The mole and Avogadro's number | Atomic structure and properties | AP Chemistry | Khan Academy

Поделиться
HTML-код
  • Опубликовано: 29 авг 2024
  • Keep going! Check out the next lesson and practice what you’re learning:
    www.khanacadem...
    One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions). The number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant. The concept of the mole can be used to convert between mass and number of particles. View more lessons or practice this subject at www.khanacadem...
    Khan Academy is a nonprofit organization with the mission of providing a free, world-class education for anyone, anywhere. We offer quizzes, questions, instructional videos, and articles on a range of academic subjects, including math, biology, chemistry, physics, history, economics, finance, grammar, preschool learning, and more. We provide teachers with tools and data so they can help their students develop the skills, habits, and mindsets for success in school and beyond. Khan Academy has been translated into dozens of languages, and 15 million people around the globe learn on Khan Academy every month. As a 501(c)(3) nonprofit organization, we would love your help!
    Donate or volunteer today! Donate here: www.khanacadem...
    Volunteer here: www.khanacadem...

Комментарии • 54

  • @shivamgagad5674
    @shivamgagad5674 4 года назад +49

    Kahn Academy is a revolutionary idea that transforms boring lectures from class and creates meaningful content that students are looking for. Clearly Khan Academy is revolutionizing the way we get and percive information.

    • @ahaanhalwai6739
      @ahaanhalwai6739 3 года назад +1

      It’s too bad their JavaScript course is outdated but the maths and chemistry is great

  • @timhacin8393
    @timhacin8393 Год назад +5

    Somebody please give this guy a medal. His videos are one of the best things the internet can offer!!!

  • @andreamunteanu6459
    @andreamunteanu6459 4 года назад +35

    You re the teacher a lot of students dream to have!!

  • @Hussain-re3bg
    @Hussain-re3bg 4 года назад +22

    Thanks, Salman you're a Hero to us!

  • @prasoonjha1816
    @prasoonjha1816 3 года назад +9

    Sir I can't thank you enough, I was super confused in mole concept and Avogadro's Constant. My textbook gave just some equations without any good explanation what is mole, one can be 100% sure while hearing your lecture that his/her doubts will be clearly solved.

  • @niajmorshed8245
    @niajmorshed8245 3 года назад +4

    I'm in 4th year of engineering in Bangladesh and hardly have I found a teacher like Sal.

  • @maxco3412
    @maxco3412 4 года назад +5

    You guys are saints I was struggling with this today in school today and here you are

  • @RISpaceCase
    @RISpaceCase 11 месяцев назад

    This was simple and straight to the point. I also use Khan Academy for my math classes, and it's always easy to follow. The color coding definitely helps keep things organized and memorable. Thank you so much.

  • @reddevil0609
    @reddevil0609 3 года назад +3

    How does the calculation from avg. atomic mass to g give us Avogadro's Number though?

    • @AliceYobby
      @AliceYobby 3 года назад +2

      So, the atomic weight of hydrogen is 1 because it has one proton. A mole of protons, would also equal a mole of hydrogen atoms, which would equal 1 gram. Because there are on average, 6.94 protons and neutrons in any amount of Li, a mole of atoms of Li would equal 6.94 grams. However, there are still a mole of protons and neutrons in 1 gram of Li.

  • @prasheetaaa_20
    @prasheetaaa_20 4 месяца назад

    Understood! Thanks 🙏

  • @KissMyBalls
    @KissMyBalls Год назад +1

    Never gonna give you up
    Never gonna let you down
    Never gonna run around and desert you
    Never gonna make you cry
    Never gonna say goodbye
    Never gonna tell a lie and hurt you

  • @ditoo2002
    @ditoo2002 4 года назад +8

    I'm literally taking this rn in school, we haven't reached the calculation part yet, we're doing more ratio though.

    • @maxco3412
      @maxco3412 4 года назад +1

      I'm doing it in college and we just started as well

    • @ditoo2002
      @ditoo2002 4 года назад +1

      @@maxco3412 interesting, good luck.

  • @kazmix2321
    @kazmix2321 4 года назад +1

    You are the best !!!

