Griffiths QM Problem 2.31 Solution: Determining the Scattering States for the finite square well

Поделиться
HTML-код
  • Опубликовано: 12 янв 2025

Комментарии • 11

  • @shubhamapte6172
    @shubhamapte6172 9 месяцев назад +1

    The amount of efforts that you put in this video deserves a salute man. Thank you so much for this explanation. Made everything clear🙌

  • @iWrInstincts
    @iWrInstincts 3 года назад +3

    I have an exam on this in less than a week. Im so grateful I found this channel! Thank you! Griffiths certainly doesn't go into the very very small details like you did, helped a lot!

  • @lightonsakala3245
    @lightonsakala3245 3 года назад +2

    Very good job, This is a very nice proof

  • @preeti0908
    @preeti0908 2 года назад

    Best channel for physics ❤
    Love you sir 💗💗💗

  • @Sirajul-in
    @Sirajul-in 6 месяцев назад

    THANK YOU SIR.

  • @haoqinggenius4335
    @haoqinggenius4335 Год назад

    oh my goodness gracious

  • @ayindelekan557
    @ayindelekan557 7 месяцев назад

    Can you please solve this using matlab?

  • @nidarahat1681
    @nidarahat1681 Год назад

    Why you put cos lx and sin lx in this region 2
    Is there is any concept for this ?

    • @NickHeumannUniversity
      @NickHeumannUniversity  Год назад

      What exactly confuses you about that? If you wonder how to choose between expressing the solution as sine/cosine or exponential, let me suggest you watch my explanatory video on that:
      ruclips.net/video/T7h22wB1RJc/видео.html
      If not, please explain what you have doubts about and i'll happily answer!