Hi Jeff, quick question. When the particle vibrates "up and down" to minimize its amplitude and in turn create the transverse waves- wouldn't this necessitate these wave packets to spread out in 360 as a general field perturbation? What is the reasoning in your mind that there would be 2 "photons emitted along a cylinder? (Or is that just an artifact of your 2d representation?) That is a hard one to rationalize geometrically. Furthermore, wouldn't the particle vibration create longitudinal waves aimed in the polar axes of its vibration, where it essentially pumps back and forth? Btw, your work is simply incredible. I am breaking now into your 2nd book. You will hear more from me soon. Thank you for your heroic efforts with this theory!
Hi Clay, the transverse component of the EM wave is perpendicular to vibration. For example, electrons in an antenna generating radio waves. There's a different video that I created for an explanation of EM waves and light at ruclips.net/video/ptpEEDTPnGI/видео.html. Around the 2:38 mark you can see some examples. To answer the other questions, the volume of the cylinder was used in the Particle Energy paper to calculate energies of photons and derive the equation that is used. The details are at: vixra.org/abs/1408.0224. And lastly, you are right that particle vibration should change the longitudinal waves when it "pumps back and forth". The longitudinal waves should be spherical, as the electric force is always felt and declines at the square of distance (spherical). But the transverse wave component of the EM wave should be different and travel perpendicular to vibration. Together, when the photon is measured, these two waves types make up the electric and magnetic components of the EM wave.
Hey Jeff, I been thinking of light, specifically the speed of wave induction and cancellation. When I think of transverse waves in water, the cancellation effect causing still water uses some measurement of time featuring travel distance, resistance, etc. Anyways, the example is like turning off the light. The answer that I heard is that the photon acts as some "packet of energy". And this likely acts similarly as the answer for how standing waves can float. This makes me think logically that some form of barrier occurs, similarly the outside of the drum head, or the fret and the bridge on the guitar. If I considered the physical properties of the outer boundary as some field that weakens the wave it makes me wonder how the photon for example can maintain its fluctuation (for example the mathematical properties of white light) over the distance of the star at the planet without decay, but it seems likely that if the photon acts as some form of traveling standing wave it could maintain its fluctuation (if it even travels). Moments after posting this, I remembered your presentation for how electricity mechanically lifts, and thought that light is considered electromagnetic.
I'll share thoughts of an experiment. When they test the speed of light (in one of the forms of testing it) they would use one mirror. I would like to see the same test done bouncing the light from 1000 mirrors and comparing the data subtracting the difference and dividing by 1000, giving the accurate light speed (if any) and the "reflective time" used from the absorption and sending of the mirror. Professor Lene Hau from Harvard University in perspective stopped and started light within matter: ruclips.net/video/-8Nj2uTZc10/видео.html
Just remembered your mathematically talented. What is the absorption and release timing of light within the atom using your kudos equation and does that cause alteration in the measurement of the speed of light?
@@jeffcreighton8669 Regarding your question about the timing of absorption and release, I don't have anything that I've modeled. But I suspect it wouldn't be constant anyway and would be proportional to photon wavelength.
Regarding the question about standing waves, if I understand right, are you asking how and where that barrier occurs when a standing wave becomes a traveling wave? Recently, I was modeling the decline of wave amplitude in the electron when I spotted what could be the answer. If you look at the graph on this page about halfway down - energywavetheory.com/particles-intro/electron/ - you will see a vertical line for the electron's radius. This distance matches the electron's classical radius. Everything to the left (on that image which is closer to the electron's core) is an amplitude that is greater than incoming amplitude (that takes a longer explanation but it should be on the page). Everything after that is less. I think this could be the answer of why it is standing waves that is measured as a particle, and why it is traveling waves that is measured as a force/charge beyond the electron's radius.
The videos are great. Thank you Jeff. The descriptions make sense, and the math logical, but I just realized that in thinking about it, I don't really have clear dimensions about the waves and photons in terms of spacial size. For example, at 4:17 in the video, two photons are going out. Are there spacial dimensions to those, based on amplitude, I suppose? For example, we know for sure the amplitude and energy would be known for the photon, as well as the momentum. But a thought came to me, is there a length and radial width to the the wave (I suppose yes), and is the wave uniform or does it have a wave center, where it is bigger in the middle, as illustrated, and weaker as it goes out from the center. Would the photon wave get longer over time?
Yes, it has spatial dimensions that are defined. One of the papers goes into more detail on the transition of the vibrating particle and the creation of a short-lived transverse wave that has a cylindrical volume with radius (K^2 * wavelength) and the same dimension for cylinder length. The details can be found on Page 28 of the latest version of this paper: vixra.org/abs/1408.0224. The volume seems to be fixed based on the classical radius of the electron regardless of the photon's energy -- a photon with higher energy has a shorter wavelength but in the same volume.
Thanks for developing this amazing theory and compilation Jeff!