  • @Mina-xo6ii
    @Mina-xo6ii 4 года назад +1

    @khan Academy please do lessons about PLS (partial least squares regression)

  • @SajedeTahmasebi-zl8gh
    @SajedeTahmasebi-zl8gh Год назад

    You teach things in a super awesome and understandable way🩵🩵

  • @braidenanderson2669
    @braidenanderson2669 4 года назад +9

    Dang, knowing that 1 gram of gold is less than a mole of gold, meaning 1 gram of gold is equal to a mole of hydrogen

    • @AliceYobby
      @AliceYobby 3 года назад

      There are a mole of protons and neutrons in one gram of ANYTHING :)

  • @SoulReviving786
    @SoulReviving786 4 года назад +12

    Sir why u didnt mention the more easy and accurate formula for finding moles!

  • @smokingterran6
    @smokingterran6 6 месяцев назад

    ok i got the part we need to find mol but i cant get the right answer. im using a TI-83 plus calculator, and i divide 0.0154/72.63=2.12E-4. not the answer of the vid 0.000212 what am i doing wrong on the ti-83 calculator?

  • @0divide136
    @0divide136 4 года назад +3

    why this channel has less views now

  • @carsforkids3512
    @carsforkids3512 4 года назад +3

    I’m still confused 🤷‍♂️

  • @jeetukumarkv
    @jeetukumarkv 3 года назад

    thank u

  • @yousefshello582
    @yousefshello582 4 года назад

    Why sir you put 4 as Unified Atomic Mass Unit instead of 3 for the Li ?

  • @alberteinstein6040
    @alberteinstein6040 4 года назад +3

    I always hated schools but this, this isn’t school

    • @konzeptwerks6710
      @konzeptwerks6710 4 года назад +1

      You did?
      Are you actually speaking for Albert Einstein !??!

  • @roll28moainhabib72
    @roll28moainhabib72 4 года назад

    Amazing

  • @lucaspeck7995
    @lucaspeck7995 4 года назад +2

    The Avogadro has a number!!!

  • @andrewparesa5116
    @andrewparesa5116 4 года назад

    Yes

  • @harshitajangir8521
    @harshitajangir8521 2 года назад

    How many moles of electrons do we have in a kilogram of electrons?

  • @pancake3321
    @pancake3321 4 года назад +10

    anyone hear the phone notification at 5:02?

  • @simpleyasser2251
    @simpleyasser2251 4 месяца назад

    I've never felt so confused

  • @jasonvegan5761
    @jasonvegan5761 4 года назад +3

    Wow that’s a lot of aloms 😏

  • @hongyaness2580
    @hongyaness2580 3 года назад +1

    how 6.02214076 x 10^22 became 6.022 x 10^23 ?

    • @hongyaness2580
      @hongyaness2580 2 года назад +1

      @@MV-sg9zh rounding doesn't change the power from 22 to 23

  • @SandeepKumar-yy8ey
    @SandeepKumar-yy8ey 4 года назад

    Mole concept definition

  • @JavaAidTutorials
    @JavaAidTutorials 4 года назад

    I love chemistry..

  • @godxon_5648
    @godxon_5648 2 года назад

    "Which is a lot"

  • @cosmosapien6221
    @cosmosapien6221 3 года назад +2

    How many atoms in a guaca-mole?
    Avocado's number!

  • @shalinikurup7051
    @shalinikurup7051 4 года назад

    S

  • @ummehabeebah7153
    @ummehabeebah7153 4 года назад

    Pls try to do in urdu.that would be helpful for many students

  • @OnurKeskinonurkeskin
    @OnurKeskinonurkeskin 4 года назад

    🇹🇷

  • @Indyin
    @Indyin 4 года назад

    GG

  • @sudhirkushwaha7110
    @sudhirkushwaha7110 4 года назад +1

    Sir please hindi me bhi video please

  • @truthcrusade8371
    @truthcrusade8371 4 года назад +2

    Basically memorization and using tables, you don't explain sh*t in terms of how each term came to be and how each element ended up with all those numbers you are using. Teaching based on memorization is like catching a movie towards the end, it's like, what the hell happened here?!

    • @AliceYobby
      @AliceYobby 3 года назад +1

      If you watch the whole series in order you would have a better understanding.