Domain : All Students in the world. P(x) : x student has taken more than 21 credit hours in a semester and received all A's. Therefore, ∃x P(x) What about this ?
Domain: All people P(x): x is a student s(x): x has taken more than 21 credits q(x): x has received all "A"' Ex(p(x)^s(x)^q(x)) is it correct? plz reply I've an exam tomorrow
Thank you, you are wonderful in your explanation, I'm studying this course at the university now, I benefit very much from you and wish you a little hurry to complete it
i have a doubt a11:03 .if s(x) is =>x is richly coloured ,i think we can't say that not of x means x is dull in color .because not of x will mean not richly cololoured .it can also mean that the bird is "okay" coloured.
Domain: Set of all the people on the planet S(x) : x is a student C(x): x has taken more than 21 credit hours in a semester A(x): x has received all A's ∃x[S(x)^C(x)^A(x)] Is this correct? If not, please point out the error.
Domain: All people. S(x): x is a student. P(x): x has taken more than 21 credit hrs in a sem. Q(x): x has received all A's. then ∃x (S(x) ^ P(x) ^ Q(x))
Domain: all people on the planet earth. P(x): x is a student. Q(x): x has taken more than 21 credit hours in a semester. R(x): x has received all A's. Ans: ∃ x [P(x) ∧ Q(x) ∧ R(x)] "There exists x such that x is a student and x has taken more than 21 credit hours in a semester exam and x has received all A's."
Sir, can we write it as this way too? Hope you reply sir :) Domain: All students P(x) : "x has taken more than 21 credit hours in a semester." S(x, y) : "x received y" ∃x[ P(x) ^ ∀y( S(x, y)) ]
H/W prob. ans:
Domain : All students
P(x) : x students has taken more than 21 credit hours in a semester.
Q(x) : x received all A's
So,
∃x[P(x)^Q(x)]
I also got this...
Thoda doubt tha.about selecting the domain
Domain : All Students in the world.
P(x) : x student has taken more than 21 credit hours in a semester and received all A's.
Therefore, ∃x P(x)
What about this ?
so for exactly one student ( a student) it holds ? i thought it would need negation
Domain: All people
P(x): x is a student
s(x): x has taken more than 21 credits
q(x): x has received all "A"'
Ex(p(x)^s(x)^q(x))
is it correct?
plz reply I've an exam tomorrow
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Thank you, you are wonderful in your explanation, I'm studying this course at the university now, I benefit very much from you and wish you a little hurry to complete it
Sir, Please complete the series of Data Structure and Algorithms as early as possible.
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They completed all but we need to pay rest of videos
Domain-all student
P(x):x >21 credits in semester
Q(x):x has recieved 'A' in all subjects
-】(p(x)^q(x))
i have a doubt a11:03 .if s(x) is =>x is richly coloured ,i think we can't say that not of x means x is dull in color .because not of x will mean not richly cololoured .it can also mean that the bird is "okay" coloured.
Really helpful, thanks!
Make videos on the computer organization & architecture
Ss .
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"no large bird live on honey"... is it wrong to negate the Q(x) instead of negating the R(x)?
Sir you said that Operating system and computer networks video are coming in app on 1st week of September. But you didn't upload it?why?
Because we’re testing the app, this time it is not a small project and it is taking little longer than our expectations.
@@nesoacademy how much time it will take?
Going to cross 1 million soon
Sorry very soon.
Domain: Set of all the people on the planet
S(x) : x is a student
C(x): x has taken more than 21 credit hours in a semester
A(x): x has received all A's
∃x[S(x)^C(x)^A(x)]
Is this correct?
If not, please point out the error.
do dont have to take s(x) because x is already a student as you mentioned for C(x)..only take C(x) and A(x)...
@@codewithsankyy5738 Okay, thanks.
birds that do not live on honey are dullin color
can also be written as there exist some bird that does not live on honey and are dullin color
Sir please complete discreet mathematics
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All of my confusion is completely cleared!
Domain: All people.
S(x): x is a student.
P(x): x has taken more than 21 credit hrs in a sem.
Q(x): x has received all A's.
then
∃x (S(x) ^ P(x) ^ Q(x))
My answer is same. Is it correct? plz reply I've midterm exam tomorrow
@@zulkarninekhan9186 👍
Hello Sir Afaq.
Domain: all people on the planet earth.
P(x): x is a student.
Q(x): x has taken more than 21 credit hours in a semester.
R(x): x has received all A's.
Ans: ∃ x [P(x) ∧ Q(x) ∧ R(x)]
"There exists x such that x is a student and x has taken more than 21 credit hours in a semester exam and x has received all A's."
Domain : All students
Let P(x) = x has taken 21 credits
Q(x) = x has received all A's
Answer to 5:45 = ∃x [ P(x) ^ Q(x) ]
7:30 (personal timestamp)
Thanks
Sir, can we write it as this way too? Hope you reply sir :)
Domain: All students
P(x) : "x has taken more than 21 credit hours in a semester."
S(x, y) : "x received y"
∃x[ P(x) ^ ∀y( S(x, y)) ]
You must define y,
Keep y as all A's not simple y
sir pls provide us you are ppt notes.
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Can we write like this : £ x p(x)
Where p(x): x has taken more than 21 credit hours in a semester and received all A's
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Did bracket matters
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Thank you :)
S(x) : is a student
M(x) : taken more than 21 credit hours
A(x) : received all As
∃x(S(x) ∧ M(x) ∧ A(x))
Thanks a lot