Sudoku Adventure

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  • Опубликовано: 26 янв 2025

Комментарии • 14

  • @caseyestok1677
    @caseyestok1677 14 дней назад +4

    Rangst I just wanted to thank you for leading me to this type of sudoku! I started play sudoku earlier this year after finding your page from tiktok NTY games videos. I started playing this series a couple months ago and just started branching out to play other puzzles from Cracking the Cryptic. Can’t thank you enough for leading me to this new hobby and community!

    • @Rangsk
      @Rangsk  14 дней назад

      It's such a great hobby and a wonderful community!

  • @praematura
    @praematura 14 дней назад

    I was a bit slow on this one in leveraging the roping created by a few of the entropic lines, but did make it through successfully with a time of 5:54. Many thanks to Gene for a really lovely puzzle, and to Rangsk for presenting it!

  • @davidrattner9
    @davidrattner9 14 дней назад +2

    Fabulous way to end theme week for us Gene!!
    Great interaction with arrows and entropics!!
    @ 3:40 Rangsk..after you got the 6 in R3C6, by roping , it has to go on the entropic in r4, which then forces the 5 off it and into R4C4, which then gives you a 1 in R5C4 and 6 into R5C5.
    Liked how you deduced Box 5 arrow!!
    Arrow theme week was everything as advertised with all 7 puzzles featured!!!

  • @TopHerGas
    @TopHerGas 14 дней назад +1

    Horizontal roping was my key in getting started. After finding that first 6 in r3c6, it forced a 6 in row 4 on that entropic line. This meant there couldn’t be a 5 on that entropic line, forcing it to be in r4c4, due to r5c6 being a 5 or less.

  • @Socialdogma
    @Socialdogma 14 дней назад

    Good puzzle today.

  • @psiphiorg
    @psiphiorg 14 дней назад

    My break-in was along line 4. Since c123 have one of each highness, so do c456. That means their minimum is 135, plus a minimum of 1 in r5c4, means that r5c56 must total at least 10, with one degree of freedom. Then the 6 in box 4 places the 6 into box 6. Then knowing that r5c4 couldn't be a 6 meant that its arrow had to have the smallest two digits from among r5c456, which made them 14 adding to 5. My time today was 4:29, solver number 23.

  • @saidavdic5601
    @saidavdic5601 14 дней назад

    I did it in 5mins.
    Rangsk, you could use powerful weapon, roping with entropic lines. There was a line row 1 column 1-3, meaning there is one low, one medium, one high, but also, it implicates the same for row 1 column 4-6, and for row 2 column 1-3, and for row 2 column 4-6 etc etc. You could instantly place 5 on r4c4, 1 on r5c4, 6 on r5c5 etc.

  • @sonalita_
    @sonalita_ 14 дней назад

    That one was a bit tricky! needed a hint about the circles looking into box 4. The entropic lines made for some interesting logic. The much easier way to deal with box 4 is to notice that that you can't have 5 and 6 in the same row in that box because of the entropy line in box 3 so the 5 must go in r4c4

  • @nineironshore
    @nineironshore 14 дней назад

    17:39

  • @Bayesic
    @Bayesic 14 дней назад

    I kind of used roping with the entropic lines to solve this puzzle (spoiler in reply)

    • @Bayesic
      @Bayesic 14 дней назад

      Basically I got that 6 in R3C6 like you got, and that means that the entropic line in box 3 must have a 6, and that's the ONLY high digit on the line, which means that 5 must be in Row 3 of Box 3. Therefore, we know that 5 goes on one of the arrows in box 4 row 4, and if you tried to put it on the right most arrow you'd be forced to put a 6 in the corresponding circle, which doesn't work because that column already has a 6. So the 6 must be in R5C5, which also gives you a 6 in box 5 by roping
      The last bit of tricky deduction is that the R5C6 circle must be a 4 or 5, but it can't be a 5 because that would force a 6 into the R5C3 circle. The rest of the puzzle kind of flows pretty easily from there

  • @vivim29
    @vivim29 14 дней назад

    It took me 45 mins but I got the right answer, lol.