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9^(n+1)-9^(n-1)=209(9ⁿ)-[(9ⁿ)/9]=2081(9ⁿ)-9ⁿ=18080(9ⁿ)=1809ⁿ=2.253²ⁿ=1.5²2n=log_3(1.5²)2n=2[log_3(1.5)]n=log_3(1.5) ❤
Very nice! ❤
9^(x-1)×(81-1)=209^(x-1)=1/49^x=9/4x=log(9/4)/log9=(log9-log4)/log9=1-log4/log9=1-log2/log3
Nice math.It improve skill.
Greetings, excellent videos, but I have a question: What application do you use for classes?
9^(x + 1) - 9^(x - 1) = 209^x*9^1 - 9^x*9^(-1) = 209^x*9^1 - 9^x/9 = 209^x*9*9 - 9^x/9*9 = 20*99^x*81- 9^x = 1809^x(81 - 1) = 1809^x*80 = 1809^x = 180/809^x = 9/4x = log9(9/4)x = log9([3/2]^2)x = 2*log9(3/2)
x = 1 - ln2/ln3
By observation, x is greater than 0 and less than 1.
@@SALogics Upon further observation, between 0 and 1/2. At one half, it becomes 27 - (1/3), which is greater than 20.
9^(n+1)-9^(n-1)=20
9(9ⁿ)-[(9ⁿ)/9]=20
81(9ⁿ)-9ⁿ=180
80(9ⁿ)=180
9ⁿ=2.25
3²ⁿ=1.5²
2n=log_3(1.5²)
2n=2[log_3(1.5)]
n=log_3(1.5) ❤
Very nice! ❤
9^(x-1)×(81-1)=20
9^(x-1)=1/4
9^x=9/4
x=log(9/4)/log9
=(log9-log4)/log9
=1-log4/log9
=1-log2/log3
Very nice! ❤
Nice math.
It improve skill.
Very nice! ❤
Greetings, excellent videos, but I have a question: What application do you use for classes?
9^(x + 1) - 9^(x - 1) = 20
9^x*9^1 - 9^x*9^(-1) = 20
9^x*9^1 - 9^x/9 = 20
9^x*9*9 - 9^x/9*9 = 20*9
9^x*81- 9^x = 180
9^x(81 - 1) = 180
9^x*80 = 180
9^x = 180/80
9^x = 9/4
x = log9(9/4)
x = log9([3/2]^2)
x = 2*log9(3/2)
Very nice! ❤
x = 1 - ln2/ln3
Very nice! ❤
By observation, x is greater than 0 and less than 1.
Very nice! ❤
@@SALogics Upon further observation, between 0 and 1/2. At one half, it becomes 27 - (1/3), which is greater than 20.