the opposite direction in which it was absorbed. Which is essentially just like the photon and atom not interacting at all

  • @whoppix
    @whoppix 14 лет назад

    @xXmatthdXx
    That seems unlikely. You need a gas or at least a liquid for this to work. On a CPU, which is opaque, you could at best shoot lasers on it from the top etc., but not from all directions, and the laser wouldn't reach into the CPU very far (or at all).

  • @leerman22
    @leerman22 13 лет назад

    Got any thermal discouragement redirection cubes?

  • @RealTwistedTwin
    @RealTwistedTwin 11 лет назад

    I heard that at the temperature of 1.41x10^32K the wavelength of the radiation which is emitted by the atom reaches the planck length... So if it's getting more energy we don't call it temperature anymore.

  • @letterpool
    @letterpool 14 лет назад

    Just subscribed today and already learned something I've wanted to know. How they cool with lasers. Of course I could have googled it but for some reason never did.
    Keep up the videos!

  • @liamdawson3845
    @liamdawson3845 12 лет назад

    Why is there a momentum shift in the gas particles when a photon hits it if photons have no mass?

  • @douro20
    @douro20 10 лет назад

    It seems that one of the biggest enemies of cooling atoms to fractional Kelvin temperature scales is not so much the physics of doing so, but the amount of time it takes to do it. Some experiments involving these temperature scales can take hours, days or even months to reach their conclusion, and the amount of time it takes to do it when you get below 1K seems to vary inversely with the temperature they want to achieve.

    • @zIHaXSaWIz
      @zIHaXSaWIz 10 лет назад

      the time scale for the actual cooling is very short due to the number of photons emitted compared to the number of collision needed

  • @clancywiggum3198
    @clancywiggum3198 7 лет назад

    Where does the energy go, though? Don't the electrons on the atoms have to re-emit the photons to return from their energised state, regaining the momentum they lost (albeit in a random direction)?

  • @V60DS
    @V60DS 12 лет назад

    Doesn't photo electric emission take place when you but the Na atoms with photons of the correct frequency? Also, why are sodium or rubidium chosen for the experiment?

  • @mimArmand
    @mimArmand 3 года назад

    So interesting! I have 2 questions!
    1- Where does the energy go?
    2- Is that theory (about the mechanism of how it works) confirmed or is it just a hypothesis?

    • @mimArmand
      @mimArmand 3 года назад

      I think I found the answer to question one!
      The cooled atom will emmit a photon immediately.
      But now I have a new question!
      3- How can you tweak / fine-tune the frequency of light with that precision?!

  • @xKargatx
    @xKargatx 12 лет назад

    @anonymousbl00dlust I also am not an expert. I think, that when the photon hits it slows the atom down. Then the photon is re-emit in a random direction and will gain momentum again, but since it does this a lot of times and the direction is random it will equal out at some time and only the slowing down effect of the photon hitting will matter, because it always hits from the same direction. Someone pleas correct me if I'm wrong.

  • @m.lazarusarnau1197
    @m.lazarusarnau1197 7 лет назад

    I have one question. Because the atoms are absorbing I assume that the electrons of the atoms are going in to a higher energy state. I know that this increase in energy doesn't imply a temperature change (electron energy != kinetic energy). But, why don't the electrons fall back in to a lower energy state and eject a photon which would counteract the momentum change? Is it because this kind of cooling is only feasible for gasses which are receptive to photon absorption but less susceptible to ejection or is it because the photons aren't being absorbed by electrons but by some other particle (something in the nucleus maybe?)?

  • @MichaelJRigby
    @MichaelJRigby 11 лет назад

    the energy isnt disappearing its being absorbed by the atom. like when two pool balls move toward each other and hit both will stop. Thats why the atom has to be moving to the laserbeam.

  • @knarkis90
    @knarkis90 12 лет назад

    What would a laser cooling system like that one in the video cost?

  • @FalcoGer
    @FalcoGer 12 лет назад

    if movement of atoms mean temperature, then there have to be a maximum temperature because atoms can't move at the speed of light right?
    what's that temperature limit?

  • @31337flamer
    @31337flamer 11 лет назад

    sadly he retired already :/ .. im glad we have these videos of him here :)

  • @DevilMudger
    @DevilMudger 14 лет назад

    That is the single coolest (heh) looking set of equipment I have ever seen.

