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Solving Problems with Young's Double Slit Interference Equation - IB Physics
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- Опубликовано: 5 авг 2024
- Now that we have proved Young's Double Slit Interference Equation, we can use it to solve for missing variables in the double slit experiment like the length between maxima, distance between the wall and the diffraction grating, the distance between the double slits, and the wavelength of the light.
Proof of Young's Double Slit Formula: • Proving Young's Double...
0:00 Review of Young's Double Slit Equation
1:32 Example Problem 1
2:48 Example Problem 2
3:45 Example Problem 3
4:57 Example Problem 4
Oh there is no word to thank you as your every lectures are speechless and praiseworthy..! I wish you can continue the same in future and make us learn more❤
This was the one unit I missed, now it’s the one I understand best, thanks
this is the only video ive found on this topic I fully understood thank you
Thank you for all your hard work and great videos!
thank you for this lesson, very simple and very straightforward
Oh my god that was so clear ! Thank you🔥🔥
Thanks a ton Sir! ❤️
Thank you brother you're a life saver
love it, so easy to understand
I LOVE YOUUU THANK YOU
Thanks, so much!
Hi Andy, as usual terrific work. Just a question. Aren't this and the previous video more concerned with two slit interference, as opposed to diffraction? Diffraction, the modulation of light intensity at different areas on the screen, is determined by the slit width, usually termed "a", and is independent of the slit separation, "d". Perhaps the nomenclature you use in the States is different? I really appreciate your videos,.
Thanks a lot Sir ✔️
Hi, I put this question on the Proof for the Double Slit Equation, but the IB formula booklet does not include 'n' in the formula, but your/your explanation does. Could you please explain this? Thanks
Thanks. Tomorrow physics waves & optics exam. ❤️
WTF this was it??? the MCAT books make this topic unbelievably confusing. Holy cow. Andy, if you wanna see some passages about these for the MCAT, I can send it to you.
Actually yes please do, it's kind of wild how needlessly confusing some textbooks can be
@@AndyMasley sent!
Thank u 😀
At my university we're trying to calculate the intensity at a given place y (which is basically just s, in your video).
So if you want the intensity at place s, don't you basically need to calculate n? Because n times total amplitude = some amplitude "=" some intensity at given s? Would this be a good method? Or am I completely off?
Sir Thank you so much my physics teacher is so useless thank you so much you help cleared my doubts
So when in the questions they ask for the distance of a second order maxima, n is 1?
why am i getting (6.4x10 exponent -13) for the 3rd example on my calculator?
Thank youuuuuuuuuuuuuuuuuuuuuuu sir
why is the slit width just completely ignored? What's the variable for that?
Hi. Why weren't standing waves and waves through pipes covered in this course?
They are!
Standing waves: ruclips.net/video/-HW8JcL8wms/видео.html
Harmonics: ruclips.net/video/hCDRaY6xUi4/видео.html
Pipes: ruclips.net/video/xzQO5M1rjfg/видео.html
In order to convert nm into m.......we should multiple with10^_9.... shouldn't we?
@@AndyMasley ok sir... Thank you so much
so is 10^-9 correct or wrong because the reply seems deleted
god bless
Hi andy
Bhaisaab yha to physics zero padi h
Aap pdhao to btao