Hi Jeff, quick question. When the particle vibrates "up and down" to minimize its amplitude and in turn create the transverse waves- wouldn't this necessitate these wave packets to spread out in 360 as a general field perturbation? What is the reasoning in your mind that there would be 2 "photons emitted along a cylinder? (Or is that just an artifact of your 2d representation?) That is a hard one to rationalize geometrically.
Furthermore, wouldn't the particle vibration create longitudinal waves aimed in the polar axes of its vibration, where it essentially pumps back and forth?
Btw, your work is simply incredible. I am breaking now into your 2nd book. You will hear more from me soon. Thank you for your heroic efforts with this theory!
Hi Clay, the transverse component of the EM wave is perpendicular to vibration. For example, electrons in an antenna generating radio waves. There's a different video that I created for an explanation of EM waves and light at ruclips.net/video/ptpEEDTPnGI/видео.html. Around the 2:38 mark you can see some examples. To answer the other questions, the volume of the cylinder was used in the Particle Energy paper to calculate energies of photons and derive the equation that is used. The details are at: vixra.org/abs/1408.0224. And lastly, you are right that particle vibration should change the longitudinal waves when it "pumps back and forth". The longitudinal waves should be spherical, as the electric force is always felt and declines at the square of distance (spherical). But the transverse wave component of the EM wave should be different and travel perpendicular to vibration. Together, when the photon is measured, these two waves types make up the electric and magnetic components of the EM wave.
Hey Jeff, I been thinking of light, specifically the speed of wave induction and cancellation. When I think of transverse waves in water, the cancellation effect causing still water uses some measurement of time featuring travel distance, resistance, etc. Anyways, the example is like turning off the light. The answer that I heard is that the photon acts as some "packet of energy". And this likely acts similarly as the answer for how standing waves can float. This makes me think logically that some form of barrier occurs, similarly the outside of the drum head, or the fret and the bridge on the guitar. If I considered the physical properties of the outer boundary as some field that weakens the wave it makes me wonder how the photon for example can maintain its fluctuation (for example the mathematical properties of white light) over the distance of the star at the planet without decay, but it seems likely that if the photon acts as some form of traveling standing wave it could maintain its fluctuation (if it even travels).
Moments after posting this, I remembered your presentation for how electricity mechanically lifts, and thought that light is considered electromagnetic.
I'll share thoughts of an experiment. When they test the speed of light (in one of the forms of testing it) they would use one mirror. I would like to see the same test done bouncing the light from 1000 mirrors and comparing the data subtracting the difference and dividing by 1000, giving the accurate light speed (if any) and the "reflective time" used from the absorption and sending of the mirror.
Professor Lene Hau from Harvard University in perspective stopped and started light within matter: ruclips.net/video/-8Nj2uTZc10/видео.html
Just remembered your mathematically talented. What is the absorption and release timing of light within the atom using your kudos equation and does that cause alteration in the measurement of the speed of light?
@@jeffcreighton8669 Regarding your question about the timing of absorption and release, I don't have anything that I've modeled. But I suspect it wouldn't be constant anyway and would be proportional to photon wavelength.
Regarding the question about standing waves, if I understand right, are you asking how and where that barrier occurs when a standing wave becomes a traveling wave? Recently, I was modeling the decline of wave amplitude in the electron when I spotted what could be the answer. If you look at the graph on this page about halfway down - energywavetheory.com/particles-intro/electron/ - you will see a vertical line for the electron's radius. This distance matches the electron's classical radius. Everything to the left (on that image which is closer to the electron's core) is an amplitude that is greater than incoming amplitude (that takes a longer explanation but it should be on the page). Everything after that is less. I think this could be the answer of why it is standing waves that is measured as a particle, and why it is traveling waves that is measured as a force/charge beyond the electron's radius.
The videos are great. Thank you Jeff.
The descriptions make sense, and the math logical, but I just realized that in thinking about it, I don't really have clear dimensions about the waves and photons in terms of spacial size. For example, at 4:17 in the video, two photons are going out. Are there spacial dimensions to those, based on amplitude, I suppose? For example, we know for sure the amplitude and energy would be known for the photon, as well as the momentum. But a thought came to me, is there a length and radial width to the the wave (I suppose yes), and is the wave uniform or does it have a wave center, where it is bigger in the middle, as illustrated, and weaker as it goes out from the center. Would the photon wave get longer over time?
Yes, it has spatial dimensions that are defined. One of the papers goes into more detail on the transition of the vibrating particle and the creation of a short-lived transverse wave that has a cylindrical volume with radius (K^2 * wavelength) and the same dimension for cylinder length. The details can be found on Page 28 of the latest version of this paper: vixra.org/abs/1408.0224. The volume seems to be fixed based on the classical radius of the electron regardless of the photon's energy -- a photon with higher energy has a shorter wavelength but in the same volume.
This was an excellent video. I literally have no questions.
Great! Glad you liked it. :)