  • @kheffah
    @kheffah 13 лет назад

    Oh WOW!! I've wondered for so long how they get stuff into such tiny temperatures. and YES i did think laser alway heated up or burned up stuff :D Thanks for clearing the misconception.

  • @emadrio
    @emadrio 12 лет назад

    Do the atoms that absorb the photons eventually release the energy from their excited state? I imagine once they're pretty slow, they would have had been quite excited

  • @unknotmiguel
    @unknotmiguel 14 лет назад

    @CRUK87 probably because.. the mirrors are altering the wave pattern by splitting and interference at the quantum level. :s

  • @tom_something
    @tom_something 5 лет назад

    So when the photon is absorbed, it's quickly re-emitted, right? Is it re-emitted back in the direction it came in from, or is it randomized? I realize that in either case the interaction will effectively steal momentum from the subject on average, but I'm curious.

  • @sidewaysfcs0718
    @sidewaysfcs0718 11 лет назад

    plank temperature , althought photons do travel at light speed, they don't have plank temperature.
    temperature is just a measure of how much "jiggling" there is in a substance, if you had an atom moving in a PERFECT straight line in a vacuum, from the inertial frame of the atom, it would be at zero kelvin, regardless of what relative liniar speed it has.
    but that's the thing, atoms don't move in straight lines, quantum fluctuation prevent matter from reaching 0 K.

  • @NoobLord98
    @NoobLord98 6 лет назад

    But what about the releasing of the absorbed photon? I'd reckon this could again increase the momentum of the atoms.

  • @inkonspishus
    @inkonspishus 12 лет назад

    I don't know about the first part, but the second part I believe is because sodium and rubidium both can form Bose-Einstein condensates.

  • @marmaladekamikaze
    @marmaladekamikaze 13 лет назад

    @anonymousbl00dlust
    The photon energy is actually lower than is necessary to excite the atoms electrons, but when the atoms are moving towards the photon source the doppler effect causes the atoms electrons to essentially be fooled into being exciting. The atoms slow down 3:40. To be honest I'm not an expert either.

  • @conoba
    @conoba 14 лет назад

    Where does the energy from the heat go?
    Are the atoms decreasing the wavelength of the laser as it passes through?

    • @sparxva
      @sparxva 5 лет назад

      @MainsOnTheOhmsRange The atoms absorb one frequency of light but then emit photons. I'm guessing they probably emit photons at a different frequency than they absorb leading to a net reduction in the energy of the atom.

  • @bmbirdsong
    @bmbirdsong 13 лет назад

    @thewiseowl Wait, if v=0, isn't that absolute zero?

  • @hyky68
    @hyky68 14 лет назад

    So how do they fine-tune the laser frequency as they hit the atoms?....if i understood the basic idea correctly, the laser frequency constantly has to undergo a change to match the atom's frequency to cool it...

  • @jamesrindley6215
    @jamesrindley6215 6 лет назад

    Where does the heat which is extracted actually go to?

  • @johnhall9222
    @johnhall9222 9 лет назад

    I don't know if this question has been asked already, but I thought Rubidium and Sodium were solid at room temperature. So when you are lowering the temperature of this gas doesn't it just turn into a solid? How do they keep the atoms seperate while lowering the temperature to such extreme levels?

    • @KyleDB150
      @KyleDB150 9 лет назад +2

      john hall melting/boiling points are different at different pressures, remember this is being done in a vacuum
      for example at water freezes at a lower temperature at high altitude (lower pressure) than at sea level (higher pressure)
      so because these particularly unstable metals are in a vacuum, they can be kept as gases at much lower temperature

  • @waauu
    @waauu 12 лет назад

    So the emitted photon has a higher energy, sort of anti-Stokes-like?

  • @igivup4815
    @igivup4815 7 лет назад

    Einstein once wondered what it would be like to travel alongside a beam of light. As I recall he pondered what the world around him would look like as he cruised along at 186,000 miles per second AND he pondered what the beam of light itself would look like as he traveled alongside it. My question is this, we have managed to slow a beam of light down to a crawl inside a Bose-Einstein Condensate. Aside from its speed, is the properties of light still the same regardless of its speed and can we study and learn things about light inside the BEC that we could only speculate about before the advent of the BEC?

  • @scottmuck
    @scottmuck 7 лет назад +1

    So where does all the heat go?

