De Broglie Wavelength Problems In Chemistry

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  • Опубликовано: 7 авг 2024
  • This chemistry video tutorial explains how to calculate the de broglie wavelength of large objects and small particles such as electrons. It contains plenty of examples and practice problems.
    Speed of Light, Frequency, Wavelength: • Speed of Light, Freque...
    Photon Energy:
    • How To Calculate The E...
    The Photoelectric Effect:
    • Photoelectric Effect, ...
    De Broglie Wavelength:
    • De Broglie Wavelength ...
    The Bohr Model of Hydrogen:
    • Bohr Model of the Hydr...
    Heisenberg's Uncertainty Principle:
    • Heisenberg's Uncertain...
    ________________________________
    Intro to Quantum Numbers:
    • Quantum Numbers
    Orbitals & Atomic Energy Levels:
    • Orbitals, Atomic Energ...
    Maximum Number of Electrons:
    • How To Determine The M...
    Intro to Electron Configuration:
    • Electron Configuration...
    Electron Configuration Exceptions:
    • Electron Configuration...
    Noble Gas Notation:
    • Electron Configuration...
    Electron Configuration of Ions:
    • Electron Configuration...
    _______________________________
    Orbital Diagrams:
    • Orbital Diagrams and E...
    Paired & Unpaired Electrons:
    • How To Determine The N...
    Aufbau's Principle & Hund's Rule:
    • Aufbau's Principle, Hu...
    Paramagnetic & Diamagnetic Elements:
    • Paramagnetic & Diamagn...
    Valence Electrons & Periodic Table:
    • Valence Electrons and ...
    Effective Nuclear Charge:
    • How To Calculate The E...
    _________________________________
    Slater's Rule:
    • How To Use Slater's Ru...
    How To Identify The Element:
    • Electron Configuration...
    Quantum Numbers - Mega Review:
    • Quantum Numbers - n, l...
    Quantum Numbers - Practice Test:
    • Orbitals, Quantum Numb...
    Final Exams and Video Playlists:
    www.video-tutor.net/
    Full-Length Videos and Worksheets:
    / collections

Комментарии • 93

  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  6 месяцев назад +3

    Final Exams and Video Playlists: www.video-tutor.net/

  • @randommeep
    @randommeep 2 года назад +81

    for anyone wondering how to get it in meters: 6.626E-34 J*s is equivalent to 6.626E-34 kgm^2/s, which should cancel out units and leave you with meters

  • @georgesadler7830
    @georgesadler7830 2 месяца назад +2

    Professor Organic Chemistry Tutor, thank you for showing How to use Broglie Equation in AP/General Chemistry. The problems and examples are simple to follow and understand using the classical De Broglie Equation. De Broglie Equation is another great contribution to Modern Chemistry. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.

  • @yasseridris1547
    @yasseridris1547 4 года назад +131

    may I give some advice. Great video first off but I suggest that you write the units for all the values too make it easier to explain.

  • @kaileeguthrie5086
    @kaileeguthrie5086 2 года назад +16

    I would like to see the units because I do not understand how they cancel out.

  • @travisfarmer1548
    @travisfarmer1548 2 года назад +3

    Me here watching the night before my first chem 105 test, The Organic Chem Tutor always comes in clutch

  • @technicalgaur
    @technicalgaur 5 лет назад +3

    You're Awesome....Luv from India

  • @razasyed575
    @razasyed575 2 года назад +4

    we love you the organic chemistry tutor

  • @bamlaktadesse4880
    @bamlaktadesse4880 4 года назад +5

    ur videos are perfect; i am gonna have more than good grades cuz of u

  • @arabellajennings6058
    @arabellajennings6058 4 года назад +6

    I love you man, your channel has helped me so much ahhhh

  • @kirstenholder7270
    @kirstenholder7270 4 года назад +4

    Thank you, this was so helpful!!

  • @ascaniosobrero
    @ascaniosobrero 3 года назад +2

    I have a question for you. In =h/mv if v=0 the relation in meaningless. But I could have a speed low enough to have the object have a visible light wavelenght. For instance, if I weight 70 kg and I move at 1.4 x 10(-29) m/s my wavelenght would be (circa) 663 nm. Does it make sense?

  • @pablosarriaquezada9357
    @pablosarriaquezada9357 5 лет назад

    Awesome video

  • @congyu3396
    @congyu3396 4 года назад +1

    thank you dude

  • @edgarfranco367
    @edgarfranco367 3 года назад +19

    I'd love to see the units and they cancel each other and convert to end up with our final units. The main reason I came to watch the video was to see the units worked out because I don't know what to do with the kg.

    • @angegogo6198
      @angegogo6198 2 года назад

      Same

    • @jerome2354
      @jerome2354 2 года назад

      Same, I don't know how to get rid of the unit kg.

    • @Samylila
      @Samylila 2 года назад +1

      @@jerome2354 remember that Plancks constant is Js. Joules=kg*m^2/s^2. so kg in numerator and denominator cancel out!

