I love this video, it's much better than the mechanical approach to Variable Elimination. Now I understand WHY it works, and it is so much easier to remember!
literally today i didn,t learn any thing from this lecture hope the students seating there in front of him have the same situation , i noticed it during the lecture.
I dont understand pushing the Summation, I know when constant we can push but here I cant identify which is constant. And moreover I believe that they are the distribution. Containg 2,4 values not only single value. Correct me if im wrong.
@Akash We have assumed that Earthquake and Burglary are two independent events and they influence Alarm. Hence P(B) and P(E) are multiplied as they are. But alarm ringing depends on E and B hence P(A|,E.B). Since alarm influences John calling or Mary calling, we have P(j|A) and P(m|A). Hence P(B) P(E) P(A|E,B) P(m|A) P(j|A)
@@kpb6 I have one more doubt , what if we have some more parents to earthquake and burglary and some more child nodes to john and mary ?? Do all these things should be considered as hidden variables for computations?
Good lecture, but he expects students to guess what he's about to say often without it yet being clear what he's looking for, which seems common in teaching probability.
I love this video, it's much better than the mechanical approach to Variable Elimination. Now I understand WHY it works, and it is so much easier to remember!
i wish you the very best,
with all the love
- a struggling student
The best explanation on the internet
Excellent explanation professor!
Beautiful explanation, great job!
very helpful explanation! i wish my professor explained it this well :)
literally today i didn,t learn any thing from this lecture hope the students seating there in front of him have the same situation , i noticed it during the lecture.
This is what should be captioned as watch till end
I dont understand pushing the Summation, I know when constant we can push but here I cant identify which is constant. And moreover I believe that they are the distribution. Containg 2,4 values not only single value. Correct me if im wrong.
Love the intro
From 14:00 How was sum over E written as f1(A,B) and sum over B written as f2(A)?
Thanks a lot IIT D
21:48 i think its because p(bug...)= 0.001 and p(earth...) = 0.002
I don't understand how that full joint distribution summing over hidden variable came. EE Dept.
@Akash We have assumed that Earthquake and Burglary are two independent events and they influence Alarm. Hence P(B) and P(E) are multiplied as they are. But alarm ringing depends on E and B hence P(A|,E.B). Since alarm influences John calling or Mary calling, we have P(j|A) and P(m|A). Hence P(B) P(E) P(A|E,B) P(m|A) P(j|A)
@@kpb6 I have one more doubt , what if we have some more parents to earthquake and burglary and some more child nodes to john and mary ?? Do all these things should be considered as hidden variables for computations?
@@manjunathakapilsharma Precisely.
For instance:
if [Earthquake] had 2 causal nodes (i.e. parents), then we would do P(E | parents) etc.
If u can mention the particular timestamp, we might be able to exactly clarify the doubt.
tq so much 😇@@kpb6
awesome lecture
Good lecture, but he expects students to guess what he's about to say often without it yet being clear what he's looking for, which seems common in teaching probability.