  • @ataraxic89
    @ataraxic89 14 лет назад

    Can someone tell me why atoms dont want to stop entirely? Or what prevents specifically? (Absolute zero)

  • @MrOldprof
    @MrOldprof 14 лет назад

    @roidroid
    A laser beam has no entropy because the photons in a laser are in a single quantum state, S = k ln(W)=k ln(1) = 0. The gas of atoms is hot (say 800 K) and has a lot of entropy.
    The absorption and re-emission of photons by the atom leads to the photon gas having a lot of entropy (disorder) and the selected atoms having less entropy (they cool). Overall, entropy is increased in the process which is the basic law of thermodynamics. The scattered photons take away the energy.

  • @Azathoth43
    @Azathoth43 12 лет назад

    I'm really glad someone busted him on this most egregious offense. No one should take this man seriously. Thank you.

  • @frankbass1
    @frankbass1 14 лет назад

    What is the first most enjoyable thing?

  • @dbrckovic
    @dbrckovic 14 лет назад

    @roidroid This is one of the things that's bugging me.
    The other one is. If you hit an atom with a photon of the right frequency, the energy of the photon is used to shift an electron of that atom to the higher orbit. If that's so, then where did the energy which slowed down the whole atom come from?
    To me it seems that the atom should do exactly the opposite. It should absorb the photon when frequency is correct, without affecting atoms speed, and reflect it when it's not correct.

  • @robertej09
    @robertej09 12 лет назад

    Yeah that's what I was wondering too.....Perhaps it doesn't re-emit the photon straight back.....

  • @JoeJoeTater
    @JoeJoeTater 13 лет назад

    So, where does the energy from the hot atoms go?

  • @mikkokylmanen9296
    @mikkokylmanen9296 8 лет назад

    Is it so that because of the Doppler effect, the atom emits a photon with a larger wavelength and energy than the one it initially absorbed; also does this cause the reduction in the kinetic energy of the atom (and cooling due to repetition of this process)?

  • @ahmedraafat8261
    @ahmedraafat8261 7 лет назад

    i have a question if anyone knows the answer, now we hit the atom with photons in the opposite direction of the atom's motion to slow it down. but in this direction due to doppler shift the atom sees a frequency closer to its resonance frequency o it will absorb it. so what about its emission? i mean that it still absorb energy and re-emit it dost these collision due to compton effect that we consider this atom like a free particle that absorbs part of the photons energy and changes in its momentum ?

  • @TioDave
    @TioDave 14 лет назад

    What is the most enjoyable thing?

  • @renedekker9806
    @renedekker9806 5 лет назад

    If the atoms absorb the photon and get into an exited state, why don't they drop back to base state, by emitting the photon again? That would give them more speed again...

  • @ProfesserPlum
    @ProfesserPlum 14 лет назад

    Where would this be applied to help us? I pretty interesting stuff!

  • @JoeJoeTater
    @JoeJoeTater 13 лет назад

    @elflordbob1 Why would that be? I would imagine converting energy into matter would only occur at very high energies, even if it's an unknown form of matter. Though I suppose dark matter particles could be of very low mass...

  • @mscir
    @mscir 4 года назад

    What's the first most enjoyable?

  • @atourdeforce
    @atourdeforce 12 лет назад

    totally agree it kills me he is actually retired now, and only very infrequently does videos anymore.

  • @whaaaaaaaaaaaaaaaaaaaaaaaaaaa
    @whaaaaaaaaaaaaaaaaaaaaaaaaaaa 5 лет назад

    Don't gas molecules have several frequencies relating to all of their modes of molecular vibration, i.e. stretch, bend, scissor, etc?

  • @olekstom
    @olekstom 14 лет назад

    Thank you for the upload. Looking forward for more videos.

  • @mathiaspaul1987
    @mathiaspaul1987 14 лет назад

    Of what kind is the energy the exited atoms give of? I guess it is light, too. But wouldn´t this light again give energy to the system... So I guess my question really is: How does the energy leave the system?

  • @stud000000079
    @stud000000079 11 лет назад

    But what about thermodynamics of the gas system?

  • @gamesbok
    @gamesbok 14 лет назад

    OK, so you reduce the momentum of the atom by hitting it with a photon, and drive the electron into a higher energy state. I presume then the electron then drops back releasing a photon that doesn't get absorbed. Otherwise you're just pumping energy in. No way will you cool it. I would have thought the new photon was exactly the right wave length to get absorbed. I don't understand.