    • @jerome2354
      @jerome2354 2 года назад

      @@Samylila Thanks, already got it

    • @Samylila
      @Samylila 2 года назад +4

      @@jerome2354 i figured haha but maybe someone else will benefit from this in the future

  • @henrychileshe9479
    @henrychileshe9479 6 лет назад

    c'est superbe..je l'aime..!!!

  • @marvievaliente5329
    @marvievaliente5329 Год назад

    Thank u💚

  • @freemanfreeman7145
    @freemanfreeman7145 6 лет назад +1

    Is the de broglie's wavelength a property of spacetime and related to the permittivity or "bendyness" of free space and can explain why the universe can bend/stretch/compress spacetime as with gravity?

    • @freemanfreeman7145
      @freemanfreeman7145 6 лет назад

      The less momentum it has, so it has less inertia keeping it from being moved around by a of spacetime as it's particle/wave propogates through space?

  • @Trynnagetmydegree__
    @Trynnagetmydegree__ 9 месяцев назад

    Thanks man

  • @royndrosario4690
    @royndrosario4690 3 года назад +10

    you need to use the fact that
    1J= 1kg m^2/s^-2
    to write Planck's constant as
    h = 6.626x10^-34 kg m^2/s^2 * s
    cancel both "s" it will be
    h = 6.626x10^-34 kg m^2/s

    • @Megs-uu7du
      @Megs-uu7du 2 года назад

      what

    • @sooji2406
      @sooji2406 2 года назад

      i love you and ill remember you forever

  • @killaclips9396
    @killaclips9396 6 лет назад +1

    excellent video!

  • @haripriyaharidas3186
    @haripriyaharidas3186 6 лет назад

    Tqu so much

  • @KY-xz9yb
    @KY-xz9yb 3 года назад +6

    I'm learning this in modern physics, I wonder if there is any difference between how its taught in chemistry and physics.

    • @raichu56k
      @raichu56k 2 года назад +1

      i'm learning it in physics as well, along with wave-particle duality

  • @alaaabubaker8442
    @alaaabubaker8442 4 года назад +1

    How do u cancel up units ?

  • @benjaminhambula9427
    @benjaminhambula9427 6 месяцев назад

    On behalf of everyone. My Jehovah bless you and everything and everyone around you. Am on another continent by yet u are lots of help.
    Sending Thenks for Zambia 🇿🇲

  • @Perzior
    @Perzior 2 года назад +1

    Quick question, why dont you use f (small letter) for the frequency, would make things less complicated i think with the wohle v and v thing right? Or not?

    • @nmarbletoe8210
      @nmarbletoe8210 2 года назад +1

      f is often used to mean "function" like f(x) = x + 2

  • @tharun9083
    @tharun9083 4 года назад

    At 5:30,planck's constant joules is kg m²/s² ,then that wavelength is in meters which will only cancel out the m² in planck's constant,how did the s² got converted to s...making it m/s

  • @manchesterfan1012
    @manchesterfan1012 4 года назад +69

    General Rule of Thumb:
    C = wavelength x frequency (v)
    Energy = h (planks constant) x frequency = h x c / wavelength
    Da Broglie’s:
    Wavelength = h/p = h/mass x velocity

    • @pintukhan1056
      @pintukhan1056 3 года назад

      CzzczczczczczzcczczCzzcczczzcczCzZcZcczczczczczczczczczczzc

    • @boha3066
      @boha3066 3 года назад +2

      Yes!

  • @yaowang9883
    @yaowang9883 2 года назад +2

    Shouldn't the last part be double-slit interference to alternate light and dark?

  • @Roust7
    @Roust7 3 года назад +2

    What if the ball is moving very very slow then the wavelength of the ball will increase. So if a ball moves really slow can it go through the wall if its wavelength becomes longer than thickness of the wall??

    • @nmarbletoe8210
      @nmarbletoe8210 2 года назад

      yes!
      try the calculations for a baseball it's amazing. talk about a "change up"

  • @barrymuindi3655
    @barrymuindi3655 5 лет назад +23

    bro you never did a video on schrodingers wave equation and i was depending on you

    • @raheemcarridice6008
      @raheemcarridice6008 3 года назад +2

      Dwl thought I was the only one I was looking so hard I ended up at professor dave instead

  • @lizang3533
    @lizang3533 5 лет назад +6

    For the first problem, why is it m and not m^2?

  • @sajjamokshith1848
    @sajjamokshith1848 5 лет назад

    Tqu

  • @prestonh7574
    @prestonh7574 4 года назад +1

    What's about in physics

  • @glizzyxav
    @glizzyxav 2 года назад

    why use v for frequency?

