Why is experimental CRSS less than theoretical CRSS?

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  • Опубликовано: 2 окт 2024
  • Why is experimental CRSS less than theoretical CRSS?

Комментарии • 20

  • @prakharbhalla9461
    @prakharbhalla9461 3 года назад +2

    Sir why it requires less energy to break bonds on at a time than all at one go?

  • @rameshram-gc4sm
    @rameshram-gc4sm 6 лет назад +2

    Nice explanation

  • @Ritikkumar-mq3fm
    @Ritikkumar-mq3fm 4 года назад

    if our theoretically calculated value of CRSS is not experimentally valid then what will be CRSS value for dislocation movement?

  • @ok-kp5jn
    @ok-kp5jn 5 лет назад +2

    Can someone write an explanation for this?

    • @deepkalariya6906
      @deepkalariya6906 3 года назад +1

      In this video slip mechanism are dislocation of half plans. As per the video you can show how slips actually occur that's consuming very lower energy. I hope you can able to get ideas 😃

  • @harikrishnan3112
    @harikrishnan3112 4 года назад

    Hi sir. If we take a defect or dislocation free crystal will it satisfy theoretical value of schmid during experiment?

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  4 года назад +3

      Yes, it is expected to do so. There have been a few experiments of this kind. The difficulty of these experiments is that it is difficult to prepare samples without any dislocations. One such experiment was performed by S.S. Brenner of General Electric Company in 1956. He published his results in the Journal of Applied Physics.
      By the way, Schmid only stated that a critical resolved shear stress is required for plastic deformation. He did not estimate these values. This was done by Frenkel.

  • @adarsh7307
    @adarsh7307 4 года назад +1

    nice

  • @mr.perfect3986
    @mr.perfect3986 4 года назад

    Sir in this diagram where is slip plane Imagine the paper is pasted in wall front of you.
    1. Is it the horizontal plane parallel to floor
    2. Or vertical plane perpendicular to paper(plane 1,2,3.... In the drawing)
    3. Or perpendicular to both these planes.
    Thank you
    3

  • @Ritikkumar-mq3fm
    @Ritikkumar-mq3fm 4 года назад

    is the formula derived in earlier lecture for CRSS valid only for single crystal system?

  • @siddharthjena2189
    @siddharthjena2189 4 года назад

    But sir,everytime we apply stress for slip, there will be dislocation. Then how can we achieve the theoretical crss value??

    • @Ritikkumar-mq3fm
      @Ritikkumar-mq3fm 4 года назад

      this was calculated for single crystal i.e. pure.

  • @DTime1970
    @DTime1970 Месяц назад

    Amazing!!

  • @abhishekagrawal8549
    @abhishekagrawal8549 4 года назад

    Sir,then what is the mechanism of elastic deformation?Is it the same as plastic deformation?

  • @mruddhav763
    @mruddhav763 4 года назад

    Nice

  • @MartinezRBA
    @MartinezRBA 4 года назад

    Nice