  • @bece3oo47hirparazeel8
    @bece3oo47hirparazeel8 4 года назад +1

    What is difference between de broglie wavelength and thresholds wavelength

  • @sonnajensen4824
    @sonnajensen4824 5 лет назад +1

    What happens to the kg? Why does the final answer only have units of meters? I know it wouldn't make sense to have kg in a wavelength measurement but I thought units only canceled if they were were present in both the numerator and denominator.

    • @uhuihiuihiuh3042
      @uhuihiuihiuh3042 5 лет назад +3

      You're right, it's always good practice to show the units in your calculations so you can analyze if your answer makes sense.
      Recall that the SI units of a joule are kg*m^2/s^2
      Therefore the units of Planck's constant are [J*s] = [kg*m^2*s/s^2]
      The kg in Planck's constant divides out with the kg from the mass and you will end up with an answer in meters.

    • @mayank2id
      @mayank2id 5 лет назад

      Solve it with dimensional factor method, you will get only [L], whose Si unit is metre.
      Hope u like.......;)

  • @amirrezahabibi2479
    @amirrezahabibi2479 3 года назад

    If we wanted to find the wavelength of an atom moving at whatever-velocity, how do we find the mass of the Li-7, in kg, to use in the formula?

    • @harshbirbrar2830
      @harshbirbrar2830 3 года назад

      Are you taking Chemistry at UBC by any odd chance?

    • @amirrezahabibi2479
      @amirrezahabibi2479 3 года назад

      @@harshbirbrar2830 haha yep

    • @Qwertyfg1234
      @Qwertyfg1234 3 года назад

      You look at the back of ur chirp to find the value of which u multiply The Amu

    • @harshbirbrar2830
      @harshbirbrar2830 3 года назад

      @@Qwertyfg1234 godsend

  • @fidelshog-oy4845
    @fidelshog-oy4845 2 года назад +1

    What if an electron moving at 1/10 the speed of light ?

  • @Doktah_Zari
    @Doktah_Zari 9 месяцев назад +2

    Remember PEMDAS people, parentheses goes first, then divide. 👍

  • @ale2wavey
    @ale2wavey 4 года назад +7

    is anyone else getting completely different answers when plugged in??

    • @godofnothing428
      @godofnothing428 4 года назад

      In case you didn’t figure it out, you’re just not plugging it properly, try using brackets and/or following pedmas

  • @soumyajitsarkar2372
    @soumyajitsarkar2372 6 лет назад

    can we use E=hf for an electron moving with velocity v ? If yes ,why ? If no,why too ?
    Thanks for the help :))

  • @noor-dl8wf
    @noor-dl8wf 10 месяцев назад

    i love you

  • @HayNayyy
    @HayNayyy 6 лет назад

    I am just not getting this! When I plug in number 2 I get 4.85 E-23... how do you get the 48.5? Do you just move the decimal over?

    • @lapinnain7703
      @lapinnain7703 5 лет назад

      In my calculator I did (4.85E-11) divided by (1E-12) and I got 48.5

  • @jordangravon998
    @jordangravon998 6 лет назад

    Number 3 is wrong, or you missed a bunch of steps to getting that answer. I ended up with 1.81x10^-10 m*s

    • @masonhunt5771
      @masonhunt5771 6 лет назад +3

      use parenthesis when entering long equations into your calculator and you should end up with what he says the answer is.

    • @robingriffin42
      @robingriffin42 4 года назад

      @@masonhunt5771 Number 3 is wrong

  • @raymondbaker987
    @raymondbaker987 Год назад +1

    Second problem is wrong

  • @priyankaexamprep.2314
    @priyankaexamprep.2314 3 года назад

    h=6.625×10 power _34 not h = 6.626×10......

  • @exile600
    @exile600 6 лет назад +7

    What is this guys accent?

    • @kotosqoposrly
      @kotosqoposrly 6 лет назад +18

      Nerdian.

    • @Mojapane
      @Mojapane 5 лет назад +1

      😆

    • @Trev0r98
      @Trev0r98 5 лет назад +5

      I'm not narrowing it down very well, but his accent is somewhere in the Camden New Jersey - Philadelphia region.

  • @Momentum_animation
    @Momentum_animation Год назад

    🙃🙃🙃🙃🙂

  • @4pharaoh
    @4pharaoh 5 лет назад

    Waaaat? " I'm just going to replace the speed of light with the general velocity v" ... You can't do that! E doesn't equal mv^2 and E doesn't equal hc ... I'm still looking for someone to make matter waves make sense. Any suggestions?

  • @JR1481M1
    @JR1481M1 5 лет назад +1

    uhhh what are u plugging in? You lost me there.

    • @tephy21
      @tephy21 4 года назад

      He means plugging the values into your calculator

  • @Mathin3D
    @Mathin3D 4 года назад +1

    FAIL!

  • @malanalan1
    @malanalan1 Год назад

    Your choice of distance units sucks big time.

  • @vishnivinara4423
    @vishnivinara4423 2 года назад

    in Sri Lanka, we don't get to use calculators for these questions....we use our brains~
